Couple Moments | Mechanics Statics | (Learn to solve any question)

[@QuestionSolutions]

Please wait, before you write a comment asking why clockwise is positive, or counter-clockwise is positive, please watch this video first: kzbin.infoP029mqnp4XY thanks!

[@cqllysto]

I love your videos so freaking much, you don't understand. The animations and explanations are so clear and so smooth. You are the most underrated channel for engineering students that I have ever come across.

[@QuestionSolutions]

Thank you so much for your kind comment, it was really nice to read :) If you can, and only if you want to, please consider sharing this channel with your friends and classmates, it might help them out too, and it will help the channel out. I would truly appreciate it. Best wishes with your studies!

[@MarnisAntonites]

my thoughts exactly

[@PunmasterSTP]

Out of curiosity, how have your studies in engineering been going?

[@MdJunayed]

Bro my engineering mechanics course is finally over. Thanks for all of your effort! I will surely suggest your channel to the juniors.

[@QuestionSolutions]

I hope you did well :) And thanks for sharing the channel, it's really appreciated.

[@talha3346]

I must admit, besides your explanations, your voice is so good and pleasing.

[@QuestionSolutions]

Thank you very much, I really appreciate it :)

[@MaryumNoorX]

I haven't been able to put together and relate all the information we are being given for a long time, but your videos are the perfect speed, content and simplicity, and complexity. It's like I've been gifted by God. Thank you.

[@QuestionSolutions]

Really glad to hear this helped! I wish you the best with your studies.

[@humzamuhammad2426]

Bro deadass explained a 80 minute lecture in 5 mins. Now I just gotta read over the PowerPoint and do the problems. This guy is GOATED

[@QuestionSolutions]

I’m glad to hear that you found the explanation helpful! Keep up the good work with your studies, and remember, practice is key when it comes to problem solving. You’re doing great! 👍

[@PunmasterSTP]

How'd the rest of your class end up going?

[@SOPHOCLESIFY]

This is like Organic Chemisty Tutor with Disney budget, short, clean, and concise.

[@QuestionSolutions]

😅 Thank you!

[@GurbetciAri]

I am student at one of the top universities of my country and you make things much more clearer just in two hours more than my lecturer did in 20 hours.

[@QuestionSolutions]

Congrats on getting into a top university. Keep up the great work and best wishes with your studies.

[@nooralmubarak4503]

Sakarya uni?

[@GurbetciAri]

@@nooralmubarak4503 not Sakarya, İTÜ

[@GurbetciAri]

@@nooralmubarak4503 not Sakarya, İTÜ

[@jasonbecker8893]

​@@nooralmubarak4503 top diyor

[@Master_KII]

Man I absolutely cannot believe how easy you make mechanics, all your videos summmarise and explain thing so clearly

[@QuestionSolutions]

Glad you like them and thank you for the nice comment! I'm glad all the videos were helpful to you :)

[@kylel.9575]

I’m a first year engineering student and you’re saving my life. Such clear explanations in a short amount of time.

[@QuestionSolutions]

Thank you very much! Really glad to hear these videos are helpful. Keep up the great work and best wishes with your studies.

[@zachazuki]

Your honestly one of the only online tutors that can teach and make it very easy to understand. Great job!

[@QuestionSolutions]

Thank you so much, I really appreciate your comment.

[@porterfielddynamics]

This video is a lifesaver, hell, all your videos are incredible. Seriously one of the hidden gems on youtube, amazingly high production value and a great help. Please don't stop making videos, this channel is going to blow up any moment and is such a great help. Thanks again!

[@QuestionSolutions]

Thank you very much for your kind comment. I am so happy to hear that these videos help :) Best wishes with your studies and keep up the great work!

[@alexandragarcia785]

This video is awesome, my so and I are going on a binge of your channel and your videos are just perfect and super helpful. I know we'll do well on our tests tomorrow thanks to you.

