how to connect LED light to 100 / 220v AC

[@СергейТрофимов-б5р3к]

Для тех кто захочет повторит. Если в розетке 220 В, а резистор на 15 КОм, то ток будет 15 мА, что хорошо для светодиода. Но при этом токе на резисторе будет выделяться 3,3 Вт. Уже через минуту резистор сильно нагреется и сгорит или расплавит все вокруг. Следовательно резистор должен быть большим по мощности и опять же рискуем расплавить корпус, т.е. следует озадачиться теплоотводом. Если не менять схему, то правильнее взять резистор на 100 КОм. Правда ток упадет, до 2 мА. При этом свою функцию ночника это устройство выполнять будет! Греться тоже будет, но не сильно. Я лично против таких роликов. Такие видео делают люди которые плохо учились в школе!!!

[@АртЯрт]

День добрый!!! Вы откуда знаете такие подробности по части того, какие именно резисторы и др. нужны ?

[@СергейТрофимов-б5р3к]

@@АртЯрт Ну так школьная программа. Закон Ома, расчет мощности. Последовательное включение резистор+светодиод+диод. Падением напряжения на светодиоде и диоде можно пренебречь.

[@oberst_krass]

​@@СергейТрофимов-б5р3к Dann müssten Sie aber auch wissen, dass Sie die Rechnung mit 110V durchführen müssen. Damit ergibt das an dem Widerstand lediglich eine Leistung von etwa 0,8 Watt.

[@trubamaniac]

А если вместо резистора - конденсатор 0.2 мкФ /400-600В? Что будет эквивалентно тому же резистору 15кОм(для переменного тока) только греться он не будет.

[@GD-777]

​@@СергейТрофимов-б5р3к вам бы самому неплохо школьный курс второй раз пройти... Диод гасит одну полуволну напряжения

[@oddball119]

That resistor is about to emit more light than the led if you keep it plugged in for too long.

[@shashwatsingh3551]

🤣

[@marcelfurst9398]

-he must use a bigger resistor to handle the loss wattage -insulation Problems -if Resitor fails CAP goes smokey boom

[@prashanth105]

Not only that I think he should have used a .22uf/250v in series to prevent that resistor from becoming too hot...

[@Core533]

Fr

[@waynemasters8673]

we're all gonna get nuked from this radiation!

[@tubanbodyslammer9125]

Beginner electronics enthusiasts, do not mess with mains

[@AlphaPiggy]

Amen 😂😂

[@stumpchump7014]

I will take that advice. Thank you.

[@Flawake]

It will work... for a short time. If you will make it, your resistor should be able to handle more power than the resistor shown in this video.

[@lucarciof]

Moreover, a lot of electric power lost in heat...

[@flamingo5900]

Our line voltage is 220v. When the neon lamp in my electric iron stopped working I replaced it with 2 LEDs. No diode, no capacitor. Just a resistor and 2 LEDs back to back. The resistor was in megaohms I think.

[@flamingo5900]

I calculated the resistor wattage of the given circuit. It is only 0.4W. If you want to reduce the wattage increase the resistance.

[@Flawake]

@flamingo5900 It would indeed work when you use a resistor in the mega ohms. But this person only used 15k. I think the led is 12V best case. This makes the voltage over the resistor 220 - 12 = 108V. Ohms law tells us that 108/15000 = 0.0072A trough the resstor. 0.0072 * 208 = 1.5W. only half of the time on and a lot of that time not 220V but less so lets divide by 3, gives us 0.5W. The resistor seems to be only 0.25W. This was my calculation. What was yours?

[@SubratkumarJena.]

As it is a half wave rectifier we get 93 v DC from 230v ac supply as a half wave rectifier has efficiency is equal to 40.6℅. So we have to use 15k/1w resistor.

[@rudie2902]

You put about 8 Watt in a 0.5 Watt Resistor? Will get very hot and burn out fast.

[@rashidmdamin5552]

his ac outlet must have been 110v, that will draw ~ .8watts/2 , the circuit only operating at a 1/2 cycle.

[@broderickclayburn]

I thought those types of plugs carry 220-240 volts

[@DIBROV]

@rudie2902, how did you get 8 watts. P=U²/R. If U=220 V (ex - USSR countries), P=3,23 Watts, but taking into account one half-wave out of two, half as much - 1.6 watts. Else if U=110 Volts (USA), U²/R= 0.8, and half=0.4 Watts. Or not?

