Center of Mass Physics Problems - Basic Introduction

[@TheOrganicChemistryTutor]

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[@tombrady339]

in the last problem, it depends on what reference point we are going to pick. We can use the one that our professor, The Organic Chemistry Tutor, used wherein the back of the truck is in the x=10m or we can use the other one wherein the back of the truck is in x=0m and the front of the truck is in the x=10m. In this case, the computation will be 5m= (4,000kg(6m) + 1400kg(x2))/5400kg and if we solve it algebraically, the result will be 2.14m. Why 6m? It is because based on the problem, the truck "has its center of mass 4m behind the front of the truck." If we use the reference point where the front of the truck is in x=10m, then 10m-4m is equal to 6m. Let me know if you also use this one.

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[@tatiana1310]

I dont know if someone will answer me but I could not understand why at 11:31 he use the center mass?

[@wardahdarwich3718]

he used the center of mass of the truck as x because if u want to calculate x the mass will be canceled and x is equal to the center of mass i don't know if you got it

[@Ihatelife]

I don't get it either

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Reading this 20 minutes to exam 😹

[@yan_eng8661]

wouldn't the answer to the last question be 2.14m if the truck was facing right instead of left?

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[@harshavardhanreddyy1979]

I have a doubt sir, in the last problem who have taken x1 value 4 which is center of gravity , but we should take 10 right , but why did you take 4 as x1🙂 plz give me answer sir

[@tlili3990]

he took 4 because the x values should be the centres of individual masses and the centre of mass is at 4 meters for the truck. the 10m lenght doesnt need to be in the equation, it just shows that the centre of mass will be somewhere between 0 and 10.

[@Ihatelife]

​@@tlili3990 But doesn't x need to be distance? Why would he take it as centre of mass of truck? I m confused af💀

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10:02 I kind of ''hate'' when he says this because just a moment before I was thinking ''Woah! Look at that. I could not draw it like that''.

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[@vinaybhat4330]

in the last question i dont understand why you multiply the truck weight with its centre of mass whereas in the other problems you multiplied the mass usually with the distance.Kindly guide me Thanking you in advance

[@Ihatelife]

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[@jovilynmarabe6809]

Excuse me, why that the center of mass on the 4th problem is 5? Isn't it 4?

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Sorry is the illustration of diagram compulsory ??

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[@abdulrhmanmohammed9505]

In the last problem why did he used the x1 for the truck 4 insted of zero, since the front of the car is located at position zero?

[@na-chan163]

he just arbitrarily assigned the 0 to be the front of the truck, so the cm of truck is at 4m relative to the origin zero. What the answer of 7.86m means is that the center of mass of the object weighing 1400kg must be at 7.86 m relative to the origin. This cm of the individual objects give rise to the needed 5m center of mass of the system.

[@kindcolt2747]

How come none of these adress the fact that an object has more than one “position. If it begins at 0 and is .5 meters long, is the position the avg length? (0+.5)/2=.25

[@leviticusdionysushunt7080]

yeah so most of these examples are for particles but there are some problems where the masses have more than one position. once i had a problem where 3 boxes had different lengths/masses (but same height) and i had to find their Xcms from an origin point set at the bottom left corner of the first box. Basically ycm was half the total height cause the 3 boxes all had same height, but for length it was different cause the three boxes had different lengths. box A had length 0.25 m, mass 0.8 kg box B had length 0.35 m, mass 1 kg box C had length 0.2 m, mass 0.6 kg i'm not sure if mass is relevant to your question, but you would use it to find the center of mass of the whole system. however, if we're just looking for center of mass for each box, this is how: I solved it with: X(a)cm = 0.25 m/2 = 0.125m X(b)cm = *0.25* + (0.35 m/2) = 0.425 m X(c)cm = *0.25m + 0.35 m* + (0.2m/2) = 0.7 m if we wanted to find center of mass for the whole 3-box system: xcm = (0.8kg * 0.125m) + (1 kg * 0.425m) + (0.6kg * 0.7 m) DIVIDED BY (0.8 kg + 1 kg + 0.6 kg) then we get the answer, the center of mass of the system is 0.394m. hopefully this answers your question!

[@thsbig741]

Why you choose 5m is a center of mass in article 4.

[@Brandon-lx3mf]

because the question asks for it to be moved to the middle, and the middle of a 10m truck is 5m

[@muhibbul7255]

did we assume that the weight of only the front of the truck to be 4000 and not the whole truck?......

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Hey but does anyone know where I can get detailed notes on the topic

[@ziyustalkies1003]

thank u😊

[@faisalmohamed4595]

How did we get the 5 at the last question and why is it xcm=5

[@nkosingiphilenene2237]

How did you got 5m as center of mass?

[@maryamibrahim8283]

Because in the question they said the center of mass will be right in the middle of the truck and the truck is 10m long so the middle of the truck is 5

[@faisalmohamed4595]

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[@joshuaantony9716]

error in calculation in last question 27000/16000|=11000

[@saorisaori3467]

Is this a Integral formula? Can anyone answer my question please??? Thank you in advanced :)

[@JonathanL_]

Maybe

[@ChisomEluchie.]

If only he could reply comments😢

[@krissandrew4524]

Wat..I..dnt.. undstnd..is How..d..5..came..2..b Did..we.. assume..it.? Also..my.. weakness..is.. trying..2 Interpret..a... question..it.. really Killing..me

[@herondalecarstairs1480]

dude i cant understand your doubt..in case its the last qn,then its bcz its said that Centre of mass is in themiddle of the truck meaning 10/2=5..its middle

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The basic idea is not well understood

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