Zener Diode as Voltage Regulator (Part 1)

[@hansikagupta2161]

Thank you sir, your videos are very helpful. Iz=2.67mA,VL=10V, current across 1k ohm is 6mA,Pz=26.7mW

[@junaidsheikh2442]

these are all the examples from BOYLESTAD's book . thanks a lot, because we read the same book in our university.

[@ramjishivhare1238]

Sir condition for zener diode to act as voltage regulator is v(input) greater than v(rever bias of zener ) or mod of v(input) greater than v reverse?

[@ramjishivhare1238]

Sir condition for zener diode to act as voltage regulator is v(input) greater than v(rever bias of zener ) or mod of v(input) greater than v reverse?

[@vamsikrishna9825]

Ramji Shivhare The condition for Zenor doide to be act as an voltage regulator is that the applied voltage across the zenor diode must be greater than the rated zenor voltage so that we can get the constant output vz at load resistance. Hope u understand

[@CelestialMpulo]

9th

[@deepakpandey9935]

That book is so huge bro, I m even scared to see it😂

[@lutfunnaharasha7814]

VL=10v,VR=6v,IR=6mA,IZ =2.67mA,PZ=26.67mW. Thanks for the awesome videos😊

[@Ravikumar-so1bi]

Can u give clear explaination please

[@SaifAreqi]

@@Ravikumar-so1bi Vz= 10 from the question

[@thecalm_soul]

Detailed solution please.

[@AdityaRaj-gj4dl]

@@thecalm_soul If we consider load is equal to 3K ohm then calculate Vth. Vth is 12V. Since 12 > 10 zener diode in breakdown region.Since Zener is a voltage regulator voltage across load will remain 10 volts only.Use Nodal analysis. IR =(16-10)/1000= 6mA. Since Voltage across load is 10 volts, IL =10/3k =3.33m. Apply KCL in order get current through zener diode Iz=(6-3.33)mA=2.67mA. Pz =(Iz*Vz)=2.67*10=26.67mW.

[@AdityaRaj-gj4dl]

@@Ravikumar-so1bi See the above explanation.

[@ayushvats1808]

After long search on you tube I got it in ur video,,thanks sir bcoz kha kha maine tum waste kiya isko smjhne k liye jitta shi tarike se aapne step by step btaya was really awesome

[@marlon123444]

I've been following your lectures since last year. Thank you sir.

[@ahmedrihin]

Vr = 6v VL = 10V Iz = 2.67mA Pz = 26.7mW Thank you sir .❤

[@jitendrakumarmahato2055]

Lot's of love ❤️❤️❤️ from Nepal 🇳🇵 Your videos are amazing and I am gaining confidence in electronics as well. Your efforts are very much appreciated. Thanks a lot.😊😊

[@ananda_saha_shorts]

Iz=2.66mA,Pz=26.6mW

[@AkashDeep-bv1fi]

Same mera bhi

[@Chalo_Badle_Bihar]

Same here bro

[@anusmitsaha8604]

Same here🤟🤟🤟🤟

[@sabidkhan3970]

✌✌✌

[@EnglsihCommByNawaz]

No I= 4A , Vth= 12V, IR= 4 mA VR=4V, VL= 12V

[@watch2-grow]

thank you very much Neso Academy, one of the best videos for understanding Zener Diodes as VOLTAGE REGULATORS

[@harshpatidar7682]

mkc teri , exam aa gayi kya ? humse pehle mat pad

[@Josuke217]

bit mesra k23?

[@tasfiaaminchowdhury2561]

Thanks for these awesome videos .. these are really awesome and really helpful for us .. like for the night before the exam ..

[@preetamkumar838]

Hey There is an calculation error in last line of numerical. It would be 8.72 instead of 8.64

[@prasanthg546]

Sss , u r correct

[@sindhupalanki6578]

Yes

[@_sadaf_]

Yess

[@hiteshleburu]

Yes

[@nimitgarg2531]

Yes there is a calculation error

[@XAKGSAISREENIVAS]

Without u iam zero, love neso

[@aakashranjanghosh2640]

Bro tell me a thing , that in question Iz is entering through positive terminal of Zener diode hence will it absorb power?

