Absolute Dependent Motion: Pulleys (learn to solve any problem)

Learn to solve absolute dependent motion (questions with pulleys) step by step with animated pulleys.
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More solved questions:
• Determine the displace...
• The motor at C pulls i...
• Determine the constant...
• Determine the speed of...
• If the end A of the ca...
If block A is moving downward...
If the end of the cable at A is pulled down...
Determine the time needed for the load at B...
Determine the speed of block A...
Find more at www.questionsolutions.com
Book used: R. C. Hibbeler and K. B. Yap, Mechanics for engineers - dynamics. Singapore: Pearson Education, 2014.

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[@QuestionSolutions]

I am sorry to hear about the troubles you're facing. I can understand the frustration of professors showing slides or explaining things minimally, since I've seen it happen even before the quarantine. But I am glad to hear that this helped you :) Stay safe, and keep your family safe. I wish you good health and the utmost success for you in your endeavors. Best of luck with your studies!

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[@mustardthe2ndkingoffastfoo570]

I dont know if this contradicts what you are doing, but what I have been taught to do is after getting the relation e.g Sa + Sb = 0, to then draw a free body diagram for each system and to assume the direction where the cable length increases to be positive. thank you for the video

[@QuestionSolutions]

There are many ways to solve these problems. I think its much easier to just pick the direction of your position coordinates to be positive, instead of going back and forth with positives and negatives trying to find which moves up and which moves down. It's completely up to you, but with this method, if you get a negative value, its opposite to the direction of your position coordinates, and if its positive, its in the same direction. Its a lot easier to keep track of. This also eliminates the need to draw free body diagrams since you said your method requires that as well. In the end, it's entirely up to you 👍

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Great explanation. Can you say which software did you use to do such nice animations? Thank you

[@QuestionSolutions]

I use illustrator to draw the diagrams and after effects to animate.

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You're very welcome and I am really glad this was helpful :)

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@@QuestionSolutions can you also upload questions on bohrs model ? Would be a great help

[@QuestionSolutions]

I am not familiar with bohrs model. Is the spelling correct?@@joc4970

[@joc4970]

@@QuestionSolutions i am sorry jf I was not clear but By bohr's model i meant bohr's atomic structure. Im sorry but english is not my first language

[@QuestionSolutions]

Ah, okay, that makes sense. I was trying to figure out what the Bohr's model had to do with statics 😅 So I haven't really covered any chemistry yet on the channel, and I am not sure when I would cover that topic. There are lots of videos on that topic, did you do a search on youtube?@@joc4970

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[@QuestionSolutions]

Illustrator for diagrams, after effects to animate👍

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Best video on pulley

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Glad to hear :)

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[@altuber99_athlete]

I'm studying Control Systems. Is there a relationship for the _forces_ rather than _speeds_ along the pulleys? Great explanation.

[@QuestionSolutions]

Hmm, I am not sure. There might be, and if I learned it, I just don't remember. If I do come across it though, I will definitely leave a comment here.

[@altuber99_athlete]

@@QuestionSolutions The only relationship I've seen so far is that, for frictionless pulleys and massless cables that can't be stretched, the magnitude of the _tension_ force along the two extremities of the cable is the same, and the magnitude of the _acceleration_ too.

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Thank you very much 🌹🌹 What program do you use for editing?

[@QuestionSolutions]

You're very welcome. Diagrams are drawn on Illustrator, videos are animated on After Effects.

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brilliant!

[@QuestionSolutions]

Thank you!

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bro it gave me confidence as i didnt have it i knew how to do it but with the shit pulleys i drew ahh helped to visualize way better

[@QuestionSolutions]

Always happy to help! Keep up the good work 🙂

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[@QuestionSolutions]

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[@QuestionSolutions]

Thank uuuuu :)

[@JD-xp6gc]

could I theoretically have said Sa+Sb+(Sa-2Sb)=L for the first equation? Also your videos are incredibly helpful!

[@QuestionSolutions]

Hmm, no, because that doesn't account for the cable attached to block C. So Sa-Sb gives us a small section on cable A, if you subtract 2Sb, I am not sure what that accounts for, I guess 2 lengths of Sb from Sa, because you're "subtracting" the length of Sb from Sa. Also, since you only have Sa and Sb, you can't get the velocity of C. Usually, I think its a lot better to keep them as simple as possible, just a position coordinate per pulley. I am glad the videos are helpful :) Many thanks!

[@myelinsheathxd]

thx!

[@QuestionSolutions]

You're welcome!

[@jhfghrt1918]

Hello! i wonder, i the case where we need 2 datum lines, does the datum line need to be in perpendicular all the times?

[@QuestionSolutions]

I think what you are asking is whether the datum lines need to be perpendicular to each other? If so, then no, it doesn't. The datum line is only a reference line to measure the distance from. If the "object" is going in the vertical direction, then we create a vertical datum line, and if it's in the horizontal direction, we create a horizontal datum line. In most cases though, the datum lines will end up being perpendicular to each other since they are either drawn vertically or horizontally.

[@jhfghrt1918]

@@QuestionSolutions Ahh, thank you very much!

[@QuestionSolutions]

@@jhfghrt1918 You are very welcome!

[@The_Engineer]

in the third problem the length of cable from C to B doesnt change in length. You said earlier in the video that we dont need to account for unchanging lengths, so why do we account for it here?

[@QuestionSolutions]

It actually does change lengths. It's just hard to show it, but there is a small change as it's being pulled up since cable BC is wrapped around the big pulley.

[@jakeschnos9689]

At 5:03 you give the equation for pulley B’s cable length. Why Sb+2(Sb-Sc) instead of Sb+2Sb-Sc? I’m having trouble seeing where that second Sc term comes from.

[@QuestionSolutions]

So if you look you can see there are two cables between pully C and B. SB represents the length from the datum to pully B, so we don't have 2 of those cables. So it can't be 2SB. How can we determine the length between pully C and B? We can do that by subtracting the length of SC from SB. So the total length to pully B minus the length to pully C. You have 2 cables, so we get 2(SB-SC).