[@QuestionSolutions]

I'm so glad! I hope you guys do really well on your test. Best of luck. 👍

[@DanielMcilroy-lc3fr]

I have not understood what my professor has been saying all semester and I've learned everything we've done so far in like 3-4 hours thanks to you. You are a gift from above my guy, God bless you

[@QuestionSolutions]

I am really happy to hear these videos helped you out. Thank you for the kind comment and I wish you the best in your studies!

[@sohankobiri]

Your videos have been really helpful. The way the concepts are broken down into simple steps with exams are really efficient, literally saving my finals for me! Thanks for putting them up :)

[@QuestionSolutions]

Glad to hear that! I hope you do awesome on your finals and thank you so much for taking the time to write such a nice comment. I really appreciate it. :)

[@rubaiyaruhi4641]

I have known about this channel from my rollmate, Undoubtedly the best channel for every Engineering student ❤️

[@QuestionSolutions]

Wow, really glad to hear these videos are being shared and super happy to hear they help you out. Thank you for taking the time to write your comment, really appreciate it.

[@KabeloMokoena-q5d]

This is best channel,just learnt what I was taught in class whole 2 hours in just few minutes🔥🔥

[@QuestionSolutions]

I am really glad to hear that! Keep up the good work :)

[@PunmasterSTP]

There were a couple of really awesome nuggets of information in this video!

[@QuestionSolutions]

Glad you enjoyed those nuggets, they're great for making those mechanics problems a breeze!

[@yannietan]

I don't get where you get these numbers for your cross product.

[@QuestionSolutions]

So I assume you're asking about the position vectors and expressing forces in cartesian form? If yes, please watch: kzbin.info/www/bejne/eXTIiKxnoNKrg9U and kzbin.info/www/bejne/o6uamIOmfrFjfc0 Those 2 videos will cover how to get the values for the cross product. Let me know if you have further questions. Thanks!

[@alaybey9771]

Best statics channel ever but i just need more videos and harder problems

[@QuestionSolutions]

Thank you. Once you gain the fundamentals, you can solve pretty much any question thrown at you :) Keep up the good work!

[@Handleoriginal12]

Wow thank you so much! I didn’t understand my professor after 2 lectures but understood this explanation in the first 30 seconds of the video.

[@QuestionSolutions]

I’m really glad to hear that you found the video explanation helpful! Keep up the great work and best wishes with your studies. 😊

[@jesussaquin6266]

man even for a quick review of statics youre the boss man.

[@QuestionSolutions]

Thank you very much! Glad to hear it's helpful.

[@ahmadtheaviationlover1937]

where did the 400 come from?? at timestamp 2:49

[@QuestionSolutions]

Read the question, it's in there 😅

[@ayae1290]

Thank you. You explain the problems so clearly that anyone could understand.

[@QuestionSolutions]

I am really glad to hear that :) Thank you!

[@daigosol5375]

@ minute 1:22 you say we have to ignore the force at A since force 1 cannot create a moment about point A. What is the force 1 in the situation? Is it the force at A cannot create a moment about point A? I just stumbled upon your channel. So far, it's really good work thank you so much!

[@daigosol5375]

So basically is force 1 the negative force at point A?

[@QuestionSolutions]

It could be any force, but here, I was referring to the negative force. So you just ignore the force at the location of reference, in this case, point A.@@daigosol5375

[@afnansaeed6697]

The videos of this channel are the best, fast and helpful, thank you

[@QuestionSolutions]

Glad to hear :)

[@alexanderdepaemelaere3617]

Helping me out with the retake exams, thanks for the clear explanations!

[@QuestionSolutions]

You're very welcome and best of luck with your future exams.

[@shubhankar3111]

This video just cleared all my doubts. You are awesome, thank you.

[@QuestionSolutions]

Awesome! Really glad to hear that :)

[@sStrict]

Hello Question Solutions, hope you're doing well! I have a question, at 3:25 you found the Force in cartesian form to be {0i+0j+125k} I'm a little confused by how you found that, I thought we usually do f*(unit vector along Rab) to find the Force in cartesian form, could you please explain to me how you were able to find the force in cartesian form by just looking at the force magnitude? Thank you!

