Thanks for the kind words! 😊Glad you enjoyed it! 🤩
@thomasgreene57504 күн бұрын
Another, quicker way of getting to the solution is to use Euler's Identity, exp(ix)=cosx+i*sinx, to write 8i as 8*exp(i*pi/2) and k=(+/-)2sqrt(2)*exp(i*pi/4) = (+/-)2sqrt(2)*[sqrt(2)/2+i*sqrt(2)/2]. Simplifying, k = (+/-)2*(1+i).
@superacademy2474 күн бұрын
Thanks for sharing your method!That's a powerful approach. 🤩💪
@bigjazbo92174 күн бұрын
I think neither a or b can be imaginary. This is because when you equated the real and imaginary parts of k2 = 8i, with k = a + bi, you are assuming a and b to be real. If a and b are allowed to be i.aginary or complex, you cannot equate real and imaginary parts.
@sonicbreaker004 күн бұрын
you so called teachers need to learn math first before you make these videos. what takes 2 lines with polar form took you an entire notebook !
@superacademy2474 күн бұрын
I appreciate you taking the time to share your perspective. 🤩 It's a great idea to try different methods for solving problems. 💪
@sonicbreaker004 күн бұрын
@@superacademy247 what do you get out of these videos that you make ?
@superacademy2474 күн бұрын
I help thousands of learners from around the world on how to solve Math problems. I've improved Math skills 😍 of many students across the globe.💡💡💡👏👏👏
@cazacumihail36713 күн бұрын
@@superacademy247, yet a , b must be real !! Learn more about complex numbers