Substitute b=1/3^{1/a} into the given equation and rearrange to b^2+b-30=0, which has roots b=(-1±11)/2=5 or -6. From 3^{1/a}=1/b, a=-ln3/lnb. For b=5, a=-ln3/ln5=-0.682606... b=-6 yields a complex value for a, which I'll leave as homework.
@Fariq-n2c3 күн бұрын
Make some videos from abstract algebra,matrix,hyperbolic trigonometry, inverse trigonometry, gamma,pi, digamma functions and Vieta Formula.
@اسماعیلخسروی-خ6ظ3 күн бұрын
در یک سطر قابل حل است چکار میکنی مرد❤❤😊😊
@adwoasacey23793 күн бұрын
Good
@syedmdabid71913 күн бұрын
Id est a= -- log3 basis 5,responsi.😅😅😅
@shivamjha39362 күн бұрын
But a vale is not negative bro
@leonznidarsic2 күн бұрын
Too much complication: we can easily solve the quadratic equation using the discriminant t=(-b +-square root (b^2-4ac))/2a a=30 b=-1 c=-1