[@QuestionSolutions]

Sure, so if you look at the 125N force, it faces straight up. So that means it's not at an angle, which also means that it lies directly on the z-axis. So it can only have a k-component and its 125N straight up along the z axis, giving us {0i+0j+125k}. If a force lies directly along an axis, we don't need to go through the trouble of multiplying it by a unit vector. Even if you do, remember that the z-axis unit vector is {0i+0j+1k}, so it still leads us back to the same place.

[@naeemabed9126]

Your videos are extremly brilliant. The animations really help a lot so please keep it up. If possible could you summarise at the end basic steps when approaching the certain types of problems. I feel this will add even more to your excellent teaching!

[@QuestionSolutions]

Thank you for the suggestion. I think I did it before, in some older videos, and then stopped. I will see, I appreciate the feedback!

[@foundinyourmind]

For the problem at 2:51, does the vector Mc act perpendicular to the position vector, rab? also, where would you draw the couple moment?

[@QuestionSolutions]

The vector for the couple moment would be directed along the x-axis. The direction of the vector has to be found using the right hand rule. So here, a counter-clockwise moment would mean it points along the positive x-axis.

[@erickcastellanos6814]

This video was superrr helpful!! Clear explanations

[@QuestionSolutions]

Glad to hear! Best wishes with your studies.

[@yipyiphooray339]

YOU ARE AWESOMEEEE, A GOD SEND FOR ENGINEERING STUDENTSSS

[@QuestionSolutions]

Many thanks, really appreciate your comment.

[@KimberlyGutierrez-p8m]

Time stamp 5:32. How did you get i component for C to be 0.6?

[@QuestionSolutions]

350 mm + 250 mm = 600 mm = 0.6 m

[@figomegalo1974]

AWESOME RECAP THANK YOU 🔥🔥

[@QuestionSolutions]

You're very welcome!

[@juksjunior1136]

Thank you,I got the answer within the first 2mins of the video

[@QuestionSolutions]

That's awesome to hear! Keep up the good work.

[@gamingwithdingo]

You are a god, i feel like crying 😢

[@QuestionSolutions]

😅 Keep up the good work, you can do it!

[@winifredadu5077]

in the last example, how did you get the x component from A to B. I thought it would only have y and z components.

[@QuestionSolutions]

Are you talking about the position vector rAB? If so, it doesn't have an x-component (4:28). Maybe I am not understanding your question, please let me know a timestamp so I can take a look at the equation you're referring to. Many thanks!

[@fil1361]

Quick question, lets say for example on exercise 3, will the result be the same if the force on the negative Z axis didnt exist? Since we dont take it into account is MA the same regarless of F = (0i,0j,-125k)?

[@QuestionSolutions]

Your position coordinate would need to be from the z-axis to the force applied. Here, the position coordinate is from the start of one force to the other force.

[@alyx2868]

For the last question, if we were to use Rac & Rba (instead of Rca & Rba like shown in the video) are we supposed to get the same answer? was wondering since Im getting {-12.11i+10j+17.3k} should I consider the direction of the moment of each individual moment (Mc1 & Mc2)

[@QuestionSolutions]

You will get the same answer. If you go from A to C for your position vector, the only difference is that instead of ignoring the force at C, you ignore the force at A.

[@az_dh1064]

your video helps me a lot thank you 🙏🏼

[@QuestionSolutions]

You're very welcome!

[@zenobrawlstars3622]

Hello, I am a little confused about the differences between the terms moments, couples, and torques. Is the total torque of a system equal to the sum of all the moments and couples acting on the system?

