God bless you! You have no idea how much this video helped me! Thank you Chad so much!!!!
@ChadsPrep2 жыл бұрын
Glad it did, David - thank you!
@peybak3 жыл бұрын
Thanks for the repost Chad. You're a real pro!
@ChadsPrep3 жыл бұрын
You're welcome Peyman and thanks in return! I definitely don't want any errors out there confusing students. Super appreciate you catching my error!
@abhishekkumarntsescholar5550 Жыл бұрын
Thanks u sir , this really help in my iit preparation
@ChadsPrep Жыл бұрын
You're welcome - Happy Studying!
@PunmasterSTP Жыл бұрын
Hey, how did iit end up going?
@123xjd3n2 жыл бұрын
Hi Chad, Im wondering what your elementary biochemistry is. Btw thank you for your awesome videos
@ChadsPrep2 жыл бұрын
Hello Quynh! You can check it out here: www.chadsprep.com/chads-elementary-biochemistry-videos/ There's a nice drop-down menu outlining the entire course. It was designed to follow a 1-semester survey course on biochemistry. Hope this helps!
@user-qs8he1ml3k7 ай бұрын
Excellent video. Just a quick question. We have to add heat here in step 3 because removing OH as a leaving group is so unfavorable right? Also, would we consider the red boxed in product thermodynamic and the other 2 kinetic?
@ChadsPrep7 ай бұрын
So step 3 is an intramolecular aldol condensation. We need the heat to favor the aldol condensation mechanism to form the alkene product - this is an elimination mechanism (which is favored by heat) where we lose H2O (hence the name condensation) from the OH and H (alpha carbon) which I discuss at 5:00 onwards. If we don't apply heat we would get the aldol product (with the OH group still attached).
@strugglingcollegestudent Жыл бұрын
Hi Chad, my organic chemistry class teaches one more chapter (carbohydrates and reactions of carbohydrates, etc) can you add to your playlist?
@ChadsPrep Жыл бұрын
Alright Sophia! I'll have the first one ready in the morning. 😊
@PunmasterSTP Жыл бұрын
How's your class been going?
@PunmasterSTP Жыл бұрын
Robinson Annulation? More like "Really great information!" 👍
@ChadsPrep Жыл бұрын
And another!
@stephenmarvin26927 ай бұрын
If the product ends up creating another conjugated ketone, can you expect the reaction Robinson Annulation to occur again?
@ChadsPrep7 ай бұрын
Which example are you looking at?
@stephenmarvin26927 ай бұрын
@@ChadsPrep It's less so from this video but more so hypothetical. Because at 8:12 I noticed that a conjugated ketone could have been formed so I was just wondering. Thank you!
@ChadsPrep7 ай бұрын
We have to consider both steric hindrance and the presence of donating groups (alkyl groups) in this case which reduce the electrophillic nature of the beta carbon