Discrete Time Convolution (Tabular Method)

[@conceptstudy5946]

y(n) = (2,-3,4,-2,1)= 4 is the value where the 0 is place

[@acn535]

What? Where's this y(n)?

[@Deepak-ip1se]

homework problem@@acn535

[@eswarabhi999]

I really thanks to neso ,because such a good staff is teaching us❤️

[@viveksingh7388]

y[n]={2,-3,4,-2,1], 4 is at n=0.

[@evan3678]

No, -3 is you just mixed up -3 and 4.

[@neeltej4123]

@@evan3678 wtf r u saying

[@vemulamanojkumar3588]

I never forgot your help my dear brother god always bless you 🤗🤗🤗🤗

[@harishgajjar9559]

A lot simpler method than Graphical Represent method. Thanks sir.

[@maryammoghtaderi3456]

Never heard of such a straightforward method before, and WOOOW! 😍

[@philipthangngat2758]

Thank you so much sir, Im taking signals and systems 1 atm, wouldnt be able without ur videos, thank u again and love ur channel

[@kaviprashanna]

what do u do when the number of values for X1 and X2 are different, u can just put 0 for the the less numbered signal but how do we know if it should be on the left or right?

[@s199h]

Thank you Dr. so much 💕 Your explanation was great👌🏻

[@ersmilata6014]

thank you so much. my professor makes this as convoluted as possible in class

[@MegaBlabla45]

This method is a lifesaver. Why don't they teach this in my uni

[@ScientistRenzo]

Thank you so much for this video and the other video about discrete time convolution. They were great!!

[@weneedabeats9750]

This video Save my life

[@inquisitiverakib5844]

great video indeed !! but a little doubt that is as convolution is performed here, don't we need to flip one sequence ???? then do the rest of the thing

[@s199h]

y[n]= {2,-3,4,-2,1} ↑ Is it correct, Doctor?

[@aashman_40k]

yessirrr!!!

[@nitigyajoshi4658]

yes, i got same answer

[@abhimannu6077]

Yes answer is absolutely correct

[@samuelkorvie4737]

I got the same answer

[@reetomranadutta7902]

Center will be at 4.

[@Many-ge7gv]

You have motivated me to practice and learn Digital Signal Processing, your job is very great and excellent thank you so much. Appreciate it from you. Keep up and please keep up the good work. 🙏🙏🙏😃😃😃 You really motivate me to always learn my lessons with you.

[@Muhammadsleptwithayesha]

Thank you sir that was very helpful ❤

[@swatantrakumargupta2283]

really they done a very hard work......... thank u..

[@got624]

Very good content really so helpfull

[@ashenafizenebe6135]

y(n) = { 2, -3, 4*, -2, 1} ,,,,,,tnx sir

[@alihassnain2513]

is this method only applicable only when we are given values of discrete system or we can also use this method for given equations of x[n] and h[n] ?

[@ersmilata6014]

think you have to do ztransform is you dont have discrete sequence?

[@空-x2h]

Thank you so much 💕

[@RobertoRufinojr]

Excelente aula!!!!!

[@prajapatiakshay861]

Thank you brother my doubts is clear how to find origin for different situation .❤️❤️

This was on the FE exam for electrical engineers...

[@ey_imran]

this help me a lot. thanks

[@hazratali8563]

great work broo. i love u

[@fayaqkirmani]

Is it necessary that no of rows should be equal to no of columns

[@leolo3540]

that's very helpful

[@parthmodi5734]

Please complete analog electronics also

[@bltnbros122]

Thank you, and what is the procedure if one signal has 5 values and the other 4 values And dont have the information of n=0 (no arrow pointing)

[@swatisahu936]

Y[n]={2,-3,4,-2,1} (2

[@priyanshuranjan1986]

yes same but many of them are posting at 4 the arrow

[@riseabovehate9476]

Then what is Matrix method ?

[@shubhamballal2662]

If n=0 is not given or represented in given problem then how to find it

[@mixzonelive1516]

thank you sir

[@AzagloDillys-uo9sp]

Thank you very much sir..... Please I want to ask if y(n)={-2,-1,0,3,2,1,8} and x(n)={4,-1,1,2} find the system response h(n) How would I go about it...... thank you

[@aidanzsebenyi5286]

did you ever find out?

[@letsthink7664]

y[n]={2,-3,4,-2,1} n=0 at 4

[@shilpagopakumar4984]

Thanks a lot

[@allanraju1570]

y【n】 = { 2,-3,4,-2,1}

[@ehsanulkarimtalha9821]

should I do padding if the size is unequal?

[@vinayakkarandikar8493]

Hello Neso academy. Is there a reference (a book/article/paper etc) which i can cite in my report (i need citation) for the above tabular method. Thank you.

[@rutweakchacha1558]

Signals and systems by A Nagoor Kani. You can take this book as a refrence

[@abhimannu6077]

Y[n]=(1,2,4,6,8,8) then intersection of x1[n],x2[n] is 8 then which one is X(0) is please give me reply

[@maheshraina3606]

Thanks

[@mariammostafa7261]

thank youu !

[@NazmulIslam-oz4re]

y(n)= (2,-3,4,-2,1). 4 is the valu of zero.

[@huyphanducnhat1609]

thanks,the method work in the exam but the professor only give me 25% ,he didnt accept this

[@PrathamGupta-hl6yw]

Y[n]={2, -3, 4, -2, 1} where 4 is element when n=0;

[@vivianrickyjohnson7121]

N value is taken as per our wish

[@noonnoon6071]

Good

[@jheelgala6353]

this isnt te tabular method. this is the matrix method

[@Ssh-ml4yt]

is it tabular or matrix

[@shanks-tx8xu]

I thought this was matrix method

[@parthaguha4705]

Its a matrix method not tabular..

[@rationalthinker9612]

Sorry but this doesn't seem to work in all case. Try the following example, it fails: x[n] = d[n] + 2d[n-1] - d[n-3] , h[n] = 2d[n+1] + 2d[n-1]. If you do the tabular method you end up with y[n] = -d[n+4] - 2d[n+3] + 2d[n+1] + 3d[n+1] - d[n-1]. That answer is incorrect, the true answer would be y[n] = 2d[n+1] + 4d[n] + 2d[n-2] + 2d[n-1] - 2d[n-4]. If I found one example of where it doesn't work, there's bound to be infinitely more.

[@alex1357in]

i got y[n] = {2, 4, 2, 2, 0, -2} with this method

[@alex1357in]

How did you get y[n] = -d[n+4] - 2d[n+3] + 2d[n+1] + 3d[n+1] - d[n-1]?

[@BayeMoke]

why didn't you make the video short we don't have such a time also looks like you are tired be energetic

[@shaikvasim6122]

😍😍😍😍😍♥️♥️♥️♥️

[@abhisheksinghkushwahaiiitd4215]

LoL

[@deeprelaxing7071]

y[n] = { 2, -3, 4, -2, 1 } ⇧

[@loveof30]

Thanks so much