Can you Solve Stanford University Admission Interview Question ?

[@vafamoshtagh5130]

Rewrite sqrt(3) - sqrt(2) as 1 / (sqrt(3) + sqrt(2)), things simplify quickly, and you get x = sqrt(3) + sqrt(2)

[@kareolaussen819]

Beautiful observation❤: x=(1+x)/(1+1/x). I have being wondering about the origin of that "magic" simplification.

[@franciscolopez9759]

It's easier & faster multiplying x^4 by x^2 by x. It's not necessary to make x^8 and divide by x

[@superacademy247]

That's a great way to simplify the equation! 🙏👍I'll make sure to explore more efficient methods like yours in my future videos! 🤩

[@alexanderten9540]

This prooves that in combination of binary and trinary roots it becomes from irrational to long-long rational record in digital memory of 1079 binary and 881 trinary roots

[@superacademy247]

Thanks for sharing your perspective 🙏💕💯🥰✅

[@davidshen5916]

A=Sqrt（3），B=Sqrt（2），A^2-1=B^2，A^2=B^2+1，X=（A+B+1）/（A-B+1）=（A+B+1）（A+B-1）/（（A-B+1）（A+B-1））=（A^2+B^2+2AB-1）/（A^2-B^2-1+2B）=（2B^2+2AB）/（2B）=B+A=Sqrt（3）+Sqrt（2）

[@GregMoress]

The first and last terms reduce to 1, and the middle term reduces to -1. -1 ** 7= -1.

[@SaagarNayak]

simple answer: no i cant

[@sametsahin2130]

(pi)^7 cevap😊

[@oahuhawaii2141]

It seems KZbin shadow bans my comments. It doesn't allow my efficient solutions to be posted.

[@superacademy247]

Really?

[@振吉黃]

步驟多了😂

[@superacademy247]

But worth the task 💪

[@와우-m1y]

asnwer=2 isit

[@와우-m1y]

asnwer=881 /3 +1079 /2 isit

[@superacademy247]

That's it!💪