Biochemistry | Michaelis Menten & Lineweaver-Burk Plot

[@con1905]

I'm taking a biochem class in college, I haven't learned a single thing from my lectures and you're saving me right now. I can't tell you thank you enough!

[@10knovideoschallenge32]

Sir ! you have an error ! you started the graph from Km ! the graph should start from 0 whatever was the type of inhibition, Km and Vmax are changing but the enzymatic reaction always start from 0. Thanks for your efforts and hardwork ❤

[@Abi-jb8qt]

10k No Videos Challenge I think so there should be another line inthe graph which starts at the point 0 then goes and joins vmax line,but this line should be a little bit more curved ,so the Km will be higher and Vmax/2 will stay at the same point.(Cause vmax isnt changed)

[@fatemeh4266]

Yes! I wanted say that but didnt know how to explain

[@litedelight7391]

Yup, curve always starts from zero just area under the graph increases or decrease in each Type of inhibition.

[@samianadir1356]

i agree,

[@eisenj21188]

I read the comments before watching and now I understand what you guys meant. Thanks! still a great video!

[@faizajilani993]

never seen someone explain such concept with so much clarity...like he was made for this

[@sheefalydigal9753]

Yo, he's a doctor though.....

[@eidleabdirashiidomar9499]

Yeah

[@MissBenjii]

Im a student from Sweden and I can only say THANKS to you!! You've saved me!

[@andreidan2878]

Question! Since the Km is the concentration where half the Vmax is reached, why do the lines for all the inhibitions START at Km? I feel like they should all start at zero and it should be the slope of the curves that pushes the Km to the left or right!

[@galileerwamiye3669]

it might be too late to respond to your question but you're right all slopes should start a 0 because when there is no substrate there is no rate of the enzyme. It needs a substrate to operate.

[@VibeMD]

I feeL the graphs are incorrect since while explaining the initial graphs you made Km the starting point, instead of it being where the axis meet

[@claytonadkins2304]

I agree

[@risconsia]

initial km is for the substrate,the ones in colored ink are for inhibitors so they shift right

[@bartgertsen6181]

​@@risconsiayes but why does the graph start at the km

[@pizzamargherita9628]

@@risconsiano, you’re incorrect. Km is the substrate concentration which will give us half of the maximum rate of reaction (velocity) for that specific enzyme. You can’t start at Km. You start at the origin, and then shift right going for your Vmax. Then you can find the new Km in that line. But you can’t use Km as the starting point. So the graph is incorrect, I think he just didn’t notice.

[@drids.]

@@pizzamargherita9628I agree with you mr pizza

[@ammuponnu9601]

Sir i have no words to thank you, sir its very easy to understand you are amizing 😇sir iam from india from kerala state, mostly i cant never understant the foregin accent bt yr language is understandable nd easly to follow, thanks for being there to help us, 🙏😇

[@malinamorales6527]

What impressed me the most with this entire video was how straight all the lines were.

[@user-bi6yk5wg9b]

😂😂

[@salimsikder2364]

Dude, i have a huge confusion on that point, why are you starting the graph from the increased value of Km on x axis? shouldnt the graph still start from the zero (all three case)? because Km = [S] in half Vmax, help me please!

[@anonymous672]

Salim Sikder you sir are right

[@hebakhalid857]

Same question 🤔🤔🤔🤔🤔🤔🤔

[@hebakhalid857]

Salim Sikder same question

[@MelanieGloria]

Obviously hes not so good at doing graphs.... anyway still very grateful

[@nish209]

This is actually the first blatant error I’ve witnessed after watching so many of his videos

[@thearchive26788]

Thank you, Zack! Very comprehensively explained and yet easy to understand. This channel is one of the few that makes core concepts in biochemistry easy to follow. I’m reading Devlin’s biochemistry in sync with your videos. This channel for me is not just educational or informative which of course it is. It’s the ideal that you follow in taking such care to put top notch lectures out there that keeps me coming back nearly everyday at least in recent times. I’m planning on finishing all the lectures in a few months.

[@crisseltomas5936]

im speechless. thank you so much for explaining everything so well

[@andresruiz7776]

Learned more in one video than an entire semester. Preciate the awesome vids!

[@imaneaya4833]

جزاك الله خير Thank you so much sir

[@bodyspeakswithmusic1862]

Sir if v max decreases then that red poin of y axis will b lower from the pont u mentioned

[@user-hp7tw3ge7s]

I don't understand😢, if the km increases which would lead to a corresponding decrease shouldn't the graph tend towards zero given that the km is negative and the decrease once in the negative becomes bigger?

