I'm taking a biochem class in college, I haven't learned a single thing from my lectures and you're saving me right now. I can't tell you thank you enough!
@10knovideoschallenge325 жыл бұрын
Sir ! you have an error ! you started the graph from Km ! the graph should start from 0 whatever was the type of inhibition, Km and Vmax are changing but the enzymatic reaction always start from 0. Thanks for your efforts and hardwork ❤
@Abi-jb8qt5 жыл бұрын
10k No Videos Challenge I think so there should be another line inthe graph which starts at the point 0 then goes and joins vmax line,but this line should be a little bit more curved ,so the Km will be higher and Vmax/2 will stay at the same point.(Cause vmax isnt changed)
@fatemeh42664 жыл бұрын
Yes! I wanted say that but didnt know how to explain
@litedelight73914 жыл бұрын
Yup, curve always starts from zero just area under the graph increases or decrease in each Type of inhibition.
@samianadir13563 жыл бұрын
i agree,
@eisenj211883 жыл бұрын
I read the comments before watching and now I understand what you guys meant. Thanks! still a great video!
@faizajilani9933 жыл бұрын
never seen someone explain such concept with so much clarity...like he was made for this
@sheefalydigal97532 жыл бұрын
Yo, he's a doctor though.....
@eidleabdirashiidomar94992 жыл бұрын
Yeah
@MissBenjii6 жыл бұрын
Im a student from Sweden and I can only say THANKS to you!! You've saved me!
@andreidan2878 Жыл бұрын
Question! Since the Km is the concentration where half the Vmax is reached, why do the lines for all the inhibitions START at Km? I feel like they should all start at zero and it should be the slope of the curves that pushes the Km to the left or right!
@galileerwamiye36697 ай бұрын
it might be too late to respond to your question but you're right all slopes should start a 0 because when there is no substrate there is no rate of the enzyme. It needs a substrate to operate.
@VibeMD2 жыл бұрын
I feeL the graphs are incorrect since while explaining the initial graphs you made Km the starting point, instead of it being where the axis meet
@claytonadkins230411 ай бұрын
I agree
@risconsia10 ай бұрын
initial km is for the substrate,the ones in colored ink are for inhibitors so they shift right
@bartgertsen618110 ай бұрын
@@risconsiayes but why does the graph start at the km
@pizzamargherita962810 ай бұрын
@@risconsiano, you’re incorrect. Km is the substrate concentration which will give us half of the maximum rate of reaction (velocity) for that specific enzyme. You can’t start at Km. You start at the origin, and then shift right going for your Vmax. Then you can find the new Km in that line. But you can’t use Km as the starting point. So the graph is incorrect, I think he just didn’t notice.
@drids.9 ай бұрын
@@pizzamargherita9628I agree with you mr pizza
@ammuponnu96013 жыл бұрын
Sir i have no words to thank you, sir its very easy to understand you are amizing 😇sir iam from india from kerala state, mostly i cant never understant the foregin accent bt yr language is understandable nd easly to follow, thanks for being there to help us, 🙏😇
@malinamorales65272 жыл бұрын
What impressed me the most with this entire video was how straight all the lines were.
@user-bi6yk5wg9b4 ай бұрын
😂😂
@salimsikder23646 жыл бұрын
Dude, i have a huge confusion on that point, why are you starting the graph from the increased value of Km on x axis? shouldnt the graph still start from the zero (all three case)? because Km = [S] in half Vmax, help me please!
@anonymous6726 жыл бұрын
Salim Sikder you sir are right
@hebakhalid8575 жыл бұрын
Same question 🤔🤔🤔🤔🤔🤔🤔
@hebakhalid8575 жыл бұрын
Salim Sikder same question
@MelanieGloria5 жыл бұрын
Obviously hes not so good at doing graphs.... anyway still very grateful
@nish2095 жыл бұрын
This is actually the first blatant error I’ve witnessed after watching so many of his videos
@thearchive267883 ай бұрын
Thank you, Zack! Very comprehensively explained and yet easy to understand. This channel is one of the few that makes core concepts in biochemistry easy to follow. I’m reading Devlin’s biochemistry in sync with your videos. This channel for me is not just educational or informative which of course it is. It’s the ideal that you follow in taking such care to put top notch lectures out there that keeps me coming back nearly everyday at least in recent times. I’m planning on finishing all the lectures in a few months.
