Graphical convolution example

Learn how to apply the graphical "flip and slide" interpretation of the convolution integral to convolve an input signal with a system's impulse response.

[@gunther3480]

11 years later and this is one of the best videos I have watched over the past few weeks studying for my exam.

[@flame19931rs]

that made so much more sense than the 1000$ course i paid for at university

[@boygood4176]

exactly (from s.korea)

[@ramonneira8910]

Same from Evanston

[@Sebas_Cba_82]

Surely!!! Even in many first world countries they will charge you thousands of dollars to teach you, when knowledge must be free and free! Luckily that is one of the good things about my country, and that in some time I will receive my degree as an Electronic Engineer without paying anything but my taxes. Greetings from Argentina.

[@emrekazoglu4154]

Do you really pay to learn these kind of useless things lider shame on you

[@MexterO123]

You explained what took 4 class lectures in a 11 minute video. Thank you. :D

[@kitetenjo6538]

yellow pony is best pony.

[@chillingmeko]

Kite Tenjo Indeed. :D

[@dezajno]

Memo Pony And it could be explained even shorter - At least the fact HOW convolution works - However, WHY convolution works and why it is so powerful, is quite hard to understand in my opinion - At least, I am not able to find any good information on that. So either it's too hard to understand, so people are just fine with understanding HOW it works - or I am simply too dumb to understand why convolution works and is so useful.

[@Jeankuhne]

In despite the clear explanation, which is great by the way, the video totally succeed due the use of a non ordinary example! Most of the books explain continuos convolution using step and exponential functions. This is the first time that I can see a convolution example using a ramp function as h(t). This is really a good job and really helped me a lot! Thank you very much!

[@sheepman6291]

I was blown away by your example. Now this is teaching.

[@kyrinky]

Out of several videos I have watched since the morning (6:00AM) until now (7:00PM) hands down to this one. It explained the concept crystal clear. Well done, sir!

[@mensahrichard2659]

Man!, I wish I had you as my lecturer. You are marvellous, Keep doing that

[@PriyankaSharma-um8it]

Mensah Richard

[@RickopotamusRocks]

Thank you so much! I've been having a hard time wrapping my mind around this graphical method. Your animation was incredibly helpful!

[@rubytski]

Very clear explanation and nice graphical representation. Thx! you seem a talented teacher.

[@trandrew96]

This has been the most helpful video I've seen on the subject. Thank you!!

[@samueladade8746]

Best video explaining convolution. Superb job!!!

[@BoZhaoengineering]

This video is cool! we are born to recognize shape and geometry.

[@astrokits]

And I finally understand what convolution does, and the role of h(t). Thank you! I was going to memorize because I couldn't understand it!

[@vandal144]

Superior in every way to my professors explanation today. Thanks!

[@ntspress]

At 5:38, the downward-sloping ramp function needs an offset (the +1) to make it have a value of 1 when time t=0 (see the given signal shape at 1:11).

[@RafaelAcurcio]

Really usefull video. Congratulations.

[@otoalves3797]

Tb achei

[@ryanmiller3877]

Perfect explanation, that cleared up a few things. Thank you very much!

[@NguyenHieu-dc1dc]

Oh man! This is really good. Thank you NTS!

[@RohanVats]

Thanks mate, I've been using this method thanks to you - seems to work everywhere haha!

[@Andrew-jw2qs]

Incredible explanation

[@ntspress]

The "flip" is part of the mathematical definition of convolution, and generally makes a difference in the result. An exception is when the "flipped" waveform already has even symmetry, for example a triangle ramp that goes up and comes back down at the same rate (even symmetry means you can flip the waveform about its center value and it looks the same).

[@influential7693]

Hi man, I just wanted to know, of what all to know before learning convolution pls let me know and your. Videos are really helpful for my college thank you so much ans God bless

[@ntspress]

At 8:13... we need the equation of the downward-sloping line between t = 1 and 2 seconds. Projecting this line back at t = zero means that the line hits the vertical axis at 4 (this is the y-intercept). Even though the line does not actually extend up to this value (because x(t) is constant in the 0 to 1 range), you need to write the function that describes x(t) during the 1 to 2 second range. Hope that helps!

[@sayantansaha6271]

why does the interception is 4? Shouldn't it be 2?

