Field due to straight wire carrying current (Outside) | Moving charges & magnetism | Khan Academy

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THANK YOU FOR THIS AMAZING LECTURE

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sir, thank you very much.

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[@kaabdulrahman6980]

I have doubt that B is total magnetic field of total loop or B is magnetic field in particular point

[@BadDio]

It's more like, B has same value at each and every point of the circle, so even if u say B is the total magnetic field of the total loop or at a particular point, it's the same thing

[@rajeevranjan8330]

B is the total magnetic field of the complete system

[@Rajesh_Sutradhar]

Wonderful

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Is there a video where B is calculated by biot savart law?

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[@niranjan7457]

Sir at 02:48 You mentioned that, as all the points in the circle are equidistant from the wire, all points have the same magnitude of Magnetic Field. But, you mentioned here (kzbin.info/www/bejne/f2m7YnimfcSJh7sm40s) that the magnetic field in not the same for all points on the circle. I assume, in the current video video, that as the angle between the current and the displacement vector is always 90 degrees, (since the current wire pops out of the plane of the screen, and all the points on the circle lie on the plane of the screen ), the magnitude of the magnetic field at all points on the circle is equal. Please clarify this sir

[@KhanAcademyIndiaEnglish]

You are right, the circle here is perpendicular to the plane of the wire, and the field is same in magnitude everywhere. But the circle that other video is in the plane of the wire, and the field is only maximum along 90 degrees to the wire element

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