@crisseltomas59362 жыл бұрын
im speechless. thank you so much for explaining everything so well
@andresruiz777625 күн бұрын
Learned more in one video than an entire semester. Preciate the awesome vids!
@imaneaya4833 Жыл бұрын
جزاك الله خير Thank you so much sir
@bodyspeakswithmusic18623 жыл бұрын
Sir if v max decreases then that red poin of y axis will b lower from the pont u mentioned
@user-hp7tw3ge7s4 ай бұрын
I don't understand😢, if the km increases which would lead to a corresponding decrease shouldn't the graph tend towards zero given that the km is negative and the decrease once in the negative becomes bigger?
@user-vm9mv7tu9i5 ай бұрын
In class I used to sit at the end and watch your lectures😂 Thanks to you❤
@Maya_AlshabkАй бұрын
you help medical students across the world :) greetings from Germany
@ranulidassanayake31713 жыл бұрын
Thanks alot.You explained everything really well.Can you please explain y Km increases/stays the same (variation of Km) depending on nature of inhibitor?
@joec31683 жыл бұрын
wow, how much the last 45 years would have been if I had you for study aide in college! relearning if so much fun !!!!
@przhadana97294 жыл бұрын
You video is very very helpfull ,thank you so much ,but i have just a small suggestion ,please after the lecture take a picture of all the board then put it here 🙏🏻🙏🏻 i want to study them😊 i hope the best for you❤
@rohamhadidchi1196 Жыл бұрын
Simply remarkable
@ssenogaJonathan10 ай бұрын
This man from another planet
@e_220_nourmuhammed5 Жыл бұрын
If we need to extract invertase enzymes in the lab from saccharomyces yeast and give the sample for 3 students A,B and C , they extract in the same way Under the same conditions and the same chemical student (A) get 3*Km ،Student (B) get 2*Km , Student (C) get 1*Km , So, who extracts the highest amount of invertase ?
@michaelmedicforreal82 жыл бұрын
I'm speaking French I'm studying in Italy and I would work with you for helping me to buying my study. I'm able to translate ours video in Italian and French language. 😊 thank you so much
@drreyes4432 Жыл бұрын
Best video ever, the only source that made me understand everything perfectly! thanks
@OluyaliSeth5 ай бұрын
quick question: on the graph drawn on the 9th minute 28 second shouldn't the graph start at the origin and cross the half Vmax dotted line at the same point and normal then not make it to Vmax ? so as to bring out the idea of no change in Km clarify on that
@Erika-ug8vm3 жыл бұрын
Shouldn't the inhibitor lines start at the origin?
@maxruphio55156 жыл бұрын
I just love your vedios, highly detailed and love it how you connect different concepts.
@Outono9376 жыл бұрын
Your classes are brilliant!!
@NinjaNerdOfficial6 жыл бұрын
+daniela andrade coelho thank you so much for your kind words I'm so happy that we were able to help!
@MaymoonahAslam8 ай бұрын
omggggggg thanku soooo muchh you're really a very good teacher it means alot to meee thanku so muchh stay blessed ..
@smit5934 Жыл бұрын
Superb! I was really struggling with this concept Now I know the key is to convert the graph into Km and Vm
@majosimpara97102 жыл бұрын
You are made for this job ! Thank you !
@muzamilnazir6244 ай бұрын
Brilliant Ninja Nerd
@nihadzerroukhat04334 жыл бұрын
You'r amazing u just made biochemistry easier for me Thanks a lot 😍💜🤗🤗🤗🤗 Looking for more
@user-ij8si3kr6b7 ай бұрын
hey, i don't know if I understand it wrong. But at 10.14 he draws the line for N.C.I. the Km stays the same, but the km is not the start of the line right? It's when it's 0.5Vmax right? Now in the graf the Km of normal and non competitieve inhibition isn't the same.
