CSIR NET & CUET 24 | General Aptitude Short Notes of Divisibility and Simplification By Gp Sir

[@shadowshadow274]

Since na=a^2b and mb=ab^2 Then multiplying both number we get, Mn=a^2.b^2 So m^2.n^2=a^4.b^4 Hence option B is correct answer.

[@RenuVashisth-bu8ey]

B option sir. Thanku once again

[@arbazvayani9253]

For question 2 There is another way : The formula for the sum of squares of the positive integers is Sum= ((n^2+n)(2n+1)) /6 Which implies (n^2+n)(2n+1)=6*sum Which means (n^2+n)(2n+1) is a multiple of 6 and hence divisible by 6.

[@uniquemajak]

Best quality ❤

[@RPclasses2024]

Best explanation Sir

[@cheshthadewangan1234]

Apki sabhi video helpful rhti h

[@mandavisahu4582]

B options is correct sir jii 🙏🙏🙏 and very helpful series 🙏🙏

[@anuragpandey4912]

Ans - B Time taken - 5 sec Thank you so much sir 🙏🏻🙏🏻🙏🏻 Aap ki sabhi video help full rahti hai

[@vrvaghela99]

Thank you sir Ans : B

[@cheshthadewangan1234]

Thank you so much sir ji 🙏😊

[@neetusaini492]

Thank you so much sir🙏

[@31_snehakabra80]

Answer: B

[@Ripjaws3199]

Sir please ap csir ka aptitude karwaiye plus mein.

[@rahulrohilla3906]

B😊

[@parulsingh-bk7vn]

option b

[@mayankmak3414]

sir plz explain the answer of comment box qns

[@shivanichoudhary374]

B

[@manisharana265]

B take 15 second

[@neerupal3461]

Sir exam kb hoga CSIR net ka

[@anupriyafagoria6887]

6to8june

[@MMJha684]

B