[@sonusambharwal8828]

Neso acedmey is the best academy for electronics knowledge......thanks sir

[@alterguy4327]

It was Clean and Clear.Thanks Neso Academy

[@faisalshah6563]

Sir you are doing an amazing job, very fruitful videos these are .. 💜

[@sathwikreddy1544]

ohh my god i was unable to get this topic but now it's crystal clear . Thanks a lot from the bottom of my heart...

[@alfredcalleja450]

Another clear and concise explanation. Thank you again.

[@dakshgoyal5262]

Thank u sir i have cleared a lot of doubts from your lectures

[@surajkumar-ok7dm]

Ohh my god i was unable to get this topic but now it's crystal clear . Thanks a lot from the bottom of my heart.....❤

[@shubhamrajput2667]

hey I have doubt! how will u replace diode with zener voltage (if it is sufficiently reversed bias)? what will be the polarity

[@prankishoriitkgp3772]

Thank u so much sir for your helpful and mind blowing content

[@ChintanMeena]

VL=10Volts ; IL=3.34mA ; Iz=2.66mA and Pz=26.66 mW i have doubt though what if in some case i get Pz greater than maximum power diode could dissipate ...how would i solve such question ? ?

[@ChintanMeena]

i think diode will kill itself then :P

[@sandylauguico7963]

This is my answer too. VL = 10V, VR = 6V, Iz = 2.67mA, Pz = 26.67 mW

[@vamsikrishna9825]

Chintan Meena The diode it self will damage at greater power dissipation

[@Avantisha]

Iz = 2.6mA

[@Avantisha]

Iz=2.67mA

[@shashanksankepally2963]

Great explanation

[@uzairawan1029]

why did you change the polarity of voltage replacing the diode? in reverse biasing you had to mark the upper terminal as negative and lower as positive...

[@spanda7281]

thanks a lott .....neso. we love you

[@studyelectrictech1236]

Sir , in the numerical problem, why do you use both cases with an open circuit instead of using the first case with Vz

[@namankukreja818]

Thanks sir for such a nice explanation 😀

[@chinmoy5936]

diode will be on . Voltage across resistance=6V,Voltage across load=10V,current through the zener=2.66mA, power=26.6mW

[@MohanKanakaji]

can any one help me how to design a voltage regulator of output 5v and input 12V and load current(0-2)a

[@rohanbhandari9976]

what ans of your assignment you given replacement resistance 3k?

[@malcolmpinto3374]

That vz value of the battery which we put instead of the zener diode is 10v or 12 v ?

[@arijit1204]

as we know in reverse bias mode p type semiconductor is connected to -ve end of supply.. but in this case +ve terminal is connected to the p type.. I didn't get it.. is it because zener diode..?

[@Abhijeetkumar314]

Nice explanation

[@maryamshahzadi1054]

you are a perfect teacher

[@nagamahendrareddybogala6415]

please do lectures on network analysis..

[@EBKEC_rituKumari]

sir can you make a series of placement questions for analog?

[@physicsexploration7723]

Sir you explain very well

[@EEAshutoshTripathi]

I am not able to understand boylestad's example 2.22 . Sir please help me. It is very different from other problems ☹️

[@ABHISHEKKUMAR-.]

Sir in zener diode problem to check on or off we have to find first Vth And in normal diode to check on or off we have to match the direction of current to the direction of pn junction diode ???

[@nishamore8244]

how much ohm resistance must be used for current limiting resistance

[@Ankittiwari-yk8ix]

In second case zener diode should be in forward bias but why you not changed the polarity of Vi ?

[@yuvrajsingh8512]

plz upload the answer so tht we can match either we r solving rit or wrong..i request plz

[@electronics9414]

VL = 10v , VR = 6v, IZ = 2.67ma , PZ =26.7mw

[@bullshitter-guy]

Vl 12v.Vl=Vth

[@jamilsamouh9134]

why there is a resistor in series with the diode? and should there be a resistor at all the times?