[@sarahfricano6476]

what program did you use to visualize this?

[@مصطفىعبدالجبارجداح]

بارك الله فيكم وجزاكم الله خير جزاء المحسنين

[@ntspress]

Thanks, Jean, appreciate your comments!

[@MA-qi2gr]

Can anyone tell me how to determine the regions for the integration? I mean based on what?

[@meghapanchal4760]

In which application you have plotted this graphs???

[@romanonosovski5455]

thanks for the video, the flip and slide is clearly explained

[@SuperFTH1]

Thank you very much! It's been really helpful for me.

[@praveen3133]

tell me what is the software you used for that graphical convolution

[@LailahaillahChannel]

can u please explain why did u not change the eqn while ur h(-taw) is positive slope.. for me while h(-taw), eqn of line is = (1/3)taw+1 and after shifting it while h(t-taw)= (1/3)(t-taw)+1. please correct me if i am wrong...

[@ЛеоМесси-в6г]

Tell me please, what program do you use to get the convolution when you move the inverted triangle along the axis? Is there a program in free access? Thank you in advance for the answer.

[@alexanderhempfing7584]

Thank you very much for this video, great! I am wondering: Can you tell me please which tool you are using to show the graphical convolution? Did you program it in Mathematica or an other program? And if Mathematica: Is there already a tool to show this type of analysis?

[@ntspress]

Used Maple for the animation.

[@simpletwo4768]

This video is really helpful! Thanks for sharing!!!

[@funkerific13]

Awesome, thank you for posting! This helped me greatly with understanding convolution! Subscribed!

[@MissionFitnessCTC]

Great video! Thanks for posting

[@gharamalsnayyan4446]

Hi, thank you for the explanation. It was would have been better if you described how to mathematically obtain the interval, rather than just showing it graphically.

[@mariacorcoran9069]

this is the best video

[@prof_dos_anjos]

Very interesting! Thaks a lot!

[@harshitpatnaik6381]

can anyone xplain me when t

[@MrExspectator]

Learning is wonderful again!

[@rickjames8960]

Awesome. Great presentation. Keep it up.

[@fggcreed]

thank you so much sir. I am at my wit's end right now

[@danielyoung6067]

This was a beautiful explanation

[@Rconrchea]

Excellent video, thank you!

[@FakeNorris]

Very helpful thank you! But would the same result be presented if you would'nt flip it in the beginning ?

[@murtujamim5031]

Very helpfully class

[@pikofix]

Thanks, it is a great channel, keep it going!

[@MeneerPANtoffeltjie]

Awesome demonstration! :D

[@beserkergaruk]

this was very helpful in understanding the concept thank you

[@justinlynch6691]

OH my god you have saved my GPA.

[@suidisla]

Great explanation, thanks. However, I still need to know how to apply this to imaging systems.

[@jinhuaxiong9327]

at 8:10 , why is the intercept 4? I do not see it, please help !

[@kyrinky]

For future students wondering how, simply use the slope formula and slope intercept form to find the equation of the line.

[@Error404fucknickname]

Imagine that section from t=1 to 2 of x(t) alone, and then picture it extending in all the domain of t. This new line function would be x1(t)=-2t+4 when extended, but if you took only a piece of it, from 1 to 2, it'd still take the same equation to describe it. Hope it helps!

[@salpanahi]

what if the regions aren't simple and obvious? How would you determine your regions for the integration then?

[@Error404fucknickname]

Sal Panahi you take longer finding them out hahaha Or use Wolfram Mathematica :P

[@ThomasTurkington]

Really appreciate your work! It has helped immensely! I have a question, if you don't mind... At 5:23, you needed to find an equation for h(t-tau). You developed this equation from the original, unmodified version of h(t), that is a ramp with negative slope. Why did you use the original h(t) instead of the modified version, h(t-tau)?

[@tilextalex4652]

+Thomas Turkington He just came to a point, where he needed to insert the function of h. Using h(t) or the "modified version" h(t-tau) is just playing around with the argument of the function. So it's straight forward to just look at the shape of h(t) and think about the function definition, which will just give you a simple linear function as you are used to work with. Without any other constants or variables to take care of. Once you have the function of h(t), you get the function h(t-tau) by inserting "t-tau" for every occurence of "t" in h(t). That's it :)

[@trandrew96]

Thanks for this

[@kyrinky]

Well explained.

