Canada | Maths Olympiad | Nice Algebra Problem 👇

[@Maheshkumar-cw6un]

Its very nice video to watch for complete understanding

[@manojchaugule794]

nice explaination

[@LaxmanKumar-yi4cv]

Really good 👍

[@harikishan1900]

Perfect teaching experience

[@aruntiwari5714]

It's always a pleasure to watch your video

[@arvindkulkarni6580]

Very good Maam

[@KeshavKulkarni-x1w]

😊😊

[@satyadev3848]

🤩🤩🤩🤩😍😍

[@raghvendrasingh1289]

Let x= √a+√b x^3 = a√a+b√b+ 3 a√b+3 b√a x^3 = 61+135 = 216 x= √a+√b = 6 from second equation √(ab)×6 = 45 hence √(ab) = 15/2 a+b + 2√(ab) = 36 a+b = 36 -15 = 21

[@ajitandyokothakur7191]

Unless there is a constraint, you will have three roots when you take a cube--root. You only considered the real root and ignored the other two. Think about it. Dr. Ajit Thakur (USA).

[@NithyaGhumare]

Best astrologer maam