[@QuestionSolutions]

They are all the same, just interchangeable words when it comes to solving problems. The total summation of moments about a system, is the same as the total torque of a system, etc. Please see this video first: kzbin.info/www/bejne/h3-xn4OQa52Giqs

[@yashbinda4521]

at 4:31 how do you get -12,11i i get that -0.346 times 35 is the -12 but why is at the i side?

[@QuestionSolutions]

Please see: kzbin.info/www/bejne/fGmseaWdaNWWbck

[@fahimfarhan3806]

Awesome tutorial.thank you so much. Please make video on fluid mechanics too.

[@QuestionSolutions]

You're very welcome. Fluid mechanics is on my list of things to do 👍

[@bayanishaunandrew6068]

exquisite explanation!

[@QuestionSolutions]

Thank you!

[@joshl2263]

Hi, quick question abt the steering wheel. if the force is at an angle, would i find the x and y component and then find the x-y component of the distance? then do M=Fd in the x component and then M=Fd in the y component

[@QuestionSolutions]

In the steering wheel as in the ships wheel? So you have the forces applied at the 9 and 3 o'clock positions? If the force is at an angle, then you break the force into x and y components. The x component won't create a moment since it would just be pulling the wheel apart. It's like grabbing the 2 sides and one side pulls to the left and the other to the right. Only the y-component will create a moment. But in general, the steps you outlined are correct.

[@axviiaxvii5909]

For the triangle question, where are you taking moments from?

[@QuestionSolutions]

So let's look at 00:45, where are we calculating the moment about? Couple moments don't work like the normal moments. You're not specifically taking the moment about a point, though you can think of it as taking it about the center between the two forces. So in the triangle, you're just figuring out the moment, not about a specific point, but rather the moment created by the opposing forces. If it makes it easier, you can think of the triangle pinned at the middle and the forces creating a moment that spins it about that pin.

[@MickeeMoooo]

Hi, I just want to say thank you very very very much for this amazing videos. It's sooooooo helpful. 🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻 :D

[@QuestionSolutions]

You're very welcome and glad you like them! 😀❤👍

[@MegumiFushiguro-x8z]

Can i ask a question about the second question, how do you get the 0.5 in the lenght of the triangle?

[@QuestionSolutions]

So the bottom length is 1 m, half of that is 0.5 m. 1/2 = 0.5. Is that what you were referring to? If not, please let me know and I will do my best to help. Thanks!

[@WispyChups]

Can someone explain to me how the designation for ccw or cw for each force is determined? Did he just choose an arbitary point and based everything on that? What about forces that point parallel to a beam? How would you tell whether the force would effect a ccw or cw motion?

[@QuestionSolutions]

So when it comes to couple moments, you have to think about the whole object moving, not a singular point. When you write your algebraic equations, you determine whether you want clockwise movement to be positive, or counter-clockwise movement to be positive. Regardless of the direction you pick, you will end up with the same answers. In 3D problems, this isn't an issue since the vectors take care of the directions by themselves.

[@ludypalacios2889]

Great Explanation!!!!!!!!

[@QuestionSolutions]

Thank you very much! :)

[@menglimarrero4296]

Nice animation. THE rBA is A-B right? Is the MC1 and Mc2 Add together? As your last example

[@QuestionSolutions]

Thanks! Yes for the position coordinates, and yes for the moments. MC1 and MC2 are added together.

[@vikramnagarjuna3549]

Hi this is Vikram from India, Some of your videos (Absolute Dependent Motion) had been copied and re-posted in KZbin. Channel name is Hom Phaly. Please take action. I really appreciate your hard work and I am a big fan you.

[@QuestionSolutions]

Hi Vikram, thank you so much for letting me know, I really appreciate it. You are awesome! :)

[@qthassan1591]

bro your the goat

[@QuestionSolutions]

Thanks!

[@mariaalhijazeen4974]

3.16 ( why is the moment of force a is zero and how did you know the Cartesian form of the force on point b ) ??

