A TRICKY equation from SAT math exam

[@viniciusdeavilajorge5053]

You must replace π for (π+2kπ) inside Euler's identity. Your solution covers only the case k=0

[@Mathematicalexpression]

Класс

[@RobertCantwell-z1n]

Very interesting , good methods .

[@askmaxim]

x=1/log[base 5](-5)

[@GigsChad-di9oi]

Nice i learnt a alot ❤from india

[@jdbtwo]

This is almost the exact same problem that was shown on this channel in a previous video here : kzbin.info/www/bejne/nHyxiaR8Z9ypZrcsi=qzxqJhzhg5vtjfH1 . One can use the exact same solution method I outlined in the comments to said video here : kzbin.info/www/bejne/nHyxiaR8Z9ypZrc&lc=UgyLcY43MCBsiHK3ZYF4AaABAg&si=LYPguB60eXeRYLUF (Hint : ln(-1) = i*pi )

[@Eggehman]

How about 2/2 ?

[@marzipanhoplite17]

I used the first method exactly the way you did and ended up to the same result,but we cannot write x in the form a+bi

[@HowardR911]

You asked "write x in the form a+bi". Multiply first solution numerator and denominator by (iπ - ln5) and then simplify

[@EASY_ENGINEER]

So: 2*ln(i) == i*Pi, is it correct? :)

[@57abs]

Why can't we just say it's √(-5)^2, the square root gives the two positive and negative values.

[@fewwiggle]

We can say anything -- and some of what we say may even be true . . . ;-) But, seriously, where does your answer come from? And, what is the basis for claiming there are multiple solutions?

[@pranav.r2767]

Simple but interesting

[@RealQinnMalloryu4]

(x ➖ 5x+5).

[@mathouseacademy]

⚡️😊

[@keeplearning-new]

😮

[@inraid]

Worst math channel on KZbin!

[@inraid]

verbose and meandering