Dynamics - Lesson 11: Absolute Dependent Motion of Two Particles

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University or collages are places where we learn how to learn and teach our selves, as funny as it sounds professors are not there to teach the topic but to tell its name.

[@Charles-bz8kk]

the golf ball/string with the ruler on the whiteboard is such a smart teaching tool. simple and so illustrative.

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I have been having the hardest time following along in my Dynamics class, but THIS video helped me tremendously to catch up and makes conceptualizing much easier!! Thank you SOOOOO much!

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that's because he didnt account for total length of the rope

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DR. Hanson thank you for a tremendous lecture on Absolute Dependent Motion of two Particle. I understand these problems from start to finish.

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[@AB-jj4xn]

that was so helpful! but how does this change when the masses are different for A and B?

[@MisterBinx]

I think these problems would be fun if the book could explain it better. My dynamics book gives like two simple examples and then the homework problems are a nightmare.

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[@zedspikeful]

Hi professor, in other problems ive encountered the direction of the acceleration or movement of the blocks is not stated .. how would you determine the direction of the movement of the block?

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Legend

[@jcnotnot8120]

Sir, I have a question: if the pulley B on the second example is stationary, how come the S_B varies on both sides of it? Wouldn't the length be the same regardless of the motion of the rope? Edit: Thank you for that physical example with the ball. That cleared it up for me, the pulley is not stationary and it moves with the rope.

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"You are a B because we are bad at our notation." and "Ok now its B for better" 😂

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how do you pick datum lines?

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Can I get your advice on a pulley problem ?

[@ronelordona2687]

So you should focus on the lengths of the rope rather than the direction they are moving due to the masses A and B?

[@edwardhope4166]

How does block B have a velocity if the rope connected to it does not change?

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I know you get this a lot, but thank you so much!

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hero

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Why the upper extreme right corner is blurred?? Sir

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but on the last block B is not constant because it can be moved to the left direction untill it overlaps to the pully on its left side ... but still you are cool man keep calm man i love Phy

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can you make an impulse video?

[@TheLethalknife]

At 16:16, why is the length (b-Sc) + (Sa-Sc) and not just 2(Sa-Sc)?

[@davidc2837]

someone answer this lol

[@parkerolszak1020]

It's because the length of the second rope L2 includes the rope from the right wall to the pulley labeled C and also the length of the rope that goes from pulley c to the 3m/s label (the rope with the arrowhead). (b-Sc) is the length of the first part of the rope mentioned (from wall to pulley c) and (Sa-Sc) is the length from the arrowhead to the pulley. The whole length of b goes to the wall and the length of the arrowhead to pulley c is not at the wall at this instant. Realistically there could be another datum at the right wall and you just measure the first part of the equation from that datum.

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plz do with MG instead of Va

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why l2 isn't (sA - sC) + (sA - sC)

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[@theguywiththeicebreakers4345]

This is so useful, too bad my professor actively refuses to label rope lengths and draws diagrams very poorly.

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Is dynamics this easy?

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so whats the practical application in life of all this? whats the benefit to human?????

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Thanks sir it really helped me and saved my time too.

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Im taking this class right now and the book is very difficult to understand. I teach math at a local highschool and the math in the book, they make ALOT of assumptions and its very easy to get lost haha

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[@FratricideGames]

The final solution is wrong. Va is not equal to 3 but Va-Vc =3 . Also, we should have looked for Vb/2 because B is not directly connected with rope.

[@NameSpaceVoid]

he called B and C pulleys datums in the last problem which doesn't make any sense because that would mean B and C are fixed and thus nothing would move

[@miguelmartinezmanzo4082]

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[@Backflipmarine]

Having a hard time picturing why Va = -Vb, when they are both moving in the -x direction

[@hamza_ME_]

One is moving up, one is moving down. Have nothing to do with axes.

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I didn’t watch yet but thank yoy

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distinction on the way

[@abdulsamadkholia9133]

B for the best