[@QuestionSolutions]

So when you have a couple moment applied, to calculate it, you need to forget one of the forces and write a position vector from that location. Here, I chose to forget the force at A, and then wrote a position vector from A to B. The force is along the z-axis, (so just faces vertically without any other components), which means it only has a k-component. So it's just 125k.

[@m.c3899]

If i assume clockwise is negative and anticlockwise is positive, i get a different answer. Is it ok?

[@QuestionSolutions]

No, you will and should get the same exact answer. Please see: kzbin.infoP029mqnp4XY?feature=share

[@kukuyiehalem6391]

Great video. But on the second example why did we use clockwise direction for 600N but not the others

[@QuestionSolutions]

You pick the direction you want. It's up to you 👍

[@menglimarrero4296]

Sir At the last example MC2 : [0 - (-10)] j Should it be positive 10j right?

[@QuestionSolutions]

No, the j component is negative in the sequence, so you end up with (-)(-)(-) = (-)

[@menglimarrero4296]

Thank you thank you very much for answering my questions sir.

[@QuestionSolutions]

@@menglimarrero4296 You're very welcome!

[@unfeelingsalmon1350]

Great video! Thanks!

[@QuestionSolutions]

You're very welcome!

[@archiedahili5391]

I'm confused at the side of the triangle 2:28 I tried solving it with 1sin(40°) and my calculator gives me 0.6427

[@archiedahili5391]

Ohh can you explain me why is it 0.5(cos40)? Im pretty bad at this trigonometry thing

[@archiedahili5391]

And can you also explain to me where did you also get that 400? Around 2:28 also

[@QuestionSolutions]

@@archiedahili5391 Okay, so first, look at 2:20. See how I drew that pink right angle triangle? That triangle is an exact half of the big blue triangle. That means the bottom length is 0.5 m, since that's 1/2 = 0.5 m. Now that we know the bottom length, we can use the angle given to us (the 40 degree angle), to figure out the hypotenuse of the pink triangle. This hypotenuse is also the side length of the big blue triangle. So we know the adjacent length, (bottom length), which was 0.5 m. Since we have adjacent length, we need to use cosine because cosine = adjacent/hypotenuse. We can't use sine unless we know the opposite length, in this cause, that would be the height of the triangle. So we can write: cos(40) = 0.5/length. Isolate it for length. length = 0.5/cos(40) ==> 0.653 m. I hope that helps.

[@archiedahili5391]

@@QuestionSolutions oohhh ok ok thank youuu

[@QuestionSolutions]

@@archiedahili5391 You're very welcome!

[@chrisbroward]

you make is seem so easy!!!

[@QuestionSolutions]

When you do a few questions, it'll become really easy for you too :)

[@KristinaKhalilsson]

hey I love your videos however I wonder how you got the answer 829.7n ?

[@QuestionSolutions]

Thanks. Please give me a timestamp so I know where you're referring to. Thanks!

[@gilernt]

bro is singlehandedly doing the job my professor is supposed to be doing

[@QuestionSolutions]

I am glad these videos are helpful. Keep up the great work and best wishes with your studies!

[@jumpmanhush]

Why is 25j negative? 3:30 3:31

[@QuestionSolutions]

Please see this video: kzbin.info/www/bejne/fGmseaWdaNWWbck

[@capturedtv1588]

You are the best!

[@QuestionSolutions]

Thank you very much! :)

[@yassin6865]

@3.32 how did you get -25j and wouldnt it be 25i +37.5j?

[@QuestionSolutions]

For the j component, it would be 0.2 x 125 = 25, and it's negative because it's the 2nd term. Please see: kzbin.info/www/bejne/fGmseaWdaNWWbck

[@MDSHADDAMHOSSAIN-jc8gd]

do u have any tutorial on centriod and center of gravity of 2d and 3d problem solving?

[@QuestionSolutions]

I don't think I do, just mass moment of inertia.

[@naveenau143]

dear the and for 2:50 is 617.15 i guess

[@QuestionSolutions]

Sorry, I am unsure of what you mean? The answer of 829.7 N is correct. How did you get 617.15?

