Second last step: you need to use "continuity" of ln(x). (Because:with still finite x/h the term in the ln is not yet 'e'). BTW: I love the way you are presenting this explaining every step (in a calm and friendly way). Most teachers try to do it in a hurry. That is the main reason, why some students get annoyed with math.
@temporarychannel9759 Жыл бұрын
the enthusiasm made this really enjoyable to watch, great job
@averagestudent522211 ай бұрын
This guy turns math into magic
@SpiroGirah3 жыл бұрын
I never thought of this! Good job!
@barthennin6088 Жыл бұрын
Beautiful! 1st time seeing this truly from first principles!
@boguslawszostak17846 ай бұрын
If you define ln(x) as the integral from 1 to x of 1/u du, you have no problems computing its derivative. It is equal to 1/x by definition of the function.
@Th3OneWhoWaits9 ай бұрын
8:58 as h goes to 0, "n" or x/h goes to infinity. Thus, lim as h goes to 0 = lim n goes to infinity.
@ecSruthipriyaMahesh6 ай бұрын
I really like your classes, thank you for your hard work! 😃
@manoharkanade7383 Жыл бұрын
Very good explanation ❤
@wira256210 ай бұрын
It's very useful to understand the inderivatived integral of dx/x sir!
@robertveith63834 ай бұрын
Use grouping symbols: (dx)/x
@sldw3221 Жыл бұрын
Hello sir, i'm seeing that we always using definition of e with limit while proving all of these formulas but is it actually possible for you to explain or prove how or why limit n->infinity (1+1/n)^n is equal to euler's number? Did you record a video about this or would you talk about that in another video if it's possible? Thanks
@Harrykesh6305 ай бұрын
just a suggestion 😁 It might be too late to point out but, you could have started by first proving that ln(x) is indeed differentiable by Left and Right hand derivative then go on to find it.
@surendrakverma5558 ай бұрын
Very good. Thanks 👍
@EliiiAkotha6 ай бұрын
Great job
@elai31472 жыл бұрын
5:31, as h goes to zero wouldn't x/h go to either positive infinity or negative infinity?
@xavierwainwright87992 жыл бұрын
This works because lim x-> -inf (1+1/x)^x is also equal to e, but I don't know any proofs without using the derivative of ln(x) (this would be circular reasoning).
@cblpu5575 Жыл бұрын
Recall that the domain of ln (x) is **positive real numbers only** hence x/h is a positive real number x divided by a quantity h tending to zero
@alexdcruz36827 ай бұрын
Love your videos
@nellwackwitz3 жыл бұрын
You are AWESOME!!
@nichodimuszishiritinashe83292 жыл бұрын
You are the best
@wilsonhicke55985 ай бұрын
Love this
@samwelkariuki31142 жыл бұрын
Always the best teacher.....what about 1/x
@PrimeNewtons2 жыл бұрын
Thanks
@EternalScienceAndTech11 ай бұрын
You are a great man
@sandraboateng5435 Жыл бұрын
😍😍👌👌✊✊👍👍
@hassanejturay2994 Жыл бұрын
Awesome
@salamalmudarris50322 жыл бұрын
But n is integer while x/h is real number?
@festusemmanuel2111Ай бұрын
Wow ❤
@katiatzo Жыл бұрын
BRAVO
@januszek176010 ай бұрын
(1 + 1/(x/h))^(x/h) is not equal e
@Artemis1855-k4w2 ай бұрын
as h approaches 0, x over h approaches infinity, if you replace x/h with a variable it's more legible
@holyshit922 Жыл бұрын
He missed step when he used fact that ln is continuous