[@user-vm9mv7tu9i]

In class I used to sit at the end and watch your lectures😂 Thanks to you❤

[@Maya_Alshabk]

you help medical students across the world :) greetings from Germany

[@ranulidassanayake3171]

Thanks alot.You explained everything really well.Can you please explain y Km increases/stays the same (variation of Km) depending on nature of inhibitor?

[@joec3168]

wow, how much the last 45 years would have been if I had you for study aide in college! relearning if so much fun !!!!

[@przhadana9729]

You video is very very helpfull ,thank you so much ,but i have just a small suggestion ,please after the lecture take a picture of all the board then put it here 🙏🏻🙏🏻 i want to study them😊 i hope the best for you❤

[@rohamhadidchi1196]

Simply remarkable

[@ssenogaJonathan]

This man from another planet

[@e_220_nourmuhammed5]

If we need to extract invertase enzymes in the lab from saccharomyces yeast and give the sample for 3 students A,B and C , they extract in the same way Under the same conditions and the same chemical student (A) get 3*Km ،Student (B) get 2*Km , Student (C) get 1*Km , So, who extracts the highest amount of invertase ?

[@michaelmedicforreal8]

I'm speaking French I'm studying in Italy and I would work with you for helping me to buying my study. I'm able to translate ours video in Italian and French language. 😊 thank you so much

[@drreyes4432]

Best video ever, the only source that made me understand everything perfectly! thanks

[@OluyaliSeth]

quick question: on the graph drawn on the 9th minute 28 second shouldn't the graph start at the origin and cross the half Vmax dotted line at the same point and normal then not make it to Vmax ? so as to bring out the idea of no change in Km clarify on that

[@Erika-ug8vm]

Shouldn't the inhibitor lines start at the origin?

[@maxruphio5515]

I just love your vedios, highly detailed and love it how you connect different concepts.

[@Outono937]

Your classes are brilliant!!

[@NinjaNerdOfficial]

+daniela andrade coelho thank you so much for your kind words I'm so happy that we were able to help!

[@MaymoonahAslam]

omggggggg thanku soooo muchh you're really a very good teacher it means alot to meee thanku so muchh stay blessed ..

[@smit5934]

Superb! I was really struggling with this concept Now I know the key is to convert the graph into Km and Vm

[@majosimpara9710]

You are made for this job ! Thank you !

[@muzamilnazir624]

Brilliant Ninja Nerd

[@nihadzerroukhat0433]

You'r amazing u just made biochemistry easier for me Thanks a lot 😍💜🤗🤗🤗🤗 Looking for more

[@user-ij8si3kr6b]

hey, i don't know if I understand it wrong. But at 10.14 he draws the line for N.C.I. the Km stays the same, but the km is not the start of the line right? It's when it's 0.5Vmax right? Now in the graf the Km of normal and non competitieve inhibition isn't the same.

[@muhindoedith5459]

Thanks alot. You make everything very easy to understand

[@sademthunasi775]

You just saved my life😊😊

[@badhmapriyadevarajan1725]

hello nice explanations, i have doubt that why we have to plot lineweaver bruk plot while we are getting vmax and kM from micheal -menton plot

[@ME-ue9ss]

hey zach thank you very much it helps me a lot i am happy to know you god bless you genious thank you very much

[@malikaalibdat7079]

Line weaver -Burke plot begins at 12:57 Thank me later

[@ayalemfarrak7691]

Could you please do a video about allosteric enzymes ?🙏🏼 Thank you for your efforts 🌹

[@giuliodebenedetto-qz7zj]

What you don't understand about allosteric enzymes? I can explain it to you maybe

[@vjhambh4691]

It is really wonderful. Please make video explaining microscopy light and electron microscopy

[@lilyjoyeux6392]

So thanks for turning something difficult in a something easy

[@thesanode5285]

Thank You!

[@sofiiakutsenko]

how did we get -1/km on x axis in lineweaver-burk?

[@wabisabi4717]

Where did the -1/km come from in the 2nd graph?

[@margheritagentile7846]

Your lessons are amazing, a big GRAZIE from Italy

[@drrahimullahkhattak5379]

really nice lecture i understand throughly very nicely thankyou so much

[@aswingrace6980]

Thank you 🙏🙏🙏🙏🙏🙏

[@lucasmuss5098]

Incredible video!

[@vampcreations7470]

Superb sir 👌👌👌

[@refad333]

very interesting and easily described lecture

[@vid6149]

Great work sir

[@NaasiseeDaniel-ef4rh]

Why is the caption is not working🤔

[@jinx2873]

thank you

[@DreamForge9]

Amazing ! Thank you so much.

[@goddesssmiley4304]

Thanks

[@JO-2002]

BRAVO 🎉

[@solomibarium324]

Thank you Sir

[@niloofarkh4779]

thank u so much

[@MandeepKaur-uv5tn]

Thanks once again 😊

[@forever6890]

really useful thanks alot legend

[@user-ju5tg3wl6r]

I need to send a hard question and solve it before my exam today please before 10 AM could I?