@muhindoedith54592 жыл бұрын
Thanks alot. You make everything very easy to understand
@sademthunasi775 Жыл бұрын
You just saved my life😊😊
@badhmapriyadevarajan1725 Жыл бұрын
hello nice explanations, i have doubt that why we have to plot lineweaver bruk plot while we are getting vmax and kM from micheal -menton plot
@ME-ue9ss2 жыл бұрын
hey zach thank you very much it helps me a lot i am happy to know you god bless you genious thank you very much
@malikaalibdat70792 жыл бұрын
Line weaver -Burke plot begins at 12:57 Thank me later
@ayalemfarrak769110 ай бұрын
Could you please do a video about allosteric enzymes ?🙏🏼 Thank you for your efforts 🌹
@giuliodebenedetto-qz7zj9 ай бұрын
What you don't understand about allosteric enzymes? I can explain it to you maybe
@vjhambh46913 жыл бұрын
It is really wonderful. Please make video explaining microscopy light and electron microscopy
@lilyjoyeux63925 жыл бұрын
So thanks for turning something difficult in a something easy
@thesanode52855 ай бұрын
Thank You!
@sofiiakutsenko Жыл бұрын
how did we get -1/km on x axis in lineweaver-burk?
@wabisabi4717 Жыл бұрын
Where did the -1/km come from in the 2nd graph?
@margheritagentile78466 жыл бұрын
Your lessons are amazing, a big GRAZIE from Italy
@drrahimullahkhattak53795 жыл бұрын
really nice lecture i understand throughly very nicely thankyou so much
@aswingrace698010 ай бұрын
Thank you 🙏🙏🙏🙏🙏🙏
@lucasmuss5098 Жыл бұрын
Incredible video!
@vampcreations74705 жыл бұрын
Superb sir 👌👌👌
@refad3334 жыл бұрын
very interesting and easily described lecture
@vid61493 жыл бұрын
Great work sir
@NaasiseeDaniel-ef4rh7 ай бұрын
Why is the caption is not working🤔
@jinx28732 жыл бұрын
thank you
@DreamForge95 жыл бұрын
Amazing ! Thank you so much.
@goddesssmiley43043 жыл бұрын
Thanks
@JO-2002 Жыл бұрын
BRAVO 🎉
@solomibarium324 Жыл бұрын
Thank you Sir
@niloofarkh4779 Жыл бұрын
thank u so much
@MandeepKaur-uv5tn6 жыл бұрын
Thanks once again 😊
@forever68903 жыл бұрын
really useful thanks alot legend
@user-ju5tg3wl6r7 ай бұрын
I need to send a hard question and solve it before my exam today please before 10 AM could I?
@drawwithnannu45626 жыл бұрын
Thanks again .
@kamillamiller72346 жыл бұрын
Thank you!!!
@NinjaNerdOfficial6 жыл бұрын
You’re welcome!
@moizvahora241 Жыл бұрын
Amazing
@yamifonseca29936 жыл бұрын
Great video!! i needed to slow down the video. But is because im not native english speaker.
@CORPSE774 жыл бұрын
I agree, he speaks very fast even for a native speaker. I have to pause the video a lot so I can comprehend what he says :). Keep in mind, he is speaking the language of biochemistry, which is a very dark language .. lolzz
@michaelfuxeklint49092 жыл бұрын
I've got bad news for you, we're going to spend a lot of time together the coming year 😁😁🤭
@gideonibekwute3 жыл бұрын
Thanks🙌🙌🙌🙌
@malithaniman17304 жыл бұрын
Helpe a lot..thanks
@AliAhmad-zn9vc Жыл бұрын
17:55
@03-eshanair384 жыл бұрын
The t should be written in small or big
@MatchC5 ай бұрын
The graphs seem incorrect where the lines should start at starting point. Refer to the NN notes for corrected graphs 🫰🏻
@laromkashy3136 Жыл бұрын
What about Irreversibile Inhibitors? You talked about them in the last video but never mentioned if the change and how they change the Vmax or Km. Can someone help me understand it?
