x+y=a and xy=b. Then, a+b=15 and ab =54 > (a,b) = (9,6), (6,9). If a=6, b=9 > x=y=3. If a=9, b=6, x=1/2[9 +/-√57], y = 1/2[9-/+√57].
@batavuskoga2 ай бұрын
How did you get : a²-15a+54=0 ? Explanation step by step, please. You have the same some time later with x²-6x+9=0 and x²-9x+6=0. I understand the other parts of the video
@Bertin-q3y2 ай бұрын
X=3. Y=3 X=(9-57^0,5)/2. Y=( 9+57^0,5)/2 et reciproquement
@hjs61022 ай бұрын
Well I see the thumb and say 3 within one second.
@Shobhamaths2 ай бұрын
Let a=x+y, b=xy;a^2-15a+54=0, (a, b) =(6,9) ;(9, 6), (x, y) =(3, 3), (9±√57) /2 , ((9-√57) /2, (9+√57) /2)👍