that explanation about oxidation state was superb. i finally understand it. thanks so much. congrats for 100K subscribers!
@ChadsPrep8 ай бұрын
Thank you so much 😀
@narutozzz61662 жыл бұрын
Being a dyslexic, these videos have been a game changer for me- thanks Chad!
@ChadsPrep2 жыл бұрын
Glad they've helped!
@kcanduoc4 жыл бұрын
Thanks Chad!
@ChadsPrep4 жыл бұрын
You're very welcome!😊
@leonajagiello1174 жыл бұрын
All your videos are extremely helpful, thank you!!!!
@ChadsPrep4 жыл бұрын
Glad you like them, Leona - Happy learning!
@loghlogh2480Ай бұрын
i love you so much mr. chad. i hope gonna take AA
@ChadsPrepАй бұрын
Happy Studying!
@BruceWayne-i2n Жыл бұрын
hey thanks for the vid, excellent stuff. just a quick question. the vid said the diff in EN between Al and H is higher than for B and H, making it's Hydrogen more partially negative (at about 18:00 min in the video). I looked at a ptable and saw Boron has an EN of 2 while Al has an EN of 1.61, so Im a bit confused. Should I just ignore the ptable in this specific case?
@ChadsPrep Жыл бұрын
It wasn't the absolute value of the electronegativity we were looking at, but the difference in electronegativity. For 2 atoms bonded together, the larger the difference in electronegativity, the more polar the bond. Hydrogen has a value of 2.1 (2.2 in some sources). Using your values that would result in an electronegativity difference of 0.1 for the B-H bond and ~0.5 for the Al-H bond. The bigger difference in electronegativity between Al and H indicates a more polar bond (or we could say more ionic character) which is ultimately what I used in the video to explain why it was more reactive. Hope this helps!
@BruceWayne-i2n Жыл бұрын
ohhhh I gotcha. yep that nails it, I was thinking just magnitudes. great stuff, great vids, I've been going through all of them the past 2 weeks and liking them all. have a great night :D
@faridapeimanzadeh6172 жыл бұрын
Thank you for teaching so complete and great 😍😍
@ChadsPrep2 жыл бұрын
Glad you found this so helpful :)
@abdoulazizdabo9064 Жыл бұрын
Thank you 🙏🏾
@ChadsPrep Жыл бұрын
Most welcome
@jaydenallegakoen99742 жыл бұрын
AMAZING VIDEO!!!!
@ChadsPrep2 жыл бұрын
Thank you!
@gabvau878 ай бұрын
Thank you Chad
@ChadsPrep8 ай бұрын
Very welcome
@bonbonpony2 жыл бұрын
06:52 Is there a way to selectively reduce just the ketone, but not the aldehyde, or vice versa?
@siddharthpatel40642 жыл бұрын
At the 4:40 mark, you went over the OsO4 in review of the alcohol synthesis reactions. You also used NaHSO3. Instead of using NaHSO3, would it also be possible to use H2O2?
@ChadsPrep2 жыл бұрын
Absolutely Siddharth! You'll commonly see NaHSO3, Na2SO3, or H2O2 all used after OsO4 in the second step of syn-dihydroxylation.
@noorfatimanoorfatima39713 жыл бұрын
Really helpful!
@ChadsPrep3 жыл бұрын
Great!
@danielnestler58502 жыл бұрын
Nice, especially the bigger picture
@ChadsPrep2 жыл бұрын
Glad to hear it, Daniel - Happy Studying!
@laura58782 жыл бұрын
Chad, I bet you thought you saw the last of me. I made it to ochem 2
@ChadsPrep2 жыл бұрын
Ha! All the best!
@tilawatkhan9173 Жыл бұрын
Please reduce your speed of teaching and add some more informations about the catalysts and their names.
@kiulogakenia2 ай бұрын
Watching this in 2024 December ❤
@ChadsPrep2 ай бұрын
Happy Studying!
@hiyaaieh2 жыл бұрын
I learned so much more than I had hoped. Thank you, king 🙌