Amazing and helpful for all the researchers i am proud to follow you
@parthshah68463 жыл бұрын
Very informative thank you, it helps in my dissertation project for catalyst analysis thank you once again
@nanoworld61223 жыл бұрын
Great to hear!
@mdmazbahuddin55925 жыл бұрын
Sometimes I don't get FWHM in nilfitpeaks chart after peak fitting using gaussian or Lorentz profile. What could be the reason? But when I use Gauss profile FWHM is shown in nilfitpeaks chart. My samples are mostly semicrystalline. Your videos were of great help in my project. Many thanks. Keep uploading such tutorials.
@hamdirihab33194 жыл бұрын
Thank you so much, but I find negative slope, is it normal?
@navdeepsharma2102 Жыл бұрын
Thanks a Lot sir, great have no words, lots of thanks, hope to make more viedio on other parameters, obtained on XRD and characterization methods
@malihaparvin42244 жыл бұрын
May Almighty gives you the best reward for this work, really helpful.
@rv37163 жыл бұрын
It was a very helpful and detailed video for those who are working on this topic. Thank you so much!
@nanoworld61223 жыл бұрын
Glad it was helpful!
@nanoworld61223 жыл бұрын
Glad it was helpful!
@nanoworld61223 жыл бұрын
Glad it was helpful!
@pugazhinthiran41874 жыл бұрын
Thank you very much for your detailed information
@dazza91294 жыл бұрын
My strain ended being a negative slope. Was there something wrong?
@clinktanr46174 жыл бұрын
No words to say amazing PPT point to point explanation... Thanks a lot..
@nanoworld61224 жыл бұрын
Thanks and welcome
@adilmansoor27164 жыл бұрын
indeed a simple and informative.thanks a lot.
@nanoworld61224 жыл бұрын
Glad it was helpful!
@MyTwinBloggers3 жыл бұрын
Good video.. really helpful
@usmanchem086 ай бұрын
thank you for this great video. helped me a lot.
@zhenhongxue22424 ай бұрын
关注,点赞加分享,谢谢up主的分享!
@Deathunter24 жыл бұрын
Very good and informative Video, keep the work up! :)
@abdulolaoye96122 жыл бұрын
Thank you for this video. please if someone have another material present in the primary material you are working on. Am I going to consider both primary peaks and secondary peaks or primary peaks alone?
@akarakoca2 жыл бұрын
First of all thank you for your sharing. i want to ask related W-H method. when we fit curvefitting if r^2 value far from 1 what we do to fix this? Some peaks maybe subtract?
@amrradwan42795 жыл бұрын
Thanks a lot for this great job, please continue
@madeehatabassum94784 жыл бұрын
Thank you for the amazing video. For my some XRD data there is a problem ( Fit did not converge) appears. why it happens?
@nanoworld61224 жыл бұрын
either the data required a baseline correction or smoothing. Do Not Select low intensities Peaks
@riyadhkakaiey57005 жыл бұрын
well done. you made it very easy. thanks a lot, I hope to continue to share more and more videos...
@abhishekjaiswal71434 жыл бұрын
Sir, can I get this word file that u used to explain?
@sebacbsee-corner67903 жыл бұрын
Thank you so much, it was really helpful 👍
@nanoworld61223 жыл бұрын
Glad to hear that!
@tahsinmozaffor36274 жыл бұрын
Thanks a lot very easily explained
@ricardohoffmannvalencia67713 жыл бұрын
I love your videos
@sta_19793 жыл бұрын
Could you please tell how to obtain a modified W-H plot from XRD peaks?
@rutikasawant99363 жыл бұрын
Thank you so much!! It was really helpful..
@sarveshkumargupta69884 жыл бұрын
Very interesting and knowledgeable video. Thank you, Sir.
@rushikesh_here3 жыл бұрын
it is very helpfull to me. thanks you ..
@nanoworld61223 жыл бұрын
Happy to help
@kranthibedala3 жыл бұрын
Excellent sir and Thanks a lot sir 🙏🙏🙏🙏
@rupammandal37174 жыл бұрын
great as always
@Physics59157 ай бұрын
When we plot in polynomial fit, which is taken as slop
@chiranjitchaliha53182 жыл бұрын
Sir since adjacent r square value is not near to 1..its a bad fit...so will it be correct...to conclude the result without making adjacent r square to value as 1
@UmaShankar-rr8py4 жыл бұрын
Very usefull information sir. But there is any possible to plot other three methods also halder Wagner plot
@aliansarihamedani80575 жыл бұрын
Nice job
@ParameswaranPed22d0086 ай бұрын
You did not divided the angle @ FWHM convertion to Radians @ 15.40. Is that ok. Can you clarify me?
@emmakhan144 ай бұрын
brilliant job (y)
@iqrajabbar52874 жыл бұрын
Thanks,V nice ,easy method
@saddiqueakbar47744 жыл бұрын
appreciated help for students. can you please teach us how to calculate dislocation density in XRD. Edge and screw dislocation
@dr.p.s.raghavanprofessor-c3774 жыл бұрын
Thanks for the detailed demo for calculating crystallite size. Can you comment on the value of the strain and the information obtained from it?
@arjunkrishna48153 жыл бұрын
sir/madam can you define what is microstrain?
@chinsoon10683 жыл бұрын
Hi, thanks for the video. I have a question. The angle used for calculation was not divided by 2. I am not sure if I understand it wrongly or is there any mistake.
@nanoworld61223 жыл бұрын
I have divided it, please watch it again from 13:35 to 13:48
@arjunkrishna48153 жыл бұрын
@@nanoworld6122 Sir can you explain why u neglected the error in the microstrain ?
