Fingering of mosfet

[@arghyasingharoy1902]

Thank you for clearing the concept!

[@NABEELNAJEEBKASSIMBEE]

Good work!!!

[@02chandani]

Thanks for nice video lectures. Kindly upload the lectures on other layout techniques also.

[@atlurisaikanth6105]

please can you upload more concepts in analog layout

[@thotapraneeth9173]

please upload a video on common-centroid layout

[@sagarkore9648]

Hafeez very nice explanation. Thanks for the information you can add some more video. which will help to get idea of analog layout concepts. I guess fingering also helps to reduce the capacitance also (along with gate resistance) since we are sharing drain/source of both the devices.

[@socialogic9777]

can you make videos on multiplicity of mosfets.

[@pavankumarkori715]

Sir when you upload your common centroid matching video

[@anchorman3250]

Hi Hafeez, Thank you. Can you explain how increasing the gate resistance will increase noise as well? Won't increasing the Gate resistance decrease noise input to an analog system?

[@mohammedafzal534]

No the resistance depends on poly if divide the poly then resistance also divided then how it could be same as the non divided poly resistance

[@leolektor]

Hello Hafeez, thanks for you videos. Is there any possibility to simulate this gate resistance, for example to make sure that it's really reduced by fingering? Actually I want to use this gate resistance, so how can I get the gate resistance of MOSFET?

[@faiqtwilight]

can you please guide how to install cadence on linux

[@volleysmackz5960]

Decreasing width will increase resistance from R to 2R of each dividend of large mosfet and effectively it remains same for 2 W/2-mosfets in parallel

[@mohammedafzal534]

While we divide the total width into number of fingers then the gates are connected in parallel, in parallel resistance would be decrease

[@volleysmackz5960]

@@mohammedafzal534 connecting resistances in parallel will decrease the resistance but when we divide the gate into equal pieces, each piece resistance would be more than the original one. So putting every piece makes equivalent resistance equal to the original resistance.

[@volleysmackz5960]

@@ahmetyusufsalim Length is not equivalent to width, width constitutes for area. So on decreasing width, area also decreases thus increasing the resistance. PS: I don't exactly remember the context, have to re-watch the video. But that's what I think now.

[@ahmetyusufsalim]

@@volleysmackz5960 sorry my bad. I completely ignored the area.