Discrete Time System Output Example

[@عبدالرحمانمحمد-ح3ر]

Excellent 🎉

[@iain_explains]

Thanks 😊

[@lucidasser7153]

In the other discrete conv. video we can see the equation, it is always a summation. Obviously, we do not add up. I think with summation, we would get y(n)= 3x1+3x1= 6 at the point n=3 and at n=4: 3x1+3x1+1x1 = 7.......but I must be wrong(?). Thanks a lot.

[@iain_explains]

Sorry, I don't understand your question. At n=3 the first impulse has been inputted to the system (ie. the delta[n-2] function, which has its energy at n=2, and results in an output step function starting at n=2), but the second impulse has not yet been inputted to the system (ie. the delta[n-4] function, which has its energy at n=4). So the only output at time n=3 is the result of the n=2 delta function.

[@mhdabb9554]

Sir system have values at n=2 and n=4 am I right pls

[@iain_explains]

Hopefully this video will help you to understand: "Discrete Time Convolution Example" kzbin.info/www/bejne/gXKye6aneN6Xa7s

[@theengineer9910]

Thank you

[@iain_explains]

You're welcome