Fluid Mechanics: Bernoulli Equation Examples (6 of 34)

[@dianapereo8383]

All of my classes went online due to coronavirus... and you sir are a lifesaver. These lectures are better and more in depth than actually attending class.

[@SeekTheTruthAndTruth]

Happy learning:)

[@manuelbascolo6675]

It is a pleasure to study fluids with this professor. I am taking this class online right now. I literally follow these lectures more than the one given by my professor.

[@ronaldinho4eva1]

I am taking fluids online this semester due to Covid and my professor was so bad at teaching that I pretty much gave up. My finals were in a week and I started reviewing with these videos and my opinion on Fluid Dynamics as a subject has completely reversed. A good teacher is something close to magic. Many thanks to Professor Biddle.

[@calilife5392]

Why other professors dont teach like this? They make education more hard for students. Thank you Professor

[@koonlocker]

@39:03 For anyone wondering why v = 13.9 because change g unit m/s^2 to ft/s^2 the equation be Sqrt(2)(32.185)(8-5) = 13.9

[@aashna4457]

THANK YOU

[@tarekkhawam1092]

You are so calm and explain every thing very well. Each time I have a question you answer it right after. Would love to have had you as a professor

[@CPPMechEngTutorials]

He's one of our best.

[@MisterBinx]

Thank you for explaining the stagnation point better than my book did. Makes perfect sense. Many times books just assume it's so obvious and I get hung up on little details like that.

[@azzamklc7664]

I can see the light on your face Professor. What a precious video series!

[@SeekTheTruthAndTruth]

What a calm way to teach. I wish I could have been you student.

[@CPPMechEngTutorials]

Very calm, even after drinking so much coffee. :)

[@mehdi.sajadi]

you're amazing man, thank you so much , I wish our professors could teach like you, then we didn't have to search in KZbin to learn

[@afhamanam4279]

honestly i learn more through his lecture then in class

[@loveen3186]

you teach better than all lecturers combined wow

[@isee8034]

For SI people for q1: 25 psi = 172369 pa. For R the 1.242 x 10^6 = 2.077x10^3. 40 Fahrenheit = 277.594 Kelvin. So curved p, 5.8x10^-4 = 0.298459. 2.3 inch = 0.05842 Metres. Water density is 997 kg/m^3. V = 61.836 m/s = 203 feet per second

[@mohamadhoseinf1560]

I wish I had a professor like him

[@muzamilnazirmalik619]

Magical. You are Legend Sir. I wish my teacher was like you. Thank you @CPPMechEngTutorials

[@누가꿀떡을먹었나]

What an amazing lecture..! i really want to express gratitude to professor! and thank you for making the subtitles! easy to follow the lecture :)

[@CPPMechEngTutorials]

We're glad the subtitles are helpful.

[@muhammedeminural3333]

@@CPPMechEngTutorials they really are

[@MisterBinx]

It's interesting in the siphon example we didn't know the pressure at the entrance to the tube because the fluid was moving and not hydrostatic. In this examples we know pressure of moving fluid because of the pressure taps. So you can measure the pressure at a point even if the fluid is moving as long as you have a pressure tap.

[@locom16deen78]

when you think about it you dont really need to do what the prof has done at around 15:00. previously you should know that when using manometers the goal is determine the pressure in the pipe. and in this case pressure at 1 = pressure at 2. so as he has correctly resulted to its just gamma(Water)*h

[@gemacabero6482]

Hi! Thanks for the video. I had a question on the last ex. around 1:02. You say that we can do Qin = Tout because water is incompressible and this is a steady state . But how am I supposed to know that this is steady state? Thanks!

[@darkerknight38]

@45:30 his "h" he wrote on the board is given as "2ft" in the text book. Just FYI peeps, so when you calculate it yourself, you will get an actual number for P4.

[@wowcoldboy076]

How do you find V 4?