[@mohsenmazandarani7506]

Understood......nice explanation

[@sheerin_jjk1322]

Sir Vth=VL=I*RL=4×3=12V the first step u did to find out whether the diode is on or off. i worked out the way you did but if VL= 12V then Vl is not equal to Vz right sir?

[@mandheermishra147]

Sir when u replace zehar diode with its equivalent modal (as a constant voltage source) when zenar diode is on then polarity should be opposite what u wrote there because we consider that triangle of diode with +ve terminal and that line of diode as -ve terminal neso academy please clear my dabut

[@stephenmasih4460]

thanks a lot sir............your tutorials are very helpful..........

[@Viralvideonew7]

Vth=12V and VL=10 V what is the voltage across diode.... Vth or VL? If VL then why not Vth?

[@vidhyadhar64]

Your videos are good.. which software do you use for drawing or writing?

[@sexo6162]

Hakunamatata

[@Muantea]

Vidhyadhar Dharmadhikari scrapbook

[@96Lamo]

THANK YOU SO MUCH

[@swapanghosh7550]

VL = 10 v parallel to Vz Vr = 6v IL = 3.4 m A Pz = 26.7 m W < 30 mW i.e Pzm

[@righteousness185]

good teaching..very helpful.

[@Dreamlbsnaa1619]

Thanku sir ji 🙏

[@曾华-d8s]

hey it's case1 not case2, right? <a href="#" class="seekto" data-time="889">14:49</a>

[@toppersadda277]

Sir thanks for these videos'( is the ans Iz=2.67mA , Pz= 26.67mW , Vr= 6V , Ir= 6mA , Vr= 10V )?

[@alexfava4132]

How is Iz = 2.67mA? Pls explain

[@lyricalme1776]

First u calculate Vr=Vi-Vz=16-10=6volts Then calculate Ir=Vr/R=6/1=6mA Then calculate I(rl)=Vz/(rl)=10/3=3.33mA You will have Iz=Ir-I(rl)=6-(3.33)=2.67mA There you go

[@ShashikantGupta04]

VL=10V,VR=6V,Iz=2.7mA,Pz=27 mW

[@DevRamanTaneja]

great work sir but i am unable to understand why your Vth and VL are not equal

[@vinayak8041]

I'm not understanding and for which class

[@rahmath1181]

I like u r presentation...good work

[@harshpratapraghav2342]

sir 7.27*1.2=8.724 not 8.64 please correct it

[@kotasriveni7914]

Sir What's the difference between Vth and Vz? And zener conducts in reverse bias condition but why the diode is open circuited? In the problem.

[@vamsikrishna9825]

Kota Sriveni The difference between the vz and vth in above lecture is vz is the maximum output voltage that Zenor diode can give, but in order to give zenor output voltage constant the applied input voltage to the zenor must be greater than the vz. Then only the zenor diode will turn on . So to find input zenor voltage we find vth.

[@sakhawathossain7864]

Endless thank you for your job

[@dheerajkumarraghuvanshi532]

Doubt .. !!! In the two cases discussed for fixed voltage and resistance--- Since we are talking about the negative region... In case 1 when Thevnin's voltage is greater than or equal to Zener voltage the zener diode must be OFF. And when the Thevnin's voltage is lesser then the zener voltage the diode should be ON

[@sayantankundu9903]

Exactly the opposite.

[@riseabovehate9476]

How can Vth be equal to Voltage across the zener ? Don't we need to find Rth after finding Vth ? Pls answer my question asap!!

[@sayantankundu9903]

No. This is not a thevenin theorem sum.We are finding Vth to find out the voltage across the zener diode.

[@joeryder5739]

How is a Zener diode used for line and load regulation?

