COA | DPP: Instruction Pipeline | Lec 44 | GATE CSE 2021/22 Exam

[@dhruvikharadi3704]

your lectures are great sir, thank you

[@AS-we3zt]

Great sir .. all my doubts are covered in this vedio ...

[@allunique9171]

GPK Q1 CPI = 1.8 ; AVG instn exe time = 27 ns ; Speed up = 2.37

[@divyanshusingh6105]

GPK 2:42 cycles 2*(7+14)

[@nayansawarkar4471]

Really very very nice explanation of each and every topic...

[@madhursharma1441]

Thankyou so much Sir, for your great explanation and deep concept lectures. I am lucky to have great learning from your lectures. Long Live Happy Learning.

[@knowledgeexchange428]

42:20 question 2, isnt pipeline cycle time and cpu cycle time different?? we calculated cpu cycles per instruction(CPI) as 1.4. but we are multiplying it with pipeline cycle time(tp)?

[@iarpyrkhatwanlah]

1.6,24ns,2.6

[@sancharisaha5345]

Sir, @54:24, The table of question no 2 & in the same question @54:26 the table which is the corner of the right side .... how is that same table different? .... please sir clarify this doubt. Thank u, Sir.

[@namandhanotia1188]

That is printing error, focus on concept not the values.

[@darshantechful]

start at 07:40

[@criticalcommunist5]

Arre bhai time bacha diya 🙏🙏🙏🙏

[@dhruvinmodi7060]

GPKQ1 CPI=1.8, Average inst. execution time = 27 ns, speedup = 2.37037

[@saksham3002]

my speedup came to be S=2

[@Vaishnavi-nf8gh]

I got CPI = 1.6, can you please explain how 1.8?

[@SastaTrader]

Yes 1.8, 27 & 2.37

[@SastaTrader]

@@Vaishnavi-nf8gh No. Of stalls for each will be 4 here (5-1) and .2 * 4 is .8 so cpi will be 1 + .8 = 1.8

[@Vaishnavi-nf8gh]

@@SastaTrader thanks

[@abhishekghosh1998]

Very nice lecture...

[@divyanshusingh6105]

GPK - CPI=1.8 AMAT=27ns S=2.37

[@garrysacademy2122]

Great

[@mansibarot8679]

What is cpu of pipeline in gpk q?

[@farjanashaik9601]

It's cpi,may be it's typo mistake

[@nirmalaryal6446]

I got confuse when it comes to decide whether to use Idle case or normal one ....

[@udatyadeb101]

From what I have learned till now, use the Ideal case if no. of instuctions is given, or else use the ideal case.

[@adityachauhan5913]

1.8, 27ns, 2.37 speedup

[@mozart8782]

GPK ): 1.8,27nsec,2.3707

[@divyanshachaudhary1460]

How we calculating no of stalls

[@swaroop633]

@@divyanshachaudhary1460 1+0.2*(5-1)

[@criticalcommunist5]

@@divyanshachaudhary1460 actually, after complete execution of instruction next instructions is starting execution , that means all 5 stage execution with , then new execution starts with same cycle of completed execution so 4 stall cycles.

[@augustinradjou3909]

Thank you so much❤​@@criticalcommunist5