How to Calculate Pressure-Volume Work

This video shows you how to calculate the work associated with a change in volume under conditions of constant pressure. Also included in this video is a brief explanation of how an automobile engine takes advantage of pressure-volume work to move a car forward.
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[@someonefrommars4173]

Thanks Ben!!! Still watching your videos OLD BUT GOLD indeed

[@BensChemVideos]

You're very welcome! Thank you for your kind words, and thanks for watching! 😀

[@marq6325]

Wow, sir, your 10 minutes video has answered my far-fetched doubt for the entire time, thank you so much sir

[@BensChemVideos]

You're very welcome! Thank you for your kind words, and thanks for watching! 😀

[@Ashtrix.1]

thank you so much you dont understand how happy you made me when you brought out a real life example

[@BensChemVideos]

You're very welcome! Thank you very much for watching 😃

[@suppachai38]

Thanks you, this help me understand pressure-volume work better because you use the example of the car engine.

[@oogalook]

Thank you much! A good, straightforward guide!

[@rafaelgalindez4606]

i know im late but youre way of teaching is very awesome . THANK YOU VERY MUCH.

[@BensChemVideos]

You're very welcome! Thank you so much for your kind words, and thanks for watching 😀

[@adityamantri8984]

Ben...Dude...Awesome!! u just made Thermodynamics fun!!!...Keep up Buddy!

[@Cowboy_Consultants]

Good explanation, if only my prof explained it and not just left us with the formula. Also, if anyone is confused about the negative sign: for chemistry we use Q-W= Ek + Ep + H but in physics we use Q+W= Ek + Ep + H

[@NOOBCRASTINATOR69]

Which grade u in?

[@alaaalnassir9704]

You're a great teacher! Thank you very much. This was pretty helpful.

[@BensChemVideos]

You're very welcome! Thank you for your kind words!

[@microwavecoffee]

was confused about the sign. thank you.

[@BensChemVideos]

You're very welcome! Thanks for watching 😀

[@sccm100]

Great video. Not really what I was looking for but still very helpful

[@user-fv1cf3de5l]

Finally!!! I am so fucking happy that I found this one. YOU LITERALLY SAVED MY LIFE

[@justinholmes7330]

Best video I found on this topic. Thank you.

[@BensChemVideos]

You're very welcome! Glad you found it helpful!

[@thingintresting5495]

This video made my day today thanku sir

[@BensChemVideos]

You're very welcome 😀

[@sportsat5776]

Sir to good explanation. Keep it up sir👍👍👍👍.

[@BensChemVideos]

Thanks so much! 😃

[@moneymafia1535]

Yaa boy keep it up

[@mysticjaarse]

Thank you very much Mr Ben now I know where the pressure-volume equation comes from!

[@BensChemVideos]

You're very welcome. Many thanks for watching! 😃

[@MercylineVugutsa-ue6yg]

Wowww. you. know. how .to. explain 😮😮😮😮😊😊😊

[@ajitamanigupta4006]

Thank you soooo much brother 👍🏻👍🏻👍🏻😊😊😊. Got this in one shot. Thanks a lottttttt💜💜

[@BensChemVideos]

You're very welcome! Many thanks for watching 😀

[@ZoloVentorio]

I learned so much from this video. Thank you sir!

[@BensChemVideos]

You're very welcome! Big thanks for watching and commenting 😀

[@sunnypoonia5230]

thanks man for dis video...it was well explained n beter understood..! good job!!

[@himshikha4232]

thank you so much .................i understood everything!

[@BensChemVideos]

You're very welcome! Thanks for watching! 😀

[@houdael4693]

So So SO So PERFECT !!! Really thank you

[@mhonnczedz1]

thanks man, found my answer

[@BensChemVideos]

Glad I could help! 😃

[@LUKASFELIXXIONG]

Very helpful. Thanks.

[@ablublubleDaSilva]

Thanks!

[@see-wee-2936]

Thank you 👍🙂

[@BensChemVideos]

You're super welcome! Many thanks for watching and commenting 😀

[@majedaljaber134]

Many thanks

[@Botiful-Chaos]

What if i used -V delta P instead, it does not make sense for me at all.

