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Compound manometer example problem

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Engineer4Free

Engineer4Free

Күн бұрын

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Fluid Mechanics Tutorial: Compound manometer example problem.
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Пікірлер: 192
@harvinderpal4662
@harvinderpal4662 3 жыл бұрын
7 years on and this video hasn’t lost its relevance...very well explained, thank you so much👍
@robbiegolds1234
@robbiegolds1234 5 жыл бұрын
Don't apologize for redundancy. This was perfect. Perfect reps = Perfect steps.
@Engineer4Free
@Engineer4Free 5 жыл бұрын
Thanks Robb =)
@EE-pq8yn
@EE-pq8yn 6 жыл бұрын
I just waned to take a minute to thank you for teaching me your way.same exact problem i got on my test and your explanition was golden! fluid mechanics could be a big tricky game but you made it easy to digest! Please make more videos on more topics in fluid mechanics. Thanks!
@Engineer4Free
@Engineer4Free 6 жыл бұрын
Thanks for letting me know, really glad to hear this helped!! I do plan on getting more fluids videos out later this year :)
@a.h8606
@a.h8606 Жыл бұрын
This concept is the one thing I fail to remember everytime i prep for exams and each time this video delivers. Thanks man.
@humaidalkhateri3095
@humaidalkhateri3095 9 жыл бұрын
I HAVE BEEN IN REAL STRUGGLE with the plus or mins sign . I have a midterm tomorrow in fluid mech. and this's been a great help!!
@Engineer4Free
@Engineer4Free 9 жыл бұрын
+humaid alkhateri Awesome glad to hear it, those +/- signs can be tricky!
@darkforestf
@darkforestf 6 жыл бұрын
Thank you so much! This vid has divided all parts of the eqn for a better understanding unlike the textbook always come up with a compound eqn
@Engineer4Free
@Engineer4Free 6 жыл бұрын
Hey You're welcome! I try to keep the method as transparent as possible. Breaking it into part by part seems to be the best way to not get confused! =)
@lisagarrett3069
@lisagarrett3069 5 жыл бұрын
Thank you for the video! No need to say sorry for the repetition. I actually didn't catch the reasoning the first time, so the second time made it click and the third time solidified the knowledge. :) Great video!
@Engineer4Free
@Engineer4Free 5 жыл бұрын
Hey awesome, glad that it finally clicked for you =) =)
@Akki420ish
@Akki420ish 7 жыл бұрын
This video is gold. Cleared my concept after 4 years. Thanks a ton! One thing l'd like to ask: The pressure you took at P1 = P(atm) is a gauge pressure or absolute pressure? I have seen in some books that P(atm) is taken zero sometimes. Can you explain?
@fareedhaddad8240
@fareedhaddad8240 7 жыл бұрын
abs .. i think coz its open
@Engineer4Free
@Engineer4Free 7 жыл бұрын
Yeah this whole video is done in absolute pressure. If you define Patm = 0 then take the difference between any P and Patm and you will have the gauge pressure instead (actually in this video, P2,P3,P4 will all be vacuum). This is a good video on the difference between absolute, gauge, and vacuum pressure: kzbin.info/www/bejne/pYCwq4WwpbN1e6c
@wafa98_67
@wafa98_67 7 жыл бұрын
from what i have learnt , it is absolute
@exogendesign4582
@exogendesign4582 7 жыл бұрын
this helps me a lot, I was trying to figure it out on my own, and had the signs flip out coz I didn't consider the action of the fluid after watching this video it cleared me up, thanks for this man.
@Engineer4Free
@Engineer4Free 7 жыл бұрын
Thanks for letting me know that! Glad the videos are helping! :)
@RikkuCloud
@RikkuCloud 8 жыл бұрын
Thank you sir, had some problem getting over the "unsidedown oil" part in a exercise problem I've been having, but when you said "as you go down deeper into the fluid P3 is going to be greater than P2" then my mind finally got it hahaa, thanks.
@Engineer4Free
@Engineer4Free 8 жыл бұрын
+RikkuCloud sometimes you just need to hear things said in a slightly different way. Glad it helped and thanks for commenting!
@shensley011
@shensley011 4 жыл бұрын
Always be redundant! Thanks for the help (again) you're a true gem. Question, what is it wasn't open to the atmosphere and was just a fluid?