[@drawwithnannu4562]

Thanks again .

[@kamillamiller7234]

Thank you!!!

[@NinjaNerdOfficial]

You’re welcome!

[@moizvahora241]

Amazing

[@yamifonseca2993]

Great video!! i needed to slow down the video. But is because im not native english speaker.

[@CORPSE77]

I agree, he speaks very fast even for a native speaker. I have to pause the video a lot so I can comprehend what he says :). Keep in mind, he is speaking the language of biochemistry, which is a very dark language .. lolzz

[@michaelfuxeklint4909]

I've got bad news for you, we're going to spend a lot of time together the coming year 😁😁🤭

[@gideonibekwute]

Thanks🙌🙌🙌🙌

[@malithaniman1730]

Helpe a lot..thanks

[@AliAhmad-zn9vc]

17:55

[@03-eshanair38]

The t should be written in small or big

[@MatchC]

The graphs seem incorrect where the lines should start at starting point. Refer to the NN notes for corrected graphs 🫰🏻

[@laromkashy3136]

What about Irreversibile Inhibitors? You talked about them in the last video but never mentioned if the change and how they change the Vmax or Km. Can someone help me understand it?

[@humayra4277]

Because the substrate can’t bind to the enzyme, both Vmax. The substrate being unable to bind to the enzyme means no ES complex forms (affecting Vmax); the enzyme would have a much lower affinity to the enzyme (binding to the inhibitor) and I’m pretty sure it would mean Km is higher. Higher Km = lower affinity

[@humayra4277]

Vmax would be lower, I meant to say

[@laromkashy3136]

So Lower Vmax and Higher Km Are you sure? Cus I have been reading and it seems to be exactly like a competitive inhibition

[@humayra4277]

@@laromkashy3136 with competitive, with enough substrate you can eventually knock the inhibitor out. But because this one is irreversible, the inhibitor can’t be knocked out, and so you can’t form the ES complex

[@syloh5534]

Tq

[@mattulbing]

I really appreciate this channel, though I would very much like to see this video redone with the MM graph all beginning at the origin, the uncompetitive inhibitor points placed according to the direction the Km and Vmax indicates they should, and perhaps a yardstick and more space between the changes in intercepts to emphasize the change in appearance of the lineweaver-burk plot's lines. Thank you for your explanation, it just took me watching the video about 10 times to put my finger on why I felt like I was understanding it here, but there being variance from other sources.

[@vudat189]

km increase but what if it in 0.001 to 0.1 ? 18:04

[@haleemaazhar4393]

Thanku sir

[@billymeeks845]

SOLID.

[@sofiasjostedt9516]

Can you describe Kcat to me?

[@ChAbdurehmanGujjar]

Great great🎉🎉🎉

[@gypsypikis]

Thank youuuuu!!!!

[@NinjaNerdOfficial]

You’re welcome!

[@sarmadghafoor1484]

18:05 He uses the force to lift his cam up exposed.

[@junaidbhat818]

Incorrect graphical representation of enzyme inhibition. It starts from 0

[@imanesaouli9880]

can any one show me how we calculate enzyme activity??please!!!

[@alimuddin-hf2ez]

You can use spectrophometer

[@UnityAxist]

Vmax doesnt move

[@Dedded404]

What about a mixed inhibitor?

[@BioScienceClass]

More Videos on Lineweaver Burk plot: kzbin.info/www/bejne/rXK6inx9ibeLh6c

[@medicoimperfecta]

Qasam se haya jese logon ka to moh torr dene ka Dil krta ha . Mtlb Kuch bhi ? Koi ghairat, koi sharam ?😂😂

[@dhritidasstudy9337]

👍

[@dostmehmood3986]

💓

[@UnityAxist]

Vmax thoes change

[@simonemarciano6588]

i love you

[@albertodanieldelapazayala6633]

Algún comentario en español

[@nihalihsan2688]

Superr👍👍👍

[@firuddinabdullayev18]

👍🏼👍🏼👍🏼👍🏼👍🏼👍🏼👍🏼👍🏼👍🏼👍🏼👍🏼👍🏼.

[@eveberry9215]

MARRY ME

[@manyworldsin1]

Uggghhh! I live this guy sooo much. He explains things so well, but this video is MEGA cringe. The definition of asymptotic means the curve never reaches it. AND WORSE! He keeps starting the inhibition curve with an x-intercept at the uninhibited K(sub m) and saying the K(sub m) stays the same. That is wrong! Edit this video to fix please! Restore my faith in you as the best resource out there!