[@GamrokFeddy]

Then we need POWER RESISTORS

[@victorfourman1683]

@@DIBROV Вроде нет. У меня получается мощность в 2 раза меньше на резисторе 15кОм. Почему вы берете полное напряжение в квадрате, если реально на резисторе половина?

[@DI43EL]

If you add only 100kohm resistor in series it will work too. I have something like that done 30 years ago and it's still working

[@prashanth105]

Done the same, but I had used a.22/250v cap in series. But the resistor heats up although not too much...

[@soundspark]

With modern LEDs you need a reverse blocking diode.

[@milenbuinov384]

Capacitor.... 3sec. later BOOM 💥🤣

[@milenbuinov384]

@@denpar5450 мне тоже нравитьса

[@muppetpaster]

I doubt it is 3 seconds.😂 I bet it is instantly....

[@flamingo5900]

Wrong. The voltage on the capacitor will not be more than the forward baising voltage of the LED.

[@milenbuinov384]

@@flamingo5900 uh..yeah sorry I’m wrong see the scheme

[@Dogday2-t7v]

​@@flamingo5900yes dude

[@xuniwor]

Capacitive dropper should be the answer, that's like 80% efficient or so. This circuit is more like 5% efficient, if you're lucky

[@joseguzmana7485]

Funciona... Pero les aconsejo que la resistencia sea de 120k a 220k .... para que no tengan problemas....

[@bernardovaldez5066]

Para 110v de cuanto debe ser la resistencia para queno se caliente?

[@losparanoicos8339]

Pasen nombres de los materiales... Me interesa

[@ramirasosa]

Capacitar de poliester

[@herculeskart7093]

Creo que funciona pero se recalienta y las soldaduras se sueltan tiene poco tiempo de duración 😅👎😕💥

[@brendavazquez8335]

Alguien podría explicarme cuál es la función de cada uno de los componentes que se usaron.

[@GRAHAMAUS]

Instead of the 15K resistor, use a 220nF 400V non-polar capacitor. It will drop the same voltage but dissipate no power so won't get hot. You also don't need the 1n4007, the LED will block the negative half waves of only a few volts without any problem.

[@mikemordkovich7653]

Or you may solder two LEDs in parallel, but in opposite direction. And get twice the lumen power... :)

[@ishanyadav5186]

That one unemployed friend at 3 am 😂😂

[@GarryAlexeef]

Параллельно светодиоду неплохо бы ещё включить диод в обратной полярности. Ибо у светодиода небольшое допустимое обратное напряжение.

[@Technotronic27]

Там диод последовательно, как думаю с расчетом на сетевое и кондер на выходе в качестве фильтра этого импровизированного так сказать источника - напряжение самое что ни есть постоянное!!! :)

[@SubratkumarJena.]

Ye half wave rectifier hota hai jiska efficiency 0.406 hi hai. To 230v ac ko wo 93.4 v dc me convert karta hai fir ek diode me 0.7 v drop hi hota hai to output hammo 93.4-0.7=92.7 ya 93v hi milta hai. Ek led ka resistance (3/15) k-ohm=200-ohm hi hota hai to dc current=(93/15.2)mA =6 mA hi hota hai. To power loss across the resistor=(36×10^-6×15000) w=0.54 watt hi hota hai. To ye resistor ki value 15k-ohm/1w hi hona chahiye. Ye yaad rakho ye half wave rectifier hi hai.

[@dancoulson6579]

Sorry. But the design of this is pretty aweful. Firstly you're dissipating more power than the small 1/4w resistor can handle. Then the capacitor is only rated for 35v, meaning that if the LED fails and goes open circuit, it will burst. A more efficient approach would be to use a capacitive dropper followed by a bridge rectifier.

[@victorfourman1683]

The most professional answer here 👏

[@臼-v7q]

​@@victorfourman1683 general knowledge

[@imafluffycat____3504]

FULL BRIDGE RECTIFIER

[@amaan_shaikh]

The resistor problem still remains, LED needs probably 4v max, too much dissipation, isn't it?

[@handle5557]

@@amaan_shaikh in a series of led lights the most important current. no matter how many tens or even hundreds of voltages, the most important gang is the current. so here and there the resistor is set. if in the video use 15k ohms. This means that the power generated from the circuit is limited to only 15mA, which is very safe for an LED

[@StepaSnail]

Resistor at this time: 🎵 Something fire🎵

[@oberst_krass]

Why?

[@parthchati1194]

You have good sense of humor and knowledge too

[@StepaSnail]

Power on resistor is about 48 watt. It if in socket you have 120 volts. Resistor is on 0.125 watts. It Just burns.

