The dimensions of this question is faulty, no? 21:20 because the vertical distance is 2.68 m, but the question gives it as 0.2 m. The answer wouldn’t exactly be giving the speed right after it exists the field then. So, anyway with the given dimensions, resultant velocity should be around 1.54 x 10^8 ms^1 right? Anyway, thank you so much for this. I love your explanations. You connect the concepts very fluidly, cover all most all the parts in the lesson in a breeze. I actually grasped a few of the lessons I considered super confusing, in less than a day before my test, thanks to you. Thank you so much

45:40 its ohm not volt

You win any IPHO Olympiad

only 3% of viewers liked this video WHAT!!!!!!!

Hey there! in the question at 32:00, you dont actually need the equation E = MC(Theta), because the specific heat has its units given, it is easily understood that 4200 Joules are required for a one degree rise in temperature, and 4200x7 is required for a 7 degree rise. Voltage is just joules/time so we can rearrange the P = V^2/R as W = (V^2 X time)/R and as for the voltage through A being zero, it is observed that the entire circuit is a balanced wheat stone bridge and whenever there is a balanced wheat stone bridge, current does not pass through the diagonal wire hence it can be ignored. All this makes the rest of the calculations pretty straight forward and I got the same answer as you :) GREAT VIDEO BTW IM LOVING IT!!!!!

This is really great, this question was one of the most difficult problem in the entire jee advanced 2023... Solving it completely understanding question breaking into parts writing the minimum height in terms of change in temperature

Is it useful for A2 Level IGCSE Physics?

What is Z in the last question

Get a better mic plz

exactly what i needed, thank you

I am form india ❤

Does this covers edexcel a levels spec ?

are there any textbooks which I can use to prepare for this? i do the ib programme and I take math aa hl, do I need to refer to any a-level books?

This guy has no idea, 20:00 you come out with 0 as a limit of integration? when you solve the equation you're dividing by x, so x=0 is the other solution you're looking for,

This is brilliant, very very helpful. I love how you explain. You squeeze in all the details really well. Connects each and every concept to one another, actually love it. Thank you so much.

You explained so nicely mann 👍👍👍

22:19 cheeky pun that

kzbin.info/www/bejne/pYSnfolrq5iJq80si=e5Wlt3n0vfYDnOuX

Everything we see around us exists as both particles and waves…. Anyone with a cat knows that solid matter can temporarily transmute into a liquid form. 😂

I was in 2016 batch। Ya thats true

exam in an hour and 30 minutes 😅

keep it at 69 likes

TQqqq

Hi Than you so much for your videos! They give me hope for my next years' physics exams!

Can you please have a comparison video of 30 to 35 minutes comparing this book with one of the top hardest questions of jee advanced(range: year 2014 to 2024) please consider only top hardest questions so that I get a clear view about this book

You made it easy now i am going to study COM then i will try it 😂

5:03 can we use v^2=u^2+2as for this? i got 1 x 10^16

Thank you sir. I'm going to have a physics test today. You saved my life!!!

Unhelpful

for Q8, I'm pretty you slipped at the end. 2 and 3 are non-zero, so surely A is the answer?! (question starts at ~ 13:05)

11:15 how to know when to multiply and divide????

Imagine an Asian uncles solves it in 1 second 🙏

I was close to sobbing, I missed my teacher's lecture on this topic and after an hour and half of jumping from sources, I can finally say after watching this video, that I understand the topic. Thank you so much for the well thought out & easy to understand lecture. You earned yourself a subscriber signore!

cant watch the vidoe with thaat music

Very helpful video

Hello sir I have a question, am I able to send you an email?

Would it be ok to use F=BILsintheta if theta is the angle between the area and the field lines (ie the angle u said not to use) Thank you for posting this content it’s really helping btw.❤

these videos are really helpfull thank you for that pls bring more such works on other topics also plssssssss GREAT WORK

Idk why it is consider as hard

can you do 1.5/2.5 (force/total force as a ratio) x 1.0m to get 0.60m? or is the goal to hit all the marks on mark scheme

I can’t thank you enough, genuinely, for making this video! I used to be a A* student in physics before the middle year of my AS level in physics but since I took biology instead of math my grades started to suffer due to my lack of practice in math. I currently get a B which isn’t bad but it’s not what I’m aiming for so thank you so much cause I know this will help me loads in my A2 this year ❤

Eventhough Im a TMUA applicant, watching ur ESAT videos are equally useful for my revision, love it

Where does -6.67×10^-11 came from?

Sir when solving this problem , we can easily take the moments about the point where the 5 kg mass is suspended. Considering clockwise moments as positive , d*(F1) - (1-d)*(F2) =0 d*(k1*x) = (1-d)*(k2*x) (since the extension is same in the two springs.) d*(10) = (1-d)*(15) 2*d = (1-d)*3 5*d = 3 therefore , d =0.6 m Hope this approach is better. 😊 Anyway , your video is a great one !!! ❤

Mc2=e ?

Everytime i see this question, brings back memories of JEE16. I felt the physics paper was very tough, i couldn't clear JEE Adv that year but I did it the following year. Try and try again, a little motivation for future aspirants.

Problem 1 Answer A also has x^3/4 so your method is not valid for a student taking the SAT exam as they would be confused Heres a better way to approach this. If we use chain rule we’d bring the power forward and multiply and take one off the power So thats 4(2+x/2)^3 Now we dont need to expand the entire thing We all probably know when expanding cubic term we cube the first term of the expression, here its 2 So if we expand it, 4 would get multiply we would get 4 * 2^3 which is 32. Now when using the chain rule we also differentiate the inner expression, so that’s be 1/2 if you do it So 32/2 =16 and thats your first term for your derivative and theres only one answer with 16 as first, so D

Is success in the exam and the interview enough to get in or do past academic success matter (olympiads etc.) ?

Awesome 😊❤