[@wowcoldboy076]

I get a P 4 value of -437 lb/ft^2. Did you get the same answer? Thanks

[@darkerknight38]

V5 was found earlier in the video to be 13.9 ft/s. So, V4 = V5 = V2 = V3 = 13.9 ft/s P4 = -312 lb/ft^2 because specific weight of water(γ) is 62.4 lb/ft^3, when you plug into P4 = γ[ - (V4^(2)/2g) - h ]

[@MohitSharma-qh4wq]

Great way of teaching .... i can say that for me the best lectures of fluid mechanics . Thanks Dr Biddle from INDIA . DO you teach Aerodynamics as well .

[@CPPMechEngTutorials]

Unfortunately he does not teach a course just on aerodynamics. At Cal Poly Pomona, the ME and AE departments are separate.

[@spikes1529]

Sir, i am trying to calculate how fast a particle falls out of a fluid, you wouldn't have a lecture on this? Example dirt particle falls out of water.

[@rtrt2889]

Great lecture!

[@BhattTapasvi]

can you please share the name of the textbook being used and the edition too. It will be a great help!

[@BhattTapasvi]

Got it from the comments - Fundamentals of Fluid Mechanics, 7th Edition by Munson It is.

[@علويالقلاف]

If a pressure gauge installed on a pipeline, will it give a static P reading only or a total P( static P + equivalent v + static head) in its reading?

[@ashleyhallromero4336]

when you have an opening, when can you assume Pressure is cero and when can you asume velocity is cero. Thanks :D

[@locom16deen78]

i know its 9 months late but for anyone else watching. Pressure at opeing = can be taken to be zero unless stated otherwise. And at freespace you can assume velocity = 0

[@harshitmadhian2409]

I am confused, quoting the textbook "when streamlines are horizontal (like point 1 to 2 in first example in video), R = infinity and pressure variation across streamline is hydrostatic even though fluid is in motion". In hydrostatic, pressure doesn't vary in horizontal plane, so P1 should be equal to P2. but that's not the case, why ? I think I am confusing the concepts in my head! Pls explain. Thnks :)

[@NathanAlpern]

Last example. P2 is higher than P1. P2 is downstream of P1. How is it possible to have flow if fluid flows from high pressure to low pressure?

[@puizhistephenteu1885]

due to gravitational acceleration, or elso water wont come out from a pipe.

[@merveyldrm6923]

You are perfect sir

[@nhb2722]

I study at a reputable university, and I wonder why some professors cannot explain the concepts with as much clarity as Dr John Biddle does. Makes me wonder whether college ranking is a scam.

[@lollolzi2996]

Can you please explain in more detail as to how the the fluid is static in the tube as the professor stated in time 7:35? Is there water in that tube canceling out the helium fluid flow?

[@harshitmadhian2409]

initially when the manometer tube is entered in to the pipe (with water already inside), the helium will enter from the hole above point 1 and point 2. Helium flows INITIALLY and displaces water as shown but eventually reaches equilibrium and stops or you can say helium from both sides balances water in middle as shown in figure. Either way it reaches static condition. That is why point 2 is stagnation point (zero velocity). Hope you understand! :)

[@elchaflan100]

how did he came up with the picture? i looked at the problem 3.24 on the book and it does not provide the picure.

[@seanwilson8255]

When finding P2, how does z1=8 while z2=0? If z2 is the datum, z1 must be shorter than 8.

[@CPPMechEngTutorials]

Can you provide a time stamp?

[@carlosxbw4890]

kzbin.info/www/bejne/gKHRq4Wpacyjrq8

[@lazer2405]

From Z2 to the top of the tank is 8 ft. Z1 is located at the top of the tank, and is therefor 8 ft from Z2. Z1 and Z3 are in line with each other. A height for Z4 is not provided.

[@HitmanTanmay]

Consider the Datum to be in plane with pt.1 and then draw your axis downwards, you'll have solved it XD

[@jjaswal]

@ 16:21 how did Professor get the rho value to be 12?

[@chinesemediabox3823]

42:15 z2 is not zero old senile z2 = 8-3= 5ft.

[@josipatisaj9630]

Can I say that point 2 is stagnation point?