@Surya-uv3bz Жыл бұрын
i am getting negative intercept , what to do? please help me out..
@awaisahmed29073 жыл бұрын
From where to get correlation coefficient values (R2) ?
@rac52053 жыл бұрын
I follow the same step but after fitting the peaks the data doesn't give the FWHM value.... Others are same... How can i take my FWHM value..?
@nanoworld61223 жыл бұрын
This is because, you performed the fitting using Gaussian instead of Guss
@rac52053 жыл бұрын
@@nanoworld6122 thanks for the reply..
@safoorashabir8192 жыл бұрын
sir please explain how to calculate mass fractions of aplha and beta phase in titanium aaloy from xrd data
@annisaf46893 жыл бұрын
Can you explain to me why Williamson-Hall more accurate than scherrer method. What the advantages of using Williamsoh-Hall method I mean
@nanoworld61223 жыл бұрын
Scherer equation is a rough theoretical estimation while W-H plot is more accurate. Because W-H plot separate micro strain from the grain size while this value is embedded is Scherer equation.
@faheemwani19963 жыл бұрын
sir how to calculate lattice parameter of composite film with different concentrations of doping
@maziidahh4 жыл бұрын
Sir, if there is a secondary phase in the XRD peaks, should we include the secondary peaks' information when calculating the FWHM?
@wafazina42254 жыл бұрын
Is it possible to use X'Pert high score for calculation of cristalline size and strain through this method W-H? Thanks
@awaisahmed29073 жыл бұрын
Brother, i got crystalline size different in both methods, what is the reason behind different crystalline size in debye Scherrer and W-H method ? ..thnx
@nanoworld61223 жыл бұрын
off course it will different. Scherer equation is a rough theoretical estimation while W-H plot is more accurate. Because W-H plot separate micro strain from the grain size while this value is embedded is Scherer euation.
@黃浩喆-x4e3 жыл бұрын
Thanks a lot for the tutorial, but I got a question to ask: Is it possible to have slope approximate to zero which means that there’s no strain in the material or the stress has been released causing no strain?
@sankalp35132 жыл бұрын
How do you account for instrumental broadening in this equation?
@nilkanthdevkar Жыл бұрын
What if standard data is not available
@laushenn60544 жыл бұрын
help! i have been getting Fit did not converge - mutual dependency exists between parameters error
@maryamzulfiqar95202 жыл бұрын
Respected Sir,. How much variation is acceptable between the calculated value of crystallite size by WH plot method and modified schrrer method?
@jasiras.v.3698 Жыл бұрын
did you got the answer? i got 35 nm from scherrer and 120 nm from wh plot..
@ashwanimaurya2069 ай бұрын
thanks sir,,,,,,,,,,
@nabillebchir87414 жыл бұрын
Thank you very much
@asst.prof.rohitnikam7293 жыл бұрын
What is meant by linear fit...why polynomial fit is not used
@fizikchy2 ай бұрын
You modify the equation to give you a line. \beta_T vs \theta relation is clearly non-linear. But \beta_T*\cos\theta vs \sin\theta relation is so. Therefore, you firstly create the latter plot, then apply linear fit, which works well.
@asifasadov3975 Жыл бұрын
Just Respect
@김대성-f2n8w4 жыл бұрын
thanks a lot , but when i calculate crystallites size, i have a problem in the unit value. when i use lamda as unit of Å, that time it was correct to compare to SEM. why?
@nanoworld61224 жыл бұрын
you are probably doing something wrong
@김대성-f2n8w4 жыл бұрын
@@nanoworld6122 thanks for your attention.
@vikashjaiswal52314 жыл бұрын
Excellent..
@nanoworld61224 жыл бұрын
Thanks a lot
@ManSingh-mw1il4 жыл бұрын
sir, the crystallite size we get from W-H plot is it the average crystallite size?
@nanoworld61224 жыл бұрын
Yes
@gopalakrishnanvenkata25374 жыл бұрын
evry useful. can you please send me the typed derivation shown in the video..thank you
@nanoworld61224 жыл бұрын
Ask it through email
@ericbu26314 жыл бұрын
Many thanks
@nanoworld61224 жыл бұрын
You are welcome
@rushikesh_here3 жыл бұрын
i want a pdf file of xrd.
@dalalalhilfi87 Жыл бұрын
i need the excel fil
@TSAjmal4 жыл бұрын
You are telling βT = FWHM and also βD = FWHM, why?
@rajeebkumarmalik88083 жыл бұрын
yes, I have the same doubt. is it same or what??
@fizikchy2 ай бұрын
\beta_T is the total broadening in this video. In earlier videos he does not take into account \beta_\epsilon, so \beta_D is FWHM there. But here, there are two contributions to FWHM (=\beta_T). In other models there maybe more terms contributiong to FWHM.
@arimateiaalves33494 жыл бұрын
hey man in my xdr data i obtained (Intercept -0,0028 ± 0,00891) is that possible? how can i calculate the crystal size ?
@nanoworld61224 жыл бұрын
There is a lot of explanatory material available on research-gate regarding negative W-H plot.
@PROFBCRAI4 жыл бұрын
The unit of fwhm should be radian
@PROFBCRAI4 жыл бұрын
Very nice 👍👌
@ryanrizaldynawawi34043 жыл бұрын
nice
@mohamedleminemohamedou34544 жыл бұрын
Thanks can you plz send me the word file
@sunandobanerjee7665 Жыл бұрын
your analysis is wrong because adj. R square value should come close to 1 , even at 0.8 to 0.9 is okay. you have to mask certain data points and fit the data, changing scale wont help.