Continuity of Multivariable Functions

  Рет қаралды 43,571

Mathemation

Mathemation

Күн бұрын

Пікірлер: 24
@sunraiii
@sunraiii 2 жыл бұрын
Great video, and the trick at the end, transforming cartesian to polar coordinates to have one less variable to worry about and approach (0,0) “from all directions”, is really cool!
@m.varunreddy7365
@m.varunreddy7365 2 жыл бұрын
Beautiful video, loved the visuals(graphs,3d), they help me understand faster... thank you suur!
@reijo6079
@reijo6079 2 жыл бұрын
Thank you so much, this really made helped understand how to solve basically any kind of problem like this and also how to make functions continuous in certain points!
@MiguelSantos-lu8uj
@MiguelSantos-lu8uj 2 жыл бұрын
Great video! Very underated channel with amazing quality. Love from Portugal
@mathemation
@mathemation 2 жыл бұрын
Thank you, Miguel! So glad you have been enjoying this content :)
@danieljulian4676
@danieljulian4676 Жыл бұрын
Nice presentation. First commendation is the figure at the beginning that shows a discontinuity in a surface over the domain R^2, which really brings home the bivalent situation at the discontinuity. You cover the topic (which is a standard one) and include all the usual points, including the transformation to polar coordinates. When you mention applying L'Hôpital's rule, valid on domain R, the series expansion of the function is (at least) implied, and this is also valid in domains beyond R. With the function you chose, the linear term is sufficient to show the limit exists, unless I'm forgetting something important.
@NibrasKoo
@NibrasKoo Жыл бұрын
Very helpful video with a very good explanation thank you so much
@Stefabro
@Stefabro 2 жыл бұрын
you're really good at explaining, thank you for all your help!
@MrCEO-jw1vm
@MrCEO-jw1vm 5 ай бұрын
really good explanation! thanks
@lav6978
@lav6978 2 жыл бұрын
Arigato gozaimuch for the wonderful explanations
@abdelrahmanabdelrahman8149
@abdelrahmanabdelrahman8149 2 жыл бұрын
you are so good
@satarnaghizadeh6623
@satarnaghizadeh6623 11 ай бұрын
Awesome ❤
@mwilamwamba1787
@mwilamwamba1787 Жыл бұрын
Thank you🎉
@matrixtrace
@matrixtrace 2 жыл бұрын
Last example: would it be legal to make a substitution z=x^2+y^2, without transforming to polar coordinates?
@mathemation
@mathemation 2 жыл бұрын
Yes, that's fine. This works because (x,y)->(0,0) if and only if x^2+y^2 -> 0. Effectively, this is the same as transforming to polar coordinates.
@dzdeparsio4676
@dzdeparsio4676 2 жыл бұрын
Thank you so much
@isaacmarcelino_
@isaacmarcelino_ Жыл бұрын
How do we know the best paths to take?
@عشإيجابيا
@عشإيجابيا 3 ай бұрын
same qst
@ijustwanttoseealiadabbing2270
@ijustwanttoseealiadabbing2270 Жыл бұрын
love you
@rogersowden2369
@rogersowden2369 3 жыл бұрын
Hey i checked your video before this but I couldn't see anything about x^2 + y^2 = p^2? where do I find these cartesian to polar conversions?
@mathemation
@mathemation 3 жыл бұрын
The conversion between Cartesian and polar coordinates are discussed here: kzbin.info/www/bejne/lX67hZeVj7p-fMk
@rogersowden2369
@rogersowden2369 3 жыл бұрын
@@mathemation Thanks for the quick reply! You're awesome! Subbed
@shams8917
@shams8917 2 жыл бұрын
💛
@jimmysdallas6162
@jimmysdallas6162 3 ай бұрын
Tristan tate made a math vid
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