@oharahetuka3252
@oharahetuka3252 5 жыл бұрын
Thank you Sir. Your explanation on why we should add or subtract "ρgh" helped me. I always stumbled when figuring this out. Thanks a lot again!
@Engineer4Free
@Engineer4Free 5 жыл бұрын
Awesome! Glad to hear it :D
@user-if7vh9tp9v
@user-if7vh9tp9v 7 ай бұрын
this was very useful thank you!!
@Engineer4Free
@Engineer4Free 6 ай бұрын
Glad it was helpful, thanks for watching! 😁
@tombuxton6774
@tombuxton6774 Жыл бұрын
This man is singlehandedly saving my degree at the moment.... I could kiss you
@Engineer4Free
@Engineer4Free Жыл бұрын
I gochu 🤜🤛
@nicoleng4181
@nicoleng4181 3 жыл бұрын
is the final answer gauge pressure or absolute pressure ?
@Engineer4Free
@Engineer4Free 3 жыл бұрын
The 81 kPa is absolute pressure
@nchls5730
@nchls5730 Жыл бұрын
Thank you so much for this video. This helps me prepare my fluid mechanics exam. Subscribed! :)
@wafa98_67
@wafa98_67 7 жыл бұрын
thank you so much! i watched many vids and none could help! but u explained it so simply! =)
@Engineer4Free
@Engineer4Free 6 жыл бұрын
Thanks for the feedback!
@PoproqzSwag
@PoproqzSwag 6 жыл бұрын
Thank you. I was struggling with simple concepts and my teacher would not explain it thoroughly.
@Engineer4Free
@Engineer4Free 6 жыл бұрын
Awesome glad to help. I only have a few videos about fluids right now, but the whole playlist is here if you are looking for it: kzbin.info/aero/PLOAuB8dR35oeOIPMOBH6hjwobuIJHPKSN
@Freakybananayo
@Freakybananayo 4 жыл бұрын
great video. i have a question though, see how the gas inside the bulb is higher up than point 4 wouldn't there be a difference in pressure? thanks.
@adaugoukaegbu4934
@adaugoukaegbu4934 4 жыл бұрын
I was thinking thins as well. There should be an extra pho*g*h for that pressure difference because pgas is higher
@Engineer4Free
@Engineer4Free 4 жыл бұрын
Because it’s a gas and not a liquid, you can ignore that height. Change in “depth” of gas is minuscule compared to that of liquid.
@Engineer4Free
@Engineer4Free 4 жыл бұрын
Because it’s a gas and not a liquid, you can ignore that height. Change in “depth” of gas is minuscule compared to that of liquid.
@Freakybananayo
@Freakybananayo 4 жыл бұрын
@@Engineer4Free good to know. Cheers
@andyzh2950
@andyzh2950 4 жыл бұрын
I'm SO GRATEFUL for your explanation, I finally understand when to use + or - in that equation, subscribed.
@Engineer4Free
@Engineer4Free 4 жыл бұрын
Yasssss mission accomplished 🤜🤛
@redalert1730
@redalert1730 7 жыл бұрын
thank you so much... i finally understand the measurement and depth in pressure.. hoping you will upload hydrostatic ,boyles law, buoyancy. orifice, and bernoullis theorem thank you soo muchhh
@Engineer4Free
@Engineer4Free 7 жыл бұрын
I will get to them one day!
@AnilKumar-yv4iu
@AnilKumar-yv4iu 4 жыл бұрын
I think P1=0 as gauge pressure in atmosphere is zero. In the manometer we are actually measuring gauge pressure.
@Engineer4Free
@Engineer4Free 3 жыл бұрын
Yes, P1 would be zero if we consider atmospheric pressure to be 0, which is the norm. This example was done in the frame of absolute pressure though, not gauge pressure. Pgas in this case would be -20kPa gauge (or also you could say 20 kPa vacuum. Either way, Pgas is 81 kPa absolute, which is 20kPa less that the surrounding atmospheric pressure.
@kiriyamarei7358
@kiriyamarei7358 5 жыл бұрын
You are a life saver
@Engineer4Free
@Engineer4Free 5 жыл бұрын
=) =) glad I can help
@sreejithp2740
@sreejithp2740 7 жыл бұрын
fantastic work...cleared the concept..tnku so much
@Engineer4Free
@Engineer4Free 6 жыл бұрын
Glad to hear it :)
@junior214223
@junior214223 5 жыл бұрын
Do you have any videos dealing with pumps and the pressure at those pumps?
