Chapter:10 Ex.10.2 (Q.9) Circles | Ncert Maths Class 10 | Cbse.

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Ye or bhi jyada easy ho skta h agr angles ko 1,2,3,4 ko centre pr likh diya jaye to fir cpct se 1=2 and 3=4 ho jayega or inko add krenge to L.P.A se sum 180 ho jayega or fir vo angles to equal h to 2 common aayega or 180/2 ho ho jayega and angle 2+3 =90 means angle AOB =90 ho jayega hence proved

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Sir is this triangle able to prove congurent with RHS rule?

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Sir but if we join oc, wont acc. To theorem 10.2 angle oca and angle ocb will be 90?

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Sir, can we prove these two triangles in the above question as congruent by RHS also ?

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No

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Sir, just a suggestion. Instead of writing angles on the same side each and every time, you can just write (co-interior angles)

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