[@oberst_krass]

​@@StepaSnail please explain it!

[@StepaSnail]

@@oberst_krass If the socket is 220 V, and the resistor is 15 kOhm, then the current will be 15 mA, which is good for the LED. But at this current, 3.3 watts will be released on the resistor. Within a minute, the resistor will get very hot and burn or melt everything around. Therefore, the resistor must be large in power and, again, we risk melting the case, i.e. should be concerned with heat dissipation. If you do not change the circuit, then it is more correct to take a 100 KΩ resistor. True, the current will drop to 2 mA. These videos are made by people who didn't study well in school!!!

[@АндрейЛютоев-ю9ю]

Самый хороший вариант ночника это поставит светодиод на зарядку телефона и мудрить ни чего не надо.

[@richmadrid9563]

Just use a 2volt LED, with a 510k ohm resistor for a 220v AC line. It should work fine.

[@francoceron7338]

Soy aficionado de la electrónica disculpa el valor del voltaje es cuánto ?

[@zeus-truth]

​@@francoceron7338220V Alternating Current

[@huseyinteke1194]

Kaç vat ışık veryor

[@raffaelemarino8914]

Bravissimo, ottima idea! ❤❤

[@ध्रुव_वर्मा]

When you don't know the basics of electronics:

[@diverseproduktrezensionen9222]

Bitte auf keinen Fall bei 220V bzw. 230V nachmachen! Der 0,5W Widerstand brennt in unter 1 Minute ab und schmilzt dabei mindestens den Stecker weg, wenn es nicht sogar zum Brand kommt. Also bitte auf keinen Fall nachmachen.

[@oberst_krass]

Selbst wenn der Widerstand abbrennt, würde der Stecker nicht schmelzen. Abgesehen davon ist das eine ganz korrekte Schaltung.

[@md8060]

En garantisi kondansatör arasına 1.5 voltluk bir zener bağlayip direnci iptal edip onun yerine alternatif akımda çalışan düşük kapasiteli bir kondansatör baglamak

[@pippolupin8715]

Capacitor 68uF 300V and resistor 15Kohm 2W or 5W.

[@plantekgaming2414]

This resistor will burn instantly use capacitor to limit the current through the led and you don't also need this diode because an led is already a diode

[@СергейТрофимов-б5р3к]

I did it without a diode. The LED is designed for 200V reverse voltage. LED usually punches quickly.

[@125brat]

Reverse voltage withstand is only a few volts for LEDs - check the data-sheets. The 1N4007 or similar is essential if you want the LED to last more than a few seconds.

[@mabmarsh7370]

@@125brat every single extension box out there uses LED connected to resistor, without any other diode in series, and they do last for years, not a few seconds as you claim

[@125brat]

@@mabmarsh7370 I think you'll find they are neon lamps which are very different devices. They are not polarity sensitive and require about 100V to strike the arc but the resistor limits the current to a couple of mA running current or so. Check the data-sheet of any normal LED and you will see the PIV is only a few volts, so another diode is essential if you want the LED to survive more than a short time.

[@mabmarsh7370]

@@125brat I would have agreed with you if not that the replacement LED I added to my extension box still works till today I bought a 3mm led from a local store (because my 5mm led was too wide for the space allocated) and connected it in series with a 100k ohms resistor, and since January it's still working, my extension box is almost always plugged into power. btw, the supplied rms voltage here in Nigeria is 220v

[@ReclaimerStudios]

Correct me if I’m wrong but I’m pretty sure the capacitor direction doesn’t matter because it’s ac not dc.

[@sergionicolis664]

Essa é uma conta que não fecha. 220vac - 3v ÷ 0.20 mA = 10.850 Ohms na resistência. Assim, certamente se queima o led. Mas, colocando um diodo em série cortando em meia-onda o valor da tensão, ela cai pela metade. Ok, mas ainda assim o valor do resistor é baixo. Vou simplificar e dizer que na pratica ainda coloco outro diodo em contra-fase no led para protegê-lo da tensão reversa e subo o resistor para 47 K x 1 watt, vai esquentar pouco e aumentar o tempo de vida util do led. Capacitor é opcional.

[@bernardovaldez5066]

A ver el diagrama por favor como lo harias para que funcione como dices. Gracias.

[@sergionicolis664]

@@bernardovaldez5066 Claro, dame un contacto para poder enviarte el diagrama.