@Engineer4Free
@Engineer4Free 5 жыл бұрын
Hey sorry not yet, but hopefully one day!
@found2273
@found2273 2 жыл бұрын
Thanks sir / bro from India
@omarahmed621
@omarahmed621 3 жыл бұрын
What a legend, Thank you so much
@Engineer4Free
@Engineer4Free 3 жыл бұрын
Thanks!!
@jameslondon05
@jameslondon05 7 жыл бұрын
13,580 * 9.81 * 0.15 =/= 19995 as you suggest in your first calculation. it is 19982.97, thus your final answer is a little off. great work through and still useful.
@comfortmankge7035
@comfortmankge7035 8 жыл бұрын
THANKS SIR IT WAS REALLY HELPFUL.......
@jallmo
@jallmo Жыл бұрын
Thank you so much you saved me (:
@iValkyrie46
@iValkyrie46 5 жыл бұрын
thanks sir. this really helps me
@Engineer4Free
@Engineer4Free 4 жыл бұрын
Great, glad to hear it!!
@cqaaliqcismaancllahi1487
@cqaaliqcismaancllahi1487 4 жыл бұрын
Thank you
@Engineer4Free
@Engineer4Free 4 жыл бұрын
You're welcome!
@naq8405
@naq8405 5 жыл бұрын
Hi, I'm confused as to which liquid density im supposed to choose everytime i calculate the pressure.
@Engineer4Free
@Engineer4Free 5 жыл бұрын
You always want to calculate the difference in pressure between two different points in the same fluid. Typically, with a compound manometer problem like this, you want to find the difference between the high boundary and low boundary of each fluid. When doing that, use the density of the fluid that you are considering the top and bottom boundaries of.
@naq8405
@naq8405 5 жыл бұрын
@@Engineer4Free thx!
@drcommondrate12
@drcommondrate12 4 жыл бұрын
You need to consider all of the liquids/gases including the Atm. Press. My technique is just look for the first end of the gas/liquid and determine if the other end is above (negative) or below (positive).
@mvsaditya308
@mvsaditya308 4 жыл бұрын
Thank you sir
@Engineer4Free
@Engineer4Free 4 жыл бұрын
You're welcome 😁
@piratenu1
@piratenu1 9 жыл бұрын
thanks a lot dude. Today Im taking an exam and was confused with a question of this type. Your video was much helpful to solve it. :)
@angelamargaritagallegomedr4274
@angelamargaritagallegomedr4274 3 жыл бұрын
so helpful, thank you!
@Engineer4Free
@Engineer4Free 3 жыл бұрын
Glad it was helpful!!
@danielgross8948
@danielgross8948 4 жыл бұрын
Great video man!
@Engineer4Free
@Engineer4Free 4 жыл бұрын
Thanks!! 😊
@qsdfcvgyjmkl
@qsdfcvgyjmkl 7 жыл бұрын
Thank you for this video. It really made the explanation much easier to understand! Please continue your wonderful work!
@Toptop06
@Toptop06 3 жыл бұрын
Very helpful! Thank you ❤️
@Engineer4Free
@Engineer4Free 3 жыл бұрын
You're welcome! =)
@tbarak.shakir.b5003
@tbarak.shakir.b5003 3 жыл бұрын
You r amazing thank you so much 🤩❤❤
@Engineer4Free
@Engineer4Free 3 жыл бұрын
You’re welcome 😊!!
@usmanshahid1913
@usmanshahid1913 5 жыл бұрын
Thanks man for the video!
@Engineer4Free
@Engineer4Free 5 жыл бұрын
Hey you're welcome Usman!
@teshd7108
@teshd7108 7 жыл бұрын
Very clear video, thanks!
@hijxckk
@hijxckk Жыл бұрын
Hi I was just curious how pressure would be impacted if we had air in the tube in-between p2 and p3 instead of another fluid
@Orleezinc
@Orleezinc Жыл бұрын
As the density of air is negligible compared to the densities of mercury and water, point 2 and point 3 would have the same pressure
@hijxckk
@hijxckk Жыл бұрын
@@Orleezinc ok ok, that's what I thought, thanks for the reply!
