An Introductory Relative Motion Problem

[@FlippingPhysics]

The best way to understand relative motion is to be able to visualize it. Therefore I used a large piece of paper and a slow moving toy car to create a simple, introductory vector addition problem that we can actually see. #PhysicsED #flipclass

[@ahmed99094]

That's lots of work you're putting in. I really appreciate that, Kudos! and nice socks!

[@FlippingPhysics]

+Ahmed Ali It is all about the socks really.

[@arafe-zawad-sajid]

Hi. Can you please tell me why we used the Pythagorean theorem to solve for the velocity of the car with respect to the Earth(Vce) @3:30 instead of just doing Vce=Vcp+Vpe

[@FlippingPhysics]

Vce=Vcp+Vpe would be correct if velocity were a scalar. Because velocity is a vector, you need to do vector addition: www.flippingphysics.com/tip-to-tail-vector-addition.html

[@arafe-zawad-sajid]

thank you :D

[@DisiCoco-nm2gw]

YES I UNDESTAND finally what the velocity of the respect to the paper is 😢❤

[@Ukkaxah]

good style of teaching..

[@samisiddiqi5411]

These are genuinely fun to watch, and spare no detail.

[@FlippingPhysics]

Glad you think so!

[@Adumbb]

how do you know if it’s 58 degrees west of north or 32degrees north of west? how do we know the direction is counterclockwise?

[@FlippingPhysics]

Please watch this: www.flippingphysics.com/cardinal-directions.html

[@sjaoenvf]

6:43 question is in cm but diagram is in mm. (awesome videos BTW. I sometimes forgot billy, bobby and bo are you)

[@FlippingPhysics]

Yeah. Wish KZbin would let us upload fixed versions of videos...

[@juliojuarez2953]

i didn't understand how you turned velocities into the length of x cos=a/h when adjacent was given. We know the angles of the velocity triangle but i thought they had nothing in common with the displacement triangle

[@FlippingPhysics]

The triangle with velocities on all three sides and the triangle with displacements on all three sides are _similar triangles_.

[@juliojuarez2953]

ok so would cos(58)= (692/h) [since the got the same angles] be correct? i get 1305.

[@FlippingPhysics]

cosθ=A/H => H=A/cosθ => H=692/cos(58.478) = 1323.57 ≈ 1300 mm Yes, it's the same answer. Please don't round in the middle of a problem.

[@VeerSingh-fu9ln]

Sir can you please help out with optics.

[@sundaram58]

Thank you so much

[@anshur3021]

I can't believe that you have only this much views

[@FlippingPhysics]

me either.

[@helifynoe6956]

I prefer motion relative to space-time. Looking at motion in this way, you can use simple geometry to construct some fascinating mathematical representations of that which is the outcome of this 4D motion that takes place within the 4D space-time environment. Then, once having done that, you end up being completely surprised that you came up with the same results as did Einstein, even though you knew nothing about physics at all.

[@kimsahl8555]

Rest and motion is't about relativity (or absolute), it is just "rest" and "motion". Simple.

[@thedmitryguy]

Is there anybody here from Foxford?