[@WalterParsons]

This helped so much! Thank you!

[@sakeekawsar4003]

thanx a lot!! the video is very helpful!!

[@axelsenn920]

Thank you!!

[@reynaldorodriguez5237]

WHERE HAVE YOU BEEN ALL MY LIFE????

[@cu7695]

Why did you take inercept as 4 ?

[@dedded6805]

hi ! please tell me why we must turn around h(-t)? for what this is ? please explane..... what happened if dont this is .... ( iim sorry if i did same mistakes in my message ... just im not English speaking person)

[@Soggemann]

Great video. Thanks.

[@SheilaAmalia26]

thank you so much! it helped me a lot!

[@zeby638]

Thanks!

[@Capibara1]

very well explained!

[@whisperywind8768]

extremely helpful! thanks!

[@mohamedashraf4516]

thank u it's very nice and helpful

[@azhadzuraimi394]

thanks so much sir , it's helpful

[@GPMahendra]

really an useful video

[@chandulapadmasiri1848]

Thank you so much!!!

[@Error404fucknickname]

Shit, man, you explained it perfectly. Thanks quite a lot.

[@MontanaPreston]

Why is it t-3 at 10:00 and not t-4? Can someone please help me? Thanks!

[@josephwheelerton]

Amazing thank you

[@manassematondo6172]

Pour la première fonction comment vous avez fait l'expresion analytique il semble que je nai pas comprit du tout

[@ChriiSchee]

How can I estiamte (without caclculations) the red curve as a product of the other two ones? Thanks

[@kiranmathews1953]

can you explain the convution in network calculus please?

[@cornelone1982]

excelent ... thank you

[@jaran035]

Why is -2t + 4 ?... i get the -2t part but i dont see how 4 is the y-intercept ...?

[@sleeplezznightz]

@2:02, no one explains where this t comes from and why is it on the tau line.

[@williamswade6968]

where do the h go once you drop (t-T) in for t.

[@ssater2369]

Can you please do one example with a sin(pi/2 *(x-1)) and same h(t -T) in this example?

[@ishkhann]

Thank you!!! :D

[@safeegull22]

sir how you get the ramp

[@gmailuser7449]

in the 0,1 interval we get Parabolic function 7:15. but we can see on the simulator that it is straight line and i allso draw the function and im getting parabolic line

[@ntspress]

Hi Jan Be -- The red curve straight line at 3:44 shows only the *product* of the two functions, not the convolution result. The parabolic function at 7:15 is the *area* under the red curve which is the convolution result in this interval.

[@gmailuser7449]

***** thanks alot.like your chanel.good job

[@bizzaaach]

I picture convolution as a square with a diagonal (not the (x,x) diagonal, the other one). Fight me.

[@ghilashamaili2733]

i just had this one in my test exactly same , and i did it wrong ,despite of having watched it before because i only watched and didnt repeat it on paper.

[@someone2879]

Well, you learned a lesson from this experience! Hopefully your next exams will be better... Good luck

[@rezvanehaliyari9895]

رضوانه علی یاری

[@hellmuth26]

the integrals are too complicated, loses focus on the actual convolution.

[@МихаилХамхоев]

amazing, im not so stupid :D

[@alimuqaibel7619]

Check also the following related video kzbin.info/www/bejne/mIapp2qLhcapocU

[@2009abdola]

the second part of the input i think it's -2t+2 you made it +4

[@ryanyoung2035]

you know the slope is -2 and the x intercept is 2, so for y=mx+b we have 0=(-2*2)+b, b = 4. so y=-2x+4

[@2009abdola]

oow right. thanks for helping :)

[@shivamutreja6427]

mistake; when t is negative, the curve will slide to the right.

[@huseyin.goktas]

you flip before sliding. this means when t is negative it slides to left.

[@Andrei-ds8qv]

So you must first slide, and only after you ahve slite it by t you will reverse it, right? If you do this, a very big negative t will bring your signal to the far left(first you bring it to far right, then flip it and it will go to far left) insted of brnging it to far right , is it correct?

[@vewmet]

Oh, i am the 666th person to like this- I am from illuminati

[@igbt1986]

THANK YOU !

[@vraeleragon92]

Thanks a lot!