[@SoumikDhar569]

Ye half wave rectifier ki tara h .. Ek diod current ke direction ko ektaraf kor deta h ... Matlab ac to unpure dc me convert korta h ... Or ye capacitor parralel me h jo us unpure dc ko approximately pure dc me convert korta h

[@ЕвгенийКраснов-т8т]

Берёшь неоновую лампочку от электрического чайника и не заморачиваешься с радиодеталями! ✌️😎

[@beetle1305]

Только не забудьте, что не все неонки работают без резистора

[@Владимир-у1ц5б]

@@beetle1305 работают все только очень недолго

[@ruayfe7342]

Very nice houseburner!

[@РоманДігтяренко]

Два св.диода в противоположные направления и резистор ~ 35к (4 параллельно по 150к, например).. 😊

[@brunoadiel2035]

Não façam isso em casa! O risco de choque elétrico é enorme, além de que o led e os outros componentes eletrônicos iriam queimar instantaneamente.

[@richbooth8948]

isn't anyone going to comment on the capacitor only being rated for 35v and is not bipolar. you are going to let the smoke out of the cap and resistor real soon.

[@GamrokFeddy]

Well it is not bipolar but he put a diode in front of it. The other problems are a different story

[@oberst_krass]

Uuuhh, das ist aber wenig Erfahrung mit Elektronik.

[@leandroebner1405]

​@@oberst_krass lul. Die 35V sind auch völlig in ordnung da der cap ja parallel zur LED hängt.

[@victorfourman1683]

Capacitor is in parallel with LED. So the voltage on it will be about 2 - 2.5 Volts

[@oberst_krass]

@@victorfourman1683 you are right! Maybe up to 3,5 Volts but that's it.

[@Anisimov_Yu_M]

А потом люди удивляются, что от зарядки смартфона людей в ванне убивает, ведь "там 5 вольт"

[@user-6uw7r03vrb]

And then the capacitor fucking exploded.

[@td_44]

перегрев резистора 0.5 ватт и возможно деформация вилки в месте нагрева резистора, который будет отдавать 1.5 Вата тепла.

[@oberst_krass]

Das stimmt doch gar nicht. Denke noch einmal darüber nach!

[@handle5557]

in a series of led lights the most important current. no matter how many tens or even hundreds of voltages, the most important gang is the current. so here and there the resistor is set. if in the video use 15k ohms. This means that the power generated from the circuit is limited to only 15mA, which is very safe for an LED.

[@ALEFILES]

CONGRATULATIONS!!! Greetings from Argentina!!!

[@fay296k]

Use a series capacitor instead of resistor,100nf for 220v 200nf for 110v ,with no heat problem

[@hamradio599]

Correct way is in series a high voltage mono cap instead of a resistor to limit the current. Please consider the power consumption of your resistor.

[@DaPlenThing]

Good god I haven’t hear this song in years

[@Lil_Dances]

Лучше без конденсатора, а диод подключить встречнопараллельно светодиоду.. тогда диод можно брать не высоковольтный.. потому что обратное напряжение на нем будет равным напряжению светодиода (3.3), а на светодиоде обратное 0.7в.. но возрастет мощность на резисторе . Так он выделяет тепло за один полупериод, а так будет за оба выделять..

[@HighVoltageArcRD]

If you put the diode in reverse, you will have both resistor and capacitor light up which *MUCH* brighter than the led

[@Zeddify]

JUST USE A CAPACITIVE DROPPER INTEAD OF THIS INEFFICIENT CIRCUIT!!!

[@_itzdanqq_]

Just use a ceramic bipolar cap for limiting instead of the rezistor, its much more efficient

[@marjonagalliu6359]

Gut 👍

[@ruslanstepanenko5055]

Я бы диод поставил встречно паралельно светодиоду и добавил бы неполярный конденсатор последовательно, а то есть сомнение, что резистор долго не протянет при таком включении ;)

[@Dmitry_ct]

Расскажите ,как ОПАСНО подключить светодиод

[@aufroufchanel4618]

Itu resistor 15k elko akan meledak.seharusnya di atas 100k.

[@Tonevectorpro]

thank to resistor and rectifying diode 👍👍

[@jaguaracialvescardosocardo3920]

Que natureza heim ! Tem muita coragem por favor leiam atentamente os comentários e dê credibilidade 👏

[@xanataph]

That is a *terrible* way to run an LED from the mains. What you need is a low value / high voltage capacitor X2 rated, around 330nF should do the trick and a resistor of around 100-200 ohms. These three components are wired in series. Then a SSR diode (or another LED if you prefer) is wired anti-parallel across the LED. The capacitor acts as a "wattless resistor", dropping the AC voltage. The resistor stops excessive "LED zapping" currents flowing during switch-on and during weird transient events while it's operating. The reversed diode allows the other cycle to flow, otherwise the circuit will stop once the cap is charged. It also guarantees that the reverse voltage across the LED is low.