@sphanie
@sphanie 3 жыл бұрын
Hi, is the pressure inside the tank the gauge pressure or the absolute pressure? I really hope you answer this🥺
@Engineer4Free
@Engineer4Free 3 жыл бұрын
Hey, it's 81kPa absolute, or -20kPa gauge
@sphanie
@sphanie 3 жыл бұрын
@@Engineer4Free omg thanks for replying but how do you calculate that?
@Engineer4Free
@Engineer4Free 3 жыл бұрын
Sorry I wrote that above reply wrong. Should be "-20 kPa gauge". Atmospheric pressure is given as Patm = 101kPa. Gauge pressure is how much pressure we are above reference (atmospheric) pressure. So Patm 101kPa Absolute = 0 kPa Gauge, because it's 0 kPa different from its self. 81 is 20 less than 101, so we are 20Kpa less than the reference, or - 20kPa gauge. Sometime you refer to negative gauge pressure as vacuum. So we could say "-20 kPa gauge" or "20 kPa vacuum" or just "81kPa absolute". Watch this video too: kzbin.info/www/bejne/pYCwq4WwpbN1e6c
@sphanie
@sphanie 3 жыл бұрын
@@Engineer4Free ahh yes okay that makes sense. Thank you!
@gelomelo3426
@gelomelo3426 2 жыл бұрын
Thank you so much🌹🌹🌹❤❤❤
@ridzwnrshid
@ridzwnrshid 3 жыл бұрын
thank you very much
@rko9887
@rko9887 9 жыл бұрын
Thanks!!!! Really helped a lot,... Although u need to chk ur calculation otherwise ok....
@Engineer4Free
@Engineer4Free 9 жыл бұрын
Glad it helps, I noticed after the fact that I got a little lazy with saying/writing kPa vs Pa, but hopefully the little text box that pops up clears things up!
@Gartaxo42
@Gartaxo42 Жыл бұрын
helped me out fr fr. bless you
@dfunctual5
@dfunctual5 9 жыл бұрын
Thanks for sharing. Shouldn't the equation to find P4 incorporate a height of 0.1m instead of 0.2m? As it's drawn 0.2m is the distance from point 3 to 4.
@Engineer4Free
@Engineer4Free 9 жыл бұрын
Daniel Lovik Hey where are you getting 0.1 from? We want need to use the vertical distance between 3 and 4 to find the pressure at point 4. The difference in pressure between any two points in a continuous body of a single fluid is ρgh where h is the difference in elevation between those points. Points 3 and 4 are both touching the same continuous body of water and are separated vertically by 0.2m. The shape of the body of water has nothing to do with the pressure as long as it's continuous. Once you know the pressure at the boundary between the oil and the water (point 3) write it down, then forget all about the oil and just consider the heights of the two ends of the water. This was the same logic used to find P2 and P3. Let me know if that helps or if you're still confused about it!
@dfunctual5
@dfunctual5 9 жыл бұрын
Engineer4Free Ya, still somewhat confused. I miswrote the last sentence in my previous comment meaning 0.1 not 0.2. As far as I can see the vertical distance from point three to point four is 10cm or 0.1m. Perhaps I just read it wrong and the distance between 3 and 4 is supposed to be 20cm not 10cm? Hopefully that's the case. Thanks
@josiah8006
@josiah8006 5 жыл бұрын
Hiii i have a question, if the pressure at a certain point is lower than the current then does it have to be positive? I mean add
@Engineer4Free
@Engineer4Free 5 жыл бұрын
We consider pressure to increase in the positive direction when we move down through a fluid.
@alexwalton2132
@alexwalton2132 4 жыл бұрын
thanks sir, very helpful, much love
@Engineer4Free
@Engineer4Free 4 жыл бұрын
Thanks for watching 🙂
@jacobstahlmann6958
@jacobstahlmann6958 4 жыл бұрын
How can the two P1s have the same pressure if they have different fluids above them
@alhassanjd6670
@alhassanjd6670 5 жыл бұрын
Thank you so much ..
@Engineer4Free
@Engineer4Free 5 жыл бұрын
You're welcome Hassan!!
@muhittinselcukgoksu1327
@muhittinselcukgoksu1327 8 жыл бұрын
Thank you soooo much .Your explanations and drawings were wonderful, regards.
@Engineer4Free
@Engineer4Free 8 жыл бұрын
Thanks for the kind words!
