Cavalieri's principle in 3D | Solid geometry | High school geometry | Khan Academy

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Khan Academy

Khan Academy

4 жыл бұрын

Cavalieri's principle tells us that if 2 figures have the same height and the same cross-sectional area at every point along that height, they have the same volume.
View more lessons or practice this subject at www.khanacademy.org/math/geom... .
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Пікірлер: 28
@jonathannagel7427
@jonathannagel7427 4 жыл бұрын
Interesting way to not have to use Reinmann sums & sigma notation! I’m a physical/visual learning person who probably could have told you from a young age that if you sliced a hot dog several ways, it would still displace the same amount of water... as I’m trying to teach my niece some advanced ideas in elementary ways, this is very helpful!
@activepg3d713
@activepg3d713 4 жыл бұрын
Its a real skill how he can talk and use his mouse to draw
@livethefuture2492
@livethefuture2492 3 жыл бұрын
its not a mouse, its a one of those sketch pads.
@betelgoose9712
@betelgoose9712 11 ай бұрын
Thank you so much. The way I was being taught this made it sound so complicated. This makes perfect sense.
@tejamitsrivastava7047
@tejamitsrivastava7047 4 жыл бұрын
god i am no way near the class this is for but iam still learning it in summer break
@ZennExile
@ZennExile 4 жыл бұрын
I am not coming up with a scenario where this might be useful. It feels a bit like every slice of water in bowls of identical volume will be equally wet... if that makes sense.
@joycewong4689
@joycewong4689 3 жыл бұрын
4:46 the sphere looks like an onion lol
@thattimestampguy
@thattimestampguy 4 жыл бұрын
Infinite Chocolate 🍫
@arianaazmir4321
@arianaazmir4321 8 ай бұрын
What about cylinder that is pressed at one end? Does it still have the same volume as the original cylinder?
@arianaazmir4321
@arianaazmir4321 8 ай бұрын
Will the cross sectional area be the same? Because the the circular will gradually chang to illeptical as it reach the pressed end. So can the cavalieri priciple applies to toothpaste tube shape? (Cylinder with one end pressed)
@GoatOfTheWoods
@GoatOfTheWoods 4 жыл бұрын
more polygons, though
@chunchen3450
@chunchen3450 4 жыл бұрын
Are u Zach Star😁
@himanshusharma1220
@himanshusharma1220 4 жыл бұрын
Did u saw Sushant Singh Rajput metioned you in a post before his death 😓😓😓😓😓
@muhammadhussainsarhandi9928
@muhammadhussainsarhandi9928 4 жыл бұрын
Where is that post?
@himanshusharma1220
@himanshusharma1220 4 жыл бұрын
On instagram search- Sushant singht rajput (read the cation on one of his post where he was doing coding)
@beachboardfan9544
@beachboardfan9544 4 жыл бұрын
This seems obvious, surprised theirs a principle for it
@seradfb345
@seradfb345 2 жыл бұрын
I think it seems obvious because it is displayed in such an insightful way. I came here from learning that adding a multiple of one row of a matrix does not change the determinant. It seemed quite a surprising fact to me and it made clear sense when I saw it visually. Anyway, the most beautiful maths is sometimes the simplest.
@natehaydin6423
@natehaydin6423 4 жыл бұрын
Item 1- wide top / narrow middle / wide bottom Item 2 - narrow throughout. Both have the same height. How is the volume of both items the same?
@Shibzzeg
@Shibzzeg 4 жыл бұрын
I think you're forgetting the second rule he mentioned - the cross sections at corresponding heights should have the same area. In your example - the cross sections at corresponding heights are different (and therefore, their areas are different). Imagine 2 tall stacks of CD's with the same number of disks in each of them. You could say that a single CD in the stack is a cross section of this stack. No matter how you skew any of these stacks - their volumes will be the same, because they are composed of identical cross-sections at every height and their total height is the same. Now replace one of the CD's in one of the stacks with a mini-CD. Its thickness is the same as the regular CD's, so the total stack height will remain the same, but its surface area is smaller. In this case, the volumes of two stacks will not be the same, because you replaced one of the cross sections in one of the stacks with a smaller one, so you made the stack narrower at one point (this is the same as Item 1 in your example)
@richbuilds_com
@richbuilds_com 10 ай бұрын
This doesn't hold true if you have say a pyramid and another inverted pyramid of the same volume. The tip of the first obviously has a different cross section to the base of the other. ...Unless there's addendum rules to Cavalieri's principle that state the two shapes must be in the same orientation?
@richbuilds_com
@richbuilds_com 10 ай бұрын
I'm a software developer by trade. I'm always looking for the edge cases ;-)
@Raynover
@Raynover 4 жыл бұрын
What is the software you used for the 3d objects?
@rashedulislamseum7936
@rashedulislamseum7936 4 жыл бұрын
But how could cut this kind of figure??
@Rancrom
@Rancrom 4 жыл бұрын
I can’t work the sphere out, doesn’t each cross section have to be smaller than the next? Otherwise would make a cylinder wouldn’t it? Perhaps I misunderstand that part of the principle.
@Rancrom
@Rancrom 4 жыл бұрын
Actually, I think I understand. It’s because it’s cutting at an infinitesimal point rather than a physical cut so the shape at that point should be mirrored exactly. Is that right?
@algotn
@algotn 4 жыл бұрын
@@Rancrom Yep that's right.
@downwindone
@downwindone 4 жыл бұрын
Section-n body1 == Section-n body2
@DoesMahBlockLookBig
@DoesMahBlockLookBig 4 жыл бұрын
is this somewhat similar to a Jacobian?
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