Can you Solve a tricky Entrance Exam from Cambridge University ?

[@-basicmaths862]

Only multiplied x^5 both sides of equation. Then We have (2x-1)^5=0 2x-1=0, x=1/2

[@RyanLewis-Johnson-wq6xs]

16/x-8/(x^2)+4/(x^3)-2/(x^4)+1/(x^5)=32 x=1/2=0.5 x=(±1±Sqrt[3]i)/4=±0.25±0.25Sqrt[3]i It’s in my head.

[@italiouine8909]

(2x)^0=1

[@-basicmaths862]

x=1/2