[@tarunjain241]

Good explanation

[@prathammauryahbtu7528]

is pdf of what sir is written on board is avaible anywhere

[@kiranilyas079]

answers are ... VL = 10V, VR = 6V, Iz = 2.67mA, Pz = 26.67 mW :)

[@samart3010]

Plz make video on TRANSISTORIZED SERIES VOLTAGE regulator. Please. please

[@balakumar1966]

Thank U Sir ❤🙏

[@muskangupta9250]

VL=9.9v, VR=6v, IZ=2.7mA, Pz=27mW by using case 1 where Vth>Vz.....I hope thz z correct

[@ndoumga]

Hey, do you intend uploading videos on Bipolar Transistors as well?? It will be greatly appreciated

[@thakurjaysingh10125]

This video is very helpful to me thank you so much sir

[@sadi3230]

Thank you very helpful teaching

[@mudassarraza6448]

Could anyone confirm the correct ans?? Mine is VL = 10V, VR = 6V, Iz = 2.67mA, Pz = 26.67 mW

[@MohanKanakaji]

can any one help me how to design a voltage regulator of output 5v and input 12V and load current(0-2)a

[@94D33M]

wow you got the correct answer man congrats

[@Leo-vs9dx]

Beautiful! thank you

[@-_--hp2di]

Can you derive a formula to find the voltage across zener diode using other methods besides thevenins theorem such as nodal analysis and such? Thanks for answering my question

[@ShubhamSharma-sn8rq]

In case 1 voltage source by replacing zeher diode would be in opposite sence I am nt able to understand this pls clarify

[@naturecall7861]

Sir audio is not very high. Kindly increase audio. Great Work ❤️

[@vandanashorts2520]

how the positive terminal of battery vz is upward

[@rajendrajagtap1653]

Vandana Mishra It is reverse biased to operate as voltage regulator

[@teetanrobotics5363]

Sir, please complete the playlist

[@akashkumarsingh640]

Excellent sir

[@sumitsouravamohanty8935]

why u remove the zener to calculate voltage across zaner diode

[@kailashchandmeena6073]

To check the state of zener diode

[@hemantkumarverma7255]

Sir two diode add karka short ckt. Protection hota h in transistorized series regulator. please uski working pa 1 video bana dijiya.

[@hemantkumarverma7255]

Sir I will understood, so no need of video, thank you

[@yuvanm411]

Answer for vl is must same as vth (7.27m A × 1.2k ohm = 8.72) but you mention it wrongly 8.64v... If any one noticed than hit a like

[@fazilanasim1240]

Yeah kindly explain which one is correct ! I think both methods are correct bcz diode and RL are in parallel and hence the voltage should be same .. tell me if m wrong

[@bhabanishankardas9800]

He has wrongly written that one. 7.27mA x 1.2kiloohm = 8.724 volts, instead he has written 8.64 volts.

[@jasoniasrex]

really nice job!!

[@Selenn_A]

how can ı found the q point of this diode?

[@divikchoudhary7829]

How your V(load) and V(thevenins) coming different as both are equal to 7.27mAx1.2 Kohms. You have calculated V(thevenins) = 8.72 V whereas V(load) = 8.64 V. Being both in parallel both should be same.

[@shahidqamar2276]

thinking same

[@kshitijvengurlekar1192]

Thanks

[@anishakumari6359]

VL= 10V, VR=6V, IZ=2.67mA, PZ=26.67 If my answer is not correct then please correct it.

[@-_--hp2di]

Got the same results

[@-_--hp2di]

Can you give a feedback on my comment?

[@kunalmodi6814]

its correct.. I am getting the exact values

[@mamthamamtha8271]

tq sir... it was helpful

[@pubghackieverunit3650]

thank you sirrrrrrrrrrrrrrrrrrrrrrrrrrrrr 🤗🤗

[@uzairhabiburrehman2693]

2nd exp ans is VL=12v, Vr=3.3mA,Ir=6mA,Iz=2.7mA,Pz=27watt

[@Ravikumar-so1bi]

How

[@MohanKanakaji]

can any one help me how to design a voltage regulator of output 5v and input 12V and load current(0-2)a..?pls

[@kishoryenneti1444]

My dought. Vth=VL..then how Vth= 8.72V and VL=8.64V...

[@jigarpatel5396]

good teaching sair

[@mustafasidal2255]

Thanks for video

[@jigarpatel5396]

sair please Make lecture for cliper circuits

[@haroonrasheed2271]

Thanku sir.