Complex Analysis 08: Using anti-derivatives

Contour integration with anti-derivatives. Three examples

[@leahstella785]

So happy that this video series has been posted, the teaching in my university is substandard at best, so you have saved me!

[@etlekmek]

kesin öyledir he he

[@GoogleUser-ee8ro]

these videos come in handy because i am learning CIF and residual theorem right now

[@Marawan]

6:05 Did he say inshallah?

[@manueljenkin95]

Thank you very much sir!

[@macmos1]

in this case, the interval of principle argument is from -pi/2 to pi/2?

[@1112634]

Why we didn't use 7pi/4 as the argument of 2-2i in the last example?

[@mostafaesalamony6836]

how did he find the arguments in the last example?

[@Mattdbr]

Just by inspection - you know 1 + i is in the first quadrant with an argument of pi/4, 2 + 2i has the same argument and so is pi/4. I mean you could just do inverse tan(1/1) otherwise.

[@jamesbyrd405]

Thank you

[@Mojito99]

I thought Log(z^2 + 2) is not analytic if z^2 + 2 is non positive and real why are we then talking about the imaginary axis ?

[@perchanceyes4786]

+Nick R Because z^2 + 2 = x^2 + 2ixy - y^2 +2 which is only non-positive and real when x=0 and y>=sqrt(2) and that lies on the imaginary axis.

[@AnkitVishway]

Just a rearrangement of words +Nick R Because z^2 + 2 = x^2 + 2ixy - y^2 +2 which is non-positive and real only when x=0 and y>=sqrt(2) and that lies on the imaginary axis.