[@rileyhoffman4213]

Very useful explanation, thank you

[@BensChemVideos]

You're very welcome! Thanks for watching 😀

[@kaansaroz8086]

thank you man

[@BensChemVideos]

You're very welcome! Thanks for watching 😀

[@asdflkj2041]

Wow that was clear and interesting. Thanks a lot.

[@raplopez4258]

7:25 According to my textbook: The mechanical work done on the system is defined as w = - PV, where P is the pressure and V is the volume change and is equal to V2 - V whats goin on?

[@danib4295]

Thank You! You explained this so well. :)

[@Mr.Rayanoh]

very nice and helpful video. thanks alot

[@azleezulhelmy360]

Thankyouu bro👍🏻

[@BensChemVideos]

You're very welcome 😃

[@nasranaizi2714]

Well done!!

[@isaiahgauthier2176]

One lying crook complimenting another lying crook!!!

[@Tiger-xg6ve]

Thanks man 💯 💯 blessings on blessings

[@anilsharma-ev2my]

Please findout work done by an aneroid barometer in joules ?

[@vixenmaeve]

thanks for the Lxatm conversion, I always get stuck on that

[@martinmolina5355]

very good

[@BensChemVideos]

Thanks for your kind words, and thanks for watching!

[@kowthamrajvs3042]

can you share any links or make a video to understand physically and equation wise about NON PV WORK?

[@erikmjelde4428]

very helpful thank you very much

[@yusraimran8545]

Thanku sir very Helpful😊👍

[@nehatheturtle543]

Thanks BeN

[@suyogpatil3632]

Thank you for guidance thank you so much thank you

[@ignabaiget]

THANKS

[@BensChemVideos]

You're very welcome! Many thanks for watching 😀

[@gabicote9318]

fantastic ! such an in-depth and helpful explanation. thanks for your hard work!

[@BensChemVideos]

You're very welcome! Thank you for your kind words, and thanks for watching 😀

[@sritamabose8867]

very much helpful video

[@anilsharma-ev2my]

What is workdone by aneroid barometer in joules ???per year ?? So irs done lots of work but gonna waste ?use this power in making electricity ?

[@nivermind9936]

Great 👏👏

[@vaibhavbandal8325]

A gas has initial volume 0.2 cubic metre and temperature 290 K and pressure 1 atm. If its temperature is changed to 253 K and pressure is changed to 1.2159 atm the final volume attained is 0.1453 cubic metre . So what will be work done in expansion or PdV work? should we take P=1atm(initial)or P= 1.2159atm(final) to calculate PdV work. Please help ben. Is my question wrong?

[@alexisagagon19]

how to solve the work if the initial and final volume is given and no atm given

[@myasesaleh6241]

Did you make these new videos for quality? Just curious.

[@juanlabuschagne8845]

Champion!

[@renuarya6601]

superb

[@vaibhavbandal8325]

why 3.6 atm pressure... during expansion the pressure is going to change continuously... so is it that we have to always take the initial pressure for PdV work during expansion???

[@mohamedmomen-j5f]

Perfecto

[@vaishalirana698]

Tysm :)

[@CapsuleEducation]

sir, you discussed about workdone on compression and which W=-P∆V. But You have given a example of workdone on expansion.So, how can this possible that W=-P∆V. I think it will be W=P∆V and not the '-' sign attached to it

[@natchutarao7482]

In expansion work is negative

[@baraaali9141]

4:45 Thats what you are looking for

[@dariopl8664]

Perfect, thank you so much!

[@oscarcastanedamunoz]

what if my pressure went up when I decreased the volume? what do i plug in for the -P then?

[@ganeshmurmu2338]

Oscar Castaneda Munoz fuck off

[@pitchaiv3491]

thanks for your teaching

[@jasmin_adab]

لحضة إدراك الفيديو تم تنزيله وأنا بالثاني ابتدائي وحالياً أشاهده وأنا بالخامس إعدادي 👤💔

[@agent475816]

The pressure has to be in kPa. That way you don't convert the energy. 1J = kPa L = kPa dm^3

[@giftnwagu5185]

Why is the pressure constant

[@deepak8022]

Why pressure is constant

[@thebeatsync4328]

Class 11 😒😒😒

[@HassanAli-eu6ty]

I can not intrested your video pleas speak hindi