[@mohtashimali9669]

Yup its a half wave rectifier .

[@nailcetin1014]

Merhabalar fişi ters cevirmede yanıyormu

[@oberst_krass]

​@@nailcetin1014 Hallo! Ja, denn durch die Diode wird immer nur die positive Welle der Sinuswelle durchgelassen. Egal, wie man den Stecker einsteckt. Wäre die Quelle Gleichspannung dann würde es nur gehen, wenn es richtig eingesteckt ist.

[@VaibhavGuptashourya]

15K ohm resistor will hold 250v-300v and drop 5v which is good to on a ked and diode to change ac to dc charge

[@matousbarina3706]

It's verry dangerous

[@MuhammadUzairShah23]

Capacitor...After sometime=BOOM🔥🔥🔥🔥🔥🚫🔥🔥🔥❗

[@lafix2341]

Думаю, лучше будет подключить через блок питания на 5v, заморочек в 100 раз меньше

[@engineerNaderi-800]

nice 🎉

[@tamagotchi__]

В итоге у нас получилась такая приколюшка

[@Levent.Usta539]

Ustam elimde 16K Diren var 35v 220uf kondansatör var 40v 100 uf bir kondansatör var olur mu çalışır mı ustam

[@casio-F91W]

no bridge rectifier?? ElectroBOOM needs to rectify this

[@olegskornyakov2186]

Если вдруг диод "пробъёт" накоротко (а не в "обрыв"), то на кондёр попрёт переменный ток, электролит в нём вскипит, и его разнесёт. Тут лучше другую схему применить, с обычным кондёром 0,5 мКФ на 300 вольт, например (короч, см. в инете)

[@НадзирательВселенной]

только если пробьёт два диода и светодиод при этом окажется в обрыве

[@josephkaminski1857]

relies on the diode to rectify half the AC. Then creates a voltage divider between the LED and resistor, to put most of the remaining 50/60 volts on the resistor and only 5 v on the led. The cap is a dampener to smooth out the half wave peaks. This is Very dangerous. LED's tend to malfunction on the sort circuit mode, not the open circuit mode. Capacitors also degrade/fail into the short circuit mode. You would think that if the LED fails in short mode the resistor will just burn open. or if the cap fails and shorts it will just pop. But that is not true. Both these devices have something called smart short mode. If they happen to fail that way you have a real nice piece of plastic housing to start a fire.

[@Hertzstation]

Good brother, but please use 2m ohms resistor it's safe for you

[@worldwidedatarht1191]

You are a Tech-Scientist

[@TheCelestialFox]

Even though you get to solder while making this, it’s still dangerous, so you should solder other things.

[@samobot3270]

насколько понял схема работает так: сначала через диод и резистор заряжается кондер, а светодиод заперт, т.к. он подключен в обратной полярности, а потом на другой полуволне диод отключает от сети конденсатор и он разрежается в светодиод?

[@KS.81]

I just use 1 M ohms 0.25w resistor, work like a charm...

[@СергейБурцев-х9ъ]

Толково, может пригодиться для других целей. Попробую. 👍👏👏👏🖐✌🐰

[@owenbruce4120]

Good

[@makinginprojectbd]

Nice 😊

[@mucana_art]

Great ideas

[@HYOSAIZERO]

That works but it's too dangerous, that's not isolated by a transformer. Half wave rectifiers are not too good like full wave ones, this just reduce all electronics life and loses energy by overheating (resistor), which means very low efficiency...

[@HYOSAIZERO]

Even LED lamps have small transformers, which shows: "Even if something works (video circuit) doesn't mean that's good"

[@zfriendlybiz]

I was doing this 30 years back.

[@АлександрХилютич-в8ъ]

Это всего лишь стабилизатор напряжения,у нас нет стабилизированного напряжения Это ПЛОХО для граждан ❤

[@acomka00]

Is it safe and sound? And what was taken in the right side 1N...??

[@anandha12]

Never ever make circuits like this without understanding the basic electronics. Shock and 🔥 hazard. Stay away from mains voltage.

[@1991armi]

How do you connect several of them together for a dollhouse? Several of them at different distances/inches apart?