@Lykenyte
@Lykenyte 5 жыл бұрын
Hello, I would just like to know if the final answer of the gas were in gage pressure, would the answer be P4 - Patm? Thank you!
@Engineer4Free
@Engineer4Free 5 жыл бұрын
Yes, and in this case 81 - 101 = -20 . A negative guage pressure is referred to as vacuum. -20 kPa guage = 20 kPa vacuum.
@zaazazza6555
@zaazazza6555 5 жыл бұрын
Thanks!
@Engineer4Free
@Engineer4Free 5 жыл бұрын
You're welcome!
@kustupsk1
@kustupsk1 8 жыл бұрын
Thank you for your hard work!
@Engineer4Free
@Engineer4Free 8 жыл бұрын
Your welcome :) thanks for watching!
@yiiyatschan1395
@yiiyatschan1395 5 жыл бұрын
Thank you for this video.
@Diya.Dasari
@Diya.Dasari 10 ай бұрын
THANK YOU......
@CBFD667
@CBFD667 4 жыл бұрын
awesome, definitely helped me out
@anilsharma-ev2my
@anilsharma-ev2my 4 жыл бұрын
Work done by an aneroid barometer in joules. ? Please show actual data in energy terms ?
@worldpark90
@worldpark90 5 жыл бұрын
Many Thanks !!!
@Engineer4Free
@Engineer4Free 5 жыл бұрын
You're welcome =) =)
@helper2004
@helper2004 Жыл бұрын
Thanks
@Engineer4Free
@Engineer4Free Жыл бұрын
Welcome ☺️
@knowledgezone8748
@knowledgezone8748 6 жыл бұрын
great work
@Engineer4Free
@Engineer4Free 6 жыл бұрын
Thanks!
@forrrest6609
@forrrest6609 2 жыл бұрын
​ @Engineer4Free Help! How is p3 less than p1?? I'm really confused?
@Engineer4Free
@Engineer4Free 2 жыл бұрын
Yo, check out videos 6 - 10 here: Fluid Mechanics: kzbin.info/aero/PLOAuB8dR35oeOIPMOBH6hjwobuIJHPKSN they will clear your doubts with some easier examples 👌👌
@narunstorm
@narunstorm 10 ай бұрын
❤thank you❤
@diegofung95
@diegofung95 9 жыл бұрын
Thanks for posting this!
@namnguy5024
@namnguy5024 9 жыл бұрын
very helpful. thank you
@Engineer4Free
@Engineer4Free 9 жыл бұрын
+Kevin Nguy Glad to hear it, thanks for reaching out!
@Aprst25
@Aprst25 7 жыл бұрын
Why is specific gravity of oil being multiplied with the density of water
@jameslondon05
@jameslondon05 7 жыл бұрын
SG is density relative to water (if liquid) or relative to atm if a gas, density of H2O at 20deg is 998, so it's 0.8*998 to give actual density.
@exogendesign4582
@exogendesign4582 7 жыл бұрын
because it is relative , Specific gravity = Specific weight of oil/ specific weight of water and since density =specific weight /gravity density then is specific gravity multiplied to the density of the water.
@GoatedMofo
@GoatedMofo 5 жыл бұрын
THANK YOUUU
@Engineer4Free
@Engineer4Free 5 жыл бұрын
YOU'RE WELCOMEEE
@popedope4842
@popedope4842 8 жыл бұрын
Great work man!
@Engineer4Free
@Engineer4Free 8 жыл бұрын
Hey thanks! Appreciate the feedback :)
@montana4able
@montana4able 7 жыл бұрын
great video .. great man .. thx!!
@shamitfatin3516
@shamitfatin3516 5 жыл бұрын
Thanks!!!!!!
@Engineer4Free
@Engineer4Free 5 жыл бұрын
You're welcome!!!
@lilonarry9693
@lilonarry9693 7 жыл бұрын
THANK YOU THANK YOUUU THANK YOUU ALL THE LOVE XXXXXX
@Engineer4Free
@Engineer4Free 7 жыл бұрын
hahaha you're welcome :). Thanks for watching and sending the love!!