[@mohitsharma-iy6wr]

can anyone explain to me why the atmospheric pressure is taken 0 ?

[@ElPsyKongroo]

What is that static pressure, dynamic pressure multifunction manometer thing called?

[@jaimelomayno4152]

16:21 how come that the V1=203ft/s? What iam getting is 25.7?

[@hemantchavan4995]

Where we can get text book referred by biddle sir ...from india

[@frankniiodoteimensah3213]

have a personal problem to be solved for me. please can you help me.

[@LOVEAD2]

16:17 why was H divided by 12?

[@denn7621]

thanks for sharing

[@miked3020]

At 36:27 why does V2 not = zero? Isn't it a stagnation point based on the diagram that he drew???

[@entropyz5242]

Mike D only zero when going from less dense to more dense; here it is going from denser to less dense, so velocity not zero.

[@burhanhilmi1624]

@@entropyz5242 how to determine which is less dense and which is more dense?

[@Meeroo670]

at 23:10 the professor spontaneously want to laugh at the camera man 😂😂😂

[@aminhebal3984]

can you blease send to the textbook az pdf to take a look thank you

[@hopelopez83]

at 16:19, how did you get v1=203ft/s? What conversions did you use?

[@siamislam2466]

Unit weight of water 62.43 lb/ft³

[@bernardlee2921]

why is z1-z5 equals to 3ft?( the answer not 5ft?)

[@lazer2405]

Because Z1 is at the top of the fluid and Z5 is 3 ft from the top of the surface. Z2 is 8 ft below the surface. the difference between Z5 and Z2 is 5ft.

[@joninakiabaroaschilling2554]

thanks

[@PixieLavender]

At 42.27, If there is no Gamma, doesn't P2 go to Zero?

[@CPPMechEngTutorials]

P2 is not zero because it is below 8 feet of water.

[@NostalgiaT]

and what is free jet?

[@iitkgpnits]

Not sure if you are still answering questions. But how do we make sure that all the chosen points are on a stream line, for eg. at 19:29? kzbin.info/www/bejne/gKHRq4Wpacyjrq8

[@NostalgiaT]

from the 3 equations, how do u know which one to use?

[@leahgreene5880]

It doesn't matter which you use as they're all equivalent.

[@abdullahrajab9937]

@38:59 how is V5 = 13.9 i got 7.76

[@justinvarghese52]

isn't z2=0??

[@83-ahmadmurtazahameed45]

What book is being followed

[@CPPMechEngTutorials]

Please see the comments.

[@NostalgiaT]

what does incompressible mean?

[@CPPMechEngTutorials]

The density does not change significantly under compression and be assumed to be constant. In fluid mechanics, we usually assume liquids are incompressible.

[@A.Hisham86]

Google it!

[@NostalgiaT]

when can we say z1 = z2?

[@leahgreene5880]

When the two points can be connected by a horizontal line, i.e. their vertical heights z1 and z2 from some reference point is the same.

[@ibrahimselim8583]

?which book is that

[@grittayasrinaphasawadi817]

Fundamentals of Fluid Mechanics, 7th Edition by Munson

[@nurlatifahmohdnor8939]

24.39 litre = RM50.00 2.050 litre = _______

[@nurlatifahmohdnor8939]

On 4.8.2008 Monday, my 1st child was born at 2.05 o'clock after midnight.

[@ElPsyKongroo]

Imperial units, gross! :P

[@CPPMechEngTutorials]

They aren't going away in the US anytime soon.

[@isee8034]

I'm following along converveting lol. Fahrenheit to kelvin, psi to pa, English gas constant to universal etc etc. 5yrs on I feel your pain.

[@warren140]

48:21 loooooooooooool he was probably underpressure and gave a random answer

[@williamherrington491]

Mcdonalds pay you for that ad placement?

[@CPPMechEngTutorials]

Not yet. We wouldn't turn away a nice check though.

[@A.Hisham86]

V1 is an imaginary number! LOL

[@NorthernStarTeam]

Shouldn't the answer to first question be, V= 80.5 ft/s as apposed to 203 ft/s?