[@starsofthegalaxy6100]

You saved my ass, thank you so much

[@QuestionSolutions]

You're very welcome! :)

[@GCblastercadet]

1:52 But I thought clockwise meant negative and counterclockwise meant positive..

[@QuestionSolutions]

Try it either way, you get the same answer. When you do more questions, you'll realize that your life will become easier if you pick the side that gives you the most positive signs, or all positive signs. Either way works, do what you like/ easiest for you 👍

[@ikmalhakimharun3823]

can u explain how couple moment can become negative or positive ?

[@QuestionSolutions]

So moments aren't really positive or negative, in 2D, you use clockwise or counter-clockwise to state the direction. In 3D, you can use the right hand rule (same with 2D), if you want to know the direction of the moment vector. But in essence, let's say you pick clockwise to be positive, and your answer is positive, then your moment is clockwise. If you get a negative answer, that means your moment is counter-clockwise because you picked clockwise to be positive but your answer was negative. The same is true for the opposite. So if you pick counter-clockwise to be positive, and your answer is positive, then your moment is counter-clockwise. If your answer is negative, then your moment is clockwise.

[@ikmalhakimharun3823]

@@QuestionSolutions hmm. Is this the same concept for dynamics bro ? Bcs I've been searching for how to determine the sign convention for work done due to couple moment. As far as I know. It depends on the torque direction right ? So how do I know the direction of the torque ? Is it the same as the direction of the rotation ??

[@QuestionSolutions]

@@ikmalhakimharun3823 I think you might be confusing the moment vector with the direction of turning. The vector is always found using the right hand rule. Work done by moments when it comes to dynamics involves taking the mass moment of inertia. Is that something you already covered? I think you might be mixing 2 topics together. :) Is there a problem you can show me that requires what you are asking? I can take a look and let you know.

[@ikmalhakimharun3823]

@@QuestionSolutions hmm. Probably bro. I think so too. I don't know much about couple moment. So I just Google them and found out the sign convention are related with the rotation of torque. Btw bro. Where can I give u the problem ?

[@QuestionSolutions]

@@ikmalhakimharun3823 Email me at "contact @ questionsolutions .com" without any spaces. Make sure to check your junk/spam box for my reply, for some reason, sometimes, it goes into those.

[@Lucas-fs2wf]

Thank you so much !!

[@QuestionSolutions]

You're very welcome!

[@b.naveenraj3275]

really helpful

[@QuestionSolutions]

I am really glad to hear that :)

[@davidemelu1142]

why is clockwise positive?

[@QuestionSolutions]

Use whatever direction you want to be positive, you will get the same answer. It's just a convention that counterclockwise is positive, whatever way you choose yields the same answer in the end.

[@jhononillgalvez950]

It must be positive when the force is in counter-clockwise direction and vice versa

[@QuestionSolutions]

No, it doesn't. It's completely up to you on which way you want it to be positive, because there aren't really any "positive or negative" moments. They have a direction. The positives and negatives help with figuring out the direction when doing problems. You can pick whichever way you want it to be positive, and if you get a negative answer, it's opposite to your assumption. In fact, I encourage you to do it opposite to what you just said so you can realize that you still get the same answer. This will bring you more insight into doing these problems, and will allow you to pick whichever direction you want to be positive, making you solve questions faster.

[@labibarahman9619]

You are magician

[@QuestionSolutions]

🌟 Many thanks!

[@sbruder7433]

THANK YOU

[@QuestionSolutions]

You're very welcome!

[@akhilachukka1074]

Helpful ❤️

[@QuestionSolutions]

❤

[@saithej-s1v]

congrats bro your video is suggested by chatgtp

[@QuestionSolutions]

Wow, I didn't know that. Thanks for letting me know!