@baderk326
@baderk326 7 жыл бұрын
i think p1 = p(atm)+pgH cuz the pressure that applied via p(atm) is higher than the oil
@Engineer4Free
@Engineer4Free 7 жыл бұрын
P1 = Patm because it is in contact with the atmosphere, and the air on the outside of the manometer in this problem has pressure = Patm, including the air that is right on the boundary (in contact with) the mercury. If you go down into the mercury, the pressure in the fluid starts increasing with Patm+ρgh. When you go around the bend and start coming back up the other side, the pressure in the mercury drops by ρgh until you reach the same depth on the left hand side (which I mention at 1:31): that point also has a pressure of Patm. Moving even higher up pas that point, pressure continues to drop at a rate of ρgh, and once we pass point #2, the ρ changes to that of oil. I think you are seeing the difference in height of each side of the mercury and thinking that somehoe the Patm is lefting the other side, but for compound manometers like this, you can't look at them and come to a conclusion like that, you need to methodically go through each fluid one at a time and calculate as I did in this video. Hope that helps!
@vuongngo2181
@vuongngo2181 7 жыл бұрын
ty
@lyrauken
@lyrauken 5 жыл бұрын
Thanks man.
@Engineer4Free
@Engineer4Free 5 жыл бұрын
You're welcome Berkay
@yugs6970
@yugs6970 6 жыл бұрын
Tanx a lot
@Engineer4Free
@Engineer4Free 6 жыл бұрын
Tanx for watching!
@abdullahhouran96
@abdullahhouran96 4 жыл бұрын
God bless this legend
@Engineer4Free
@Engineer4Free 4 жыл бұрын
Thank bru 🙌🙌
@bhgam3r769
@bhgam3r769 8 жыл бұрын
Thanks 🌹🌹
@asjalahmad4632
@asjalahmad4632 8 жыл бұрын
Thanks a great deal
@huhhhhh4497
@huhhhhh4497 5 жыл бұрын
Isn’t 13500*9.81*0.15 is equal 19865.25?
@huhhhhh4497
@huhhhhh4497 5 жыл бұрын
And it will be 101,000 - 19865.25?
@Engineer4Free
@Engineer4Free 5 жыл бұрын
Yeah I just rounded prematurely. You should keep more sig digs in calculation, but when I make these videos sometimes it's just super time consuming to write out the full value for such big numbers. But essentially 101 kPa - 19.9 kPa = 81.1 kPa.
@lameesk.a162
@lameesk.a162 7 жыл бұрын
You are the best, thank you verrrrrry much, you've saved me💜💛😘😘
@gelomelo3426
@gelomelo3426 2 жыл бұрын
Great👏👏👏👏👏
@bayanbtoush2786
@bayanbtoush2786 8 жыл бұрын
thaanx a million
@Engineer4Free
@Engineer4Free 8 жыл бұрын
+Bayan Btoush Thanks for the comment, glad to help!
@francoispasmore7896
@francoispasmore7896 9 жыл бұрын
Hey .. i think u have sumn wrong ... Monometers measure gauge pressure ... meaning at 1 atm the gauge would read '0'
@Engineer4Free
@Engineer4Free 9 жыл бұрын
+Francois Pasmore Good observation. I did this problem using the absolute pressure measurements. In this case where I find the pressure of the gas to be 81 kPA absolute, that could also be expressed as 20 kPa gauge (101 kPa - 81 kPa = 20kPa). Perhaps I should have been more clear that I was using absolute pressures!
@francoispasmore7896
@francoispasmore7896 9 жыл бұрын
+Engineer4Free ok that's for clearing that up
@PoproqzSwag
@PoproqzSwag 6 жыл бұрын
I also need help edith a differential manometer with 2 fluids. I'm going to check your videos for that.
@ARCANEmateCLAN
@ARCANEmateCLAN 7 жыл бұрын
Huh, I was doing your C++ tutorials and now I started my degree I'm back here
@Engineer4Free
@Engineer4Free 7 жыл бұрын
I teach all sorts of things, glad you found your way back :). What degree are you studying? I'm planning to release several more courses, hopefully you'll be able to use them!
@ARCANEmateCLAN
@ARCANEmateCLAN 7 жыл бұрын
Engineer4Free Chemical Engineering
@Engineer4Free
@Engineer4Free 7 жыл бұрын
Good luck!
@ARCANEmateCLAN
@ARCANEmateCLAN 7 жыл бұрын
Thanks!
@YazzaY1
@YazzaY1 9 жыл бұрын
THANK YOU!
