Descriptive Statistics: The Mode

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0:00 Introduction
0:27 Definition
5:09 Mean vs Median
8:17 Challenge Question
Series music by Purdy.
purdy.bandcamp.com/
Song: 3 Friends to the Stars

[@armaosk]

Hi Justin. Fun question there at the end. I came up with the following set of numbers: 0, 1, 2, 3, 3, 10 mean = (0+1+2+3+3+10)/6 = 19/6 = 3,17 mode = 3 median = (2+3)/2 = 2.5 I think this is the minimum set with median < mode < mean.

[@pipertripp]

that's what I came up with too

[@agrajgaur5788]

exactly what I came up with!

[@priyaark]

1, 1, 2, 2, 3, 3, 3, 10 Median - 2.5 Mode - 3 Mean - 3.125

[@japhethchew1604]

I like how you "tempt" people to try out the exercise :)

[@SanjayFGeorge]

I'm thinking of incomes in a banana republic. Comrade El Presidente has a huge salary pushing the mean way up into the Stratosphere ... All govt employees have the same fixed salary giving a high frequency for the mode and then a huge swathe of poor with various meagre salaries pulling the median below the mode ...

[@aalaptube]

For continuous observations (as opposed to discrete observations), the chance of a particular observation repeating is rare, though the frequency of the class interval in which it lies, may be very high. If I increase the class interval to the whole range of observations, it will become flat (horizontal). So this means: 1) Class intervals must be used, yes? 2) If so, what is the best size of class intervals for n observations? How are standard deviation curves drawn, what is their class intervals?

[@zukofire6424]

I love your voice!

[@blackheart2395]

Thank you for amazing videos. I have a doubt that finally, with a distribution where all samples have the same frequency, let's say 1, each sample can be a MODE?

[@MDMAx]

Sounds like a square distribution. Measuring a mode for it has no meaning. As a statistician it's your job to pick the most representative data to show the reader.

[@AnilPatel-fs1kt]

Brilliant - I always found statistics confusing, but your explanations are very clear, Thank you.

[@bichithbalan5424]

Which measure of location will be suitable to compare, a. Heights of students in two classes, b. Size of agricultural holding, c. Average sales for various years, d. Intelligence of students, e. Per capita income in several countries, why?

[@ashimdhungana7966]

Thank you

[@kundanshekhawat6929]

Great Learning.. Thanks

[@arfanmansoor6707]

Here is another set of number: 0,1,2,3,4,4,9,10 Mean: 4.125 Mode: 4 Median: 3.5

[@saikatpaul19]

Coincidently i got the same value bro😁😁

[@pb48711]

Flip the tail of an asymmetric distribution.

[@sainathm36]

you confused me at 3:44 you said mode is calculated by selecting 2 matching numbers and now here you are taking mode as highest frequency? how also how you calculated median and mean fully confused

[@RajeshwariThengil]

Datapoint = [1,5,5,5,3,3,5,50,2] Mode = 5, Median = average of 3 and 5 which is 4, Mean = 8.2. Median

[@lordrickalinaitwe3599]

50 is not an interger between 0&10

[@St.Karelis]

We asked 10 people, how many ice creams they wanna have for free. 1 person answered 1, 2 persons answered 2, 2 persons answered 3, 3 persons answered 4, 1 person answered 5 and 1 person answered 30! 1+2+2+3+3+4+4+4+5+30 median: 3,5 (between 3 and 4) mode: 4 (the most wanted choice) mean: 5,8 (the average demand)

[@fraggodgaming4433]

1,2,3,4,4,10

[@lifetech4146]

Quite too late for this but , here is some values 6 6 5 6 10 median = 5 mode = 6 mean = 6.6

[@ebtisamhussien7389]

My set is 2 2 1 10 The mean is 3.75 The mode is 2 The median is 1 So the mean is greater than mode which is greater than the median

[@user-hv3oy8np1g]

Your median is (2 + 2) / 2 = 2

[@guillemguigocorominas2898]

0, 0, 1, 1, 2, 2, 2, 9 median = 1.5 mode = 2 mean = 2.125

[@nethravathibg1746]

for census example, why its weighted mean is calculated and not the mean calculation?

[@26nafisbinazad93]

because of the frequencies involved. The example asked to derive the mean number of children. Btw can you tell me, why the median is two here?

[@allisonal]

If you wanted to do the calculation without weighting, you would need to take the mean over all 5 million numbers. Not a problem for computers, but would be practically impossible using pencil and paper. Weighting lets us calculate the mean from a much more compact data format.

[@uguumurkhosbayar1683]

3, 3, 3, 4, 4, 10

[@agrajgaur5788]

0, 1, 2, 3, 3, 10

[@aham_harshit_dwivedi]

2,3,4,3,1

[@juwaldtsieberhagen1120]

so how I calculated it was: credits carry more value than percent because you can sore high marks on a low credit level and still fail because it is weighted low. hence i worked out the maximum amount of credits that she can score per test. if 65% gives you 4 credits how much would 100% give you. with only one variable you can work it out. 65/100 *4/x this gives you 6.1 but as with credits you either get it or you don't so you have to round it up to the following number making it 7. calculate each maximum credit score giving you 28 possible credits. take the amount of credits she scored 20 and divided by max amount of credits times a 100. gives you 71.4%. so she is on average able to score 71.4% of the possible credits no matter the test difficulty or size.

[@user-sm6tk5vv3d]

(7,8,8)---> this is the nearest answer

[@Shivangsharmaaaaaaa]

4,4,3,5,6 median is 3 mode is 4 mean is 4.4

[@keshavverma8246]

1,1,2,0,10,1,1 here mode is 1 median Is 0 and mean is 2.28