[@theturkish1373]

4:30 you forgot to add - to J vector when doing cross multiplication. it should be positive 12.11

[@QuestionSolutions]

I assume you mean the i component, not j, since the j component is 0, and the normal convention is to not put negative signs in front of 0s, but you can if you want, it's your choice. I mean it has no value, so it doesn't really matter. 😅In most cases, you wouldn't even write out the j component, but I did because students tend to get confused or ask what happened to it. Anyways, if you are really referring to the i component, what's shown on screen is perfectly correct. The i component is -12.11, since it's -0.346 x 35 = -12.11i. 👍

[@theturkish1373]

@@QuestionSolutions Ah yes silly of me... I should go for a sleep now... Thank you sincerely.

[@QuestionSolutions]

@@theturkish1373 Have a wonderful rest! :)

[@niranjanaprasad4293]

Thank you

[@QuestionSolutions]

You're welcome!

[@欣馨频道]

moment unit is Nm or N

[@QuestionSolutions]

It's Nm, if I showed N, then it's a typo.

[@krayapureddy6510]

Voice 🔥❤️

[@QuestionSolutions]

❤️

[@atikaabu6087]

Life saver

[@QuestionSolutions]

Glad to hear it helped!

[@akosibrothercoolpzzle123]

I thought clockwise=negative? Pls help

[@QuestionSolutions]

See pinned comment.

[@akosibrothercoolpzzle123]

My bad, I didn't check the comments first. Thank you very much.

[@QuestionSolutions]

That's alright. Best wishes with your studies!@@akosibrothercoolpzzle123

[@Hastalavista29]

3.25 I didn't understand the R(AB) vector

[@QuestionSolutions]

See this video first: kzbin.info/www/bejne/eXTIiKxnoNKrg9U

[@danielhealy2524]

clockwise is negative.

[@QuestionSolutions]

See: kzbin.infoP029mqnp4XY So moments aren't really positive or negative, they just have directions. When we do calculations, we choose a direction to be positive. This allows us to solve the problem. Feel free to use clockwise as negative, it will give you the same answer as choosing clockwise as positive. It makes no difference.

[@RSA_Shock]

Love it

[@QuestionSolutions]

Thanks!

[@peurquia]

2:46

[@QuestionSolutions]

What about 2:46? Did you forget to write a question? 😅

[@alive4668]

I like you brother !!!

[@QuestionSolutions]

Many thanks!

[@SalmanFarooq660]

Let's talk for couple of moments😂😂😂

[@QuestionSolutions]

Let's talk about couple moments 👍

[@SalmanFarooq660]

@QuestionSolutions i know, it just rhymes so much....

[@SalmanFarooq660]

By the way...thanks alot... I'm watching your playlist to prepare for exam tommorow

[@QuestionSolutions]

@@SalmanFarooq660 I know, I should have said "let's talk for a couple of moments" would have been punny 😅

[@QuestionSolutions]

@@SalmanFarooq660 Best wishes on your exam tomorrow!

[@Michael-ol2gv]

Why are you going through this so fast, i mean can you just slow down and show us each step in your solutions.

[@QuestionSolutions]

What steps did you want to see? Can you give me a timestamp where you thought I should have shown more steps? Then I can think about it for future videos. Thanks!

[@joshuacho3432]

fucking goat

[@QuestionSolutions]

Thanks!

[@rueljaphetbitoy4684]

1vi9 1

[@QuestionSolutions]

Not sure what that means?

[@vox_celeste9427]

go back to school

[@QuestionSolutions]

Why, thank you! I always love a good excuse to learn something new. Maybe I'll see you there?

[@samuelgd9084]

Not interesting 👎👎👎

[@QuestionSolutions]

Sorry to hear that.

[@SeekPim]

I always mess up because I mess up the first step, getting the coordinates, then from there everything is wrong🫠

[@QuestionSolutions]

Well, on the bright side, you know where you usually make a mistake. So if you spend a few more minutes at the starting step, then the rest will be good :) Don't be too hard on yourself, do as many questions as you can. You got this!