[@freeenergy8273]

Ar visām LED diodēm tā nevar ‼️ Jāzin optimālā strāva!

[@mst795]

Hocam 1 kac dakika prizde durunca direnc yaniyor

[@ZAFERYILDIZ52]

Yanmaz kardeşim LED cok akim çekiyor dur bu durumdan direnç watini artırın

[@freeenergy8273]

Noskaidrojiet cik daudz mA patērē jūsu diode! Visas LED diodes nevar slēgt pēc šīs shēmas ‼️

[@oilbay54]

Normal değil mi? 4 Watt biniyor üstüne

[@mst795]

@@oilbay54 biliyorum, 4,4-4,6 arasi

[@oilbay54]

@@loopthruloader Umarım watt, volt, miliamper nedir biliyorsunuzdur.Burada 220V gerilim yarım dalga doğrultuluyor. RMS değeri yani DC eşdeğeri 220/2= 110 V oluyor. LED 3.5V olsa Direnç üstünde 110-3.5=106.5V kalır. Çekilen akımı Direnç belirler. Böylece akım 106.5/15= 7.1 mA olur. Direnç üzerinde harcanan güç de 106.5x7.1=756mW yapar. Direnç 250mWlık. Tam üç katı. Ve kapalı yerde. Direnç ısınır ısınır ve yanar. Kesin yanar.

[@ismailalaca]

Wattli direncmi koysaydiniz

[@petrpetrov8562]

В магазине в продаже есть китайские ночные светильники , там внутри диодный мост, резистор 68ком , три белых светодиода и всё, втыкаем в розетку и как то работает .

[@ВОИНДОБРА-у1о]

Ну если имеется диод. То на ветодиоде получается не переменый а постояный ток

[@philosof963]

@@ВОИНДОБРА-у1о ...и даже если нет диода, светодиод будет работать в пол-периода. Резистор + светодиод. Можно ещё упростить, но это совсем другая история.

[@Lightskill293]

😮😮😮😮😮😮😮

[@MTTechnology422]

Wow 😮

[@bakus-hobby-ch]

Maybe you should be added a diode for reverse voltage protection at LED.

[@satansatanow1729]

10 из 10🎉

[@luka7001]

Resistor🔥🔥🔥 Capacitor💥💥💥

[@maksfrolow9224]

Да некто и неподумал о том что 220 вольт будет на конденсаторе 😢и свето диод как стабилизатор напряжения сгорит ,диоды плохо дружат с 220 да еще большие яркие

[@porhporhev493]

Кондею ни чего не будет, а вот от резистора можно будет прикуривать😅

[@sktechworks]

Which country bro you are??

[@a.l.ramanaraoramesh2200]

సూపర్ 👍

[@anemofis]

Excelente LO SIGO!!

[@deddydj1656]

Good ideas,.....

[@didiusousa8077]

Mas serve pra 110 e 220 ??

[@jeanzinbr]

Não. Ele está todo errado. O risco do capacitor estourar é altíssimo. Não faça o mesmo que ele fez, é loucura.

[@wilfredosanchez9659]

Superrr

[@vijaychandrasm1349]

Read all, but where we can acquire this type of HOLDER. Is it available in lndia? ***

[@Osman_0359]

Perfect

[@tutunelagrenouille9595]

je suis tout à fait d'accord avec ce que dit notre ami russe!! ce montage ne fonctionnera pas longtemps car la résistance va vite se consumer en chaleur!! c'est une résistance de 0,5W et la chaleur dissipée dans la résistance est de 3,3W. la diode ne sert à rien car une LED fonctionne aussi bien en alternatif qu'en continu!!

[@Intech1200]

This is NOT safe. Just use a transformer. 4 diodes (rectifier) and a capacitor.

[@ugurrbass]

Seri polyester kondansatör ilavesi gerekiyor. Bu şekilde çok fazla voltaj direnç üzerinde harcanacak. Led pano lambaları bu şekilde.

[@eeemrky]

Bu şekilde nasıl çalışıyor.. mantığı nedir acaba. 9 volt pilde patlayan bişey şebekede nasıl zarar görmedi 😅😮

[@moti_vati0n]

so is this actually an incandescent bulb made of resistor?

[@raja.p1418]

Eeled😮

[@АлександрКруглов-к7й]

Опытным путём выясняется что 15К определённо мало. В 220В, от 50К и больше + R 1- 2Вт.

[@ebtv445]

Use a 15 kiloohm 5 watt resistor in this case