CSEC Chemistry - Electrolysis 2

[@csecchemistry]

The equation at the cathode for the electrolysis of lead (II) bromide should be Pb2+ + 2e- ----> Pb. I made a typo. Sorry about that. (time 3.01 in video)

[@Speedy_Ethan]

Wouldn't the Na at 9:00 be discharged since it is concentrated NaCl?

[@lynnnewman8003]

thank god for terry's videos. I was going to give up living because of this topic

[@yalitsatc4354]

i love your videos, thank you so much for doing this

[@kavikamoses5952]

I love your videos they are awesome and a great help

[@viflet-will]

Thank you for your words but can you tell me what ions conducts electricity but remains uncharged?

[@Rantofthings.]

Not clear on the 4OH, where did it come from. In the electrolysis of very dilute NaCl,

[@csecchemistry]

In order to figure out what happens at the anode or cathode you need to first identify what ions are present. Once you see the word "dilute" water is present. Once water is present you have the ions H+ and OH-. Since you have very dilute NaCl, you will have OH- ions present in solution.

[@Rantofthings.]

Ok , Since it's dilute there's obviously be a higher concentration of H2O molecules, So what happened at the anode was the formation of water and hydrogen gas so 2 water molecules was used. (4OH). I understand now.

[@Rantofthings.]

Ok , Since it's dilute there's obviously be a higher concentration of H2O molecules, So what happened at the anode was the formation of water and hydrogen gas so 2 water molecules was used. (4OH). I understand now.

[@Rantofthings.]

.I love your videos, it helps a lot very concise in your approach. Thanks and God bless.

[@csecchemistry]

No problem.

[@Leevon656]

kzbin.info/www/bejne/mH2lhpesfM6BhLs Im wondering in the concentrated NaCl you had H+ and Cl- (HCL) instead of Na+ and cl-

[@Leevon656]

ps exams are tomorrow

[@Leevon656]

I literally paused the video at that moment so i didnt see the fix , keep up the good work