@fareedhaddad8240
@fareedhaddad8240 7 жыл бұрын
thanks ♥
@Engineer4Free
@Engineer4Free 7 жыл бұрын
@boukhadrachakib2108
@boukhadrachakib2108 6 жыл бұрын
There is only one thing that is killing my mind we always talk about the pression from the top what about the pression ftom the bottom!?? :/
@Engineer4Free
@Engineer4Free 6 жыл бұрын
We talk about pressure from the "top down" because that's where the interface with the air is, and thus a known pressure. If you inverted the manometer in this video, the mercury on the furthest right part of the manometer would just fall out, just like turning a cup upside down. That's why you always see a boundary of liquid and gas with the liquid on the bottom, otherwise it wouldn't work. It doesn't mean that the first measurement has to be "going down" though. In this video, point 2 is above point 1, and although the column of fluid initially extends downward from 1, we don't care at all how far down it goes, we just care about the relative height difference between 1 and 2, and in this case 2 is above 1. Does that clear it up?
@lukmanali6426
@lukmanali6426 9 жыл бұрын
is the exact answer 81380pa?
@Cleonhide2
@Cleonhide2 8 жыл бұрын
i got about 2429...
@raeiilobete4117
@raeiilobete4117 8 жыл бұрын
I dunno why there is a subtraction or addition since my teacher doesn't teach that kind of method. Please help me, do you have some lesson similar to this. My teacher said that he will include a lot of this in our exam Huhuhu
@Engineer4Free
@Engineer4Free 8 жыл бұрын
+Raeii Lobete Hey, I made 10 fluids videos so far, you can find the whole playlist here: kzbin.info/aero/PLOAuB8dR35oeOIPMOBH6hjwobuIJHPKSN if you have time, it's worth watching all 10. If you are in a rush, the last 3 videos in the playlist are directly about manometers. Basically, if you are looking at pressure in two different heights in a uniform colunm of liquid, they will have different pressures. Lets use the example from this video, where P1 and P2 are both connected by the single column of mercury, and P1 is lower in height than P2. P1 will have a greater pressure, because there is more fluid on top of it (15 cm more of mercury to be exact). So that means P1 is greater than P2. Think of how the bottom of the ocean is under a great amount of pressure, that's because the weight of all the water above it is creating the pressure. So if P1 > P2, then that means P1 = P2 + something. Conversely, if P2 < P1, then that means P2 = P1 - something. (where "something" is a positive value). "something" is always = ρgh. So in other words, if you know point is lower than another in a continuous fluid, then the pressure at the lower point = the pressure at the higher point + ρgh. If you know the pressure at the lower point, then simply subtract ρgh to get the pressure at the higher point. It seems a little backwards because you add when you go down and subtract when you go up, but remembering the example that the bottom of the ocean is under high pressure, that can help sort out which way adds pressure and which way subtracts pressure. Hope that helps!
@raeiilobete4117
@raeiilobete4117 8 жыл бұрын
Thank you so much sir
@user-uj1qf2em5c
@user-uj1qf2em5c 6 жыл бұрын
على أي أساس أضع سالب أو موجب. ممكن أحد يفهمني.
@johnorrange1113
@johnorrange1113 6 жыл бұрын
حج صلي على النبي ...لما تنتقل من نقطه مرتفعه الى نقطه منخفضه نضع موجب للقانون (رو *جي*اتش) اما عندما ننتقل من نقطه منخفضه الى نقطه اعلى نضع سالب ل(رو*جي*اتش) 1
@johnorrange1113
@johnorrange1113 6 жыл бұрын
بالمثال نجد ان بي 1 اقل نخفاضا من بي 2 وهذا يعني ان بي 1 ضغطها اعلى لذلك عندما نريد ايجاد بي 2 نطرح (رو*جي*اتش)من بي 1 فنجد بي 2 والتي ضغطها اقل
@JoshCabatuando
@JoshCabatuando 10 жыл бұрын
THANKSSSSSSSSSSSSSSSSSSs
@jxmsxi
@jxmsxi 4 ай бұрын
@Mehdiranjb
@Mehdiranjb 5 ай бұрын
🌹🌹
@homermondares6607
@homermondares6607 3 жыл бұрын
labyu
@benjaminkaldahl865
@benjaminkaldahl865 7 жыл бұрын
u mi boi
@madhukumars458
@madhukumars458 5 жыл бұрын
thank you sir
@Engineer4Free
@Engineer4Free 5 жыл бұрын
You're welcome Madhu =)
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