@humayra4277 Жыл бұрын
Because the substrate can’t bind to the enzyme, both Vmax. The substrate being unable to bind to the enzyme means no ES complex forms (affecting Vmax); the enzyme would have a much lower affinity to the enzyme (binding to the inhibitor) and I’m pretty sure it would mean Km is higher. Higher Km = lower affinity
@humayra4277 Жыл бұрын
Vmax would be lower, I meant to say
@laromkashy3136 Жыл бұрын
So Lower Vmax and Higher Km Are you sure? Cus I have been reading and it seems to be exactly like a competitive inhibition
@humayra4277 Жыл бұрын
@@laromkashy3136 with competitive, with enough substrate you can eventually knock the inhibitor out. But because this one is irreversible, the inhibitor can’t be knocked out, and so you can’t form the ES complex
@syloh5534 Жыл бұрын
Tq
@mattulbing3 жыл бұрын
I really appreciate this channel, though I would very much like to see this video redone with the MM graph all beginning at the origin, the uncompetitive inhibitor points placed according to the direction the Km and Vmax indicates they should, and perhaps a yardstick and more space between the changes in intercepts to emphasize the change in appearance of the lineweaver-burk plot's lines. Thank you for your explanation, it just took me watching the video about 10 times to put my finger on why I felt like I was understanding it here, but there being variance from other sources.
@vudat1894 жыл бұрын
km increase but what if it in 0.001 to 0.1 ? 18:04
@haleemaazhar43933 жыл бұрын
Thanku sir
@billymeeks845 Жыл бұрын
SOLID.
@sofiasjostedt9516 Жыл бұрын
Can you describe Kcat to me?
@ChAbdurehmanGujjar5 ай бұрын
Great great🎉🎉🎉
@gypsypikis6 жыл бұрын
Thank youuuuu!!!!
@NinjaNerdOfficial6 жыл бұрын
You’re welcome!
@sarmadghafoor14844 жыл бұрын
18:05 He uses the force to lift his cam up exposed.
@junaidbhat8183 жыл бұрын
Incorrect graphical representation of enzyme inhibition. It starts from 0
@imanesaouli98803 жыл бұрын
can any one show me how we calculate enzyme activity??please!!!
@alimuddin-hf2ez3 жыл бұрын
You can use spectrophometer
@UnityAxist4 жыл бұрын
Vmax doesnt move
@Dedded4044 жыл бұрын
What about a mixed inhibitor?
@BioScienceClass4 жыл бұрын
More Videos on Lineweaver Burk plot: kzbin.info/www/bejne/rXK6inx9ibeLh6c
@medicoimperfecta Жыл бұрын
Qasam se haya jese logon ka to moh torr dene ka Dil krta ha . Mtlb Kuch bhi ? Koi ghairat, koi sharam ?😂😂
@dhritidasstudy93372 жыл бұрын
👍
@dostmehmood39863 жыл бұрын
💓
@UnityAxist4 жыл бұрын
Vmax thoes change
@simonemarciano65884 ай бұрын
i love you
@albertodanieldelapazayala66332 жыл бұрын
Algún comentario en español
@nihalihsan26886 жыл бұрын
Superr👍👍👍
@firuddinabdullayev183 жыл бұрын
👍🏼👍🏼👍🏼👍🏼👍🏼👍🏼👍🏼👍🏼👍🏼👍🏼👍🏼👍🏼.
@eveberry92154 жыл бұрын
MARRY ME
@manyworldsin13 жыл бұрын
Uggghhh! I live this guy sooo much. He explains things so well, but this video is MEGA cringe. The definition of asymptotic means the curve never reaches it. AND WORSE! He keeps starting the inhibition curve with an x-intercept at the uninhibited K(sub m) and saying the K(sub m) stays the same. That is wrong! Edit this video to fix please! Restore my faith in you as the best resource out there!