Calculus Mistakes Tierlist

Рет қаралды 10,262

YangMath

Күн бұрын

Пікірлер: 31

@jeremypen7818 Күн бұрын

this is some crazy brainrot I did not expect to see while reviewing for final term exams

@KingPogPigYT Күн бұрын

The memes made it easier to understand the video. I was shocked that IShowSpeed learnt the Product rule

@secondbeamship Күн бұрын

Then there’s the “forgetting even and odd functions exist” error.

@pavlopanasiuk7297 Күн бұрын

1/(x^3+1) is very much integrable in elementary class

@riceman5174 Күн бұрын

just partial fractions into a fraction with a linear term which is easy to integrate, and an irreducible quadratic which can be integrated by splitting the fraction then completing the square

@ImmenseBRPlayer2852 Күн бұрын

elementary is a bit of an overstatement, I would say this was taught in 9th grade (Algebra 1)

@pavlopanasiuk7297 Күн бұрын

@@ImmenseBRPlayer2852 whenever this is taught, I refer to elementary functions.

@enoughboy8132 Күн бұрын

@@ImmenseBRPlayer2852 wow you were taught calculus in an algebra class im assuming in calculus you must've learned algebraic topology

@ImmenseBRPlayer2852 Күн бұрын

@enoughboy8132 i meant the math you meant to do in calculus could apply to Algebra 1 as well

@lazarussevy2777 Күн бұрын

according to Symbolab, int(1/(x^3+1))dx =\frac{1}{3}\ln \left|x+1 ight|+\frac{1}{6}\left(-\ln \left|\frac{4}{3}+\frac{4x^2-4x}{3} ight|+2\sqrt{3}\arctan \left(\frac{2x-1}{\sqrt{3}} ight) ight)+C. Whatever that means. So, there at least seems to be some answer.

@Yubin_Lee_Doramelin 23 сағат бұрын

Using Mathematica on Wolfram Alpha, the antiderivative of 1/(x^3 + 1) is calculated like below. integral 1/(x^3 + 1) dx = 1/6 (-log(x^2 - x + 1) + 2 log(x + 1) + 2 sqrt(3) tan^(-1)((2 x - 1)/sqrt(3))) + constant

@pogman4753 17 сағат бұрын

What about integrating into lnx form and forgetting the abs signs

@thlst-ly5jt 3 күн бұрын

I was shocked to see you only have 149 subs

@bdk7569 3 күн бұрын

Crazy, how did he even lost 44 subs in 3 hours

@SteelBB9 2 күн бұрын

Strange@@bdk7569

@bladerunner9531 3 күн бұрын

unbrainrotted brainrot

@Tajjwar Күн бұрын

The lopital one is so true. Good video. Hope you make more

@lazarussevy2777 Күн бұрын

Super nitpicky, but L'Hopital's Rule isn't used for indeterminate forms SUCH AS 0/0 and inf/inf. Rather, it can ONLY used with forms 0/0 and inf/inf. 0*inf for example, wouldn't work.

@mangouschase Күн бұрын

0*inf is the same as 0*1/0 => 0/0 thus you may hospital but after some juggles