A video that clearly explains how to calculate flux due to linkages outside the conductor. This video will be more clear if you watch the previous video • Flux Linkages Inside t...
Пікірлер: 12
@milbronjames11 ай бұрын
finally starting to understand these concepts thank you!
@ChinmayaASV5 ай бұрын
Thank you.. Glad it was helpful...
@sreenivast52147 жыл бұрын
make video on concept of gmr and GMD sir
@twinklekisku50862 жыл бұрын
Sir final expression will be ln (D2/D1). Mistakenly u wrote opposite
@viveksinha55507 жыл бұрын
regarding internal flux linkage the value of current description is not clear
@aymanantoun88986 жыл бұрын
Can u please provide us some videos of practice problems to understand the theory inside and outside conductors please
@mohammedamir76598 жыл бұрын
why the magnetic intensity at x is not equal to fraction of current Ix
@ivjntuk97907 жыл бұрын
how you write d syi is equal to d phi directly
@gopichand50387 жыл бұрын
very helpful to me
@SHUBHAMGUPTAversion6 жыл бұрын
THANKS :)
@joshuaiyinkanmi3032 жыл бұрын
D2/D1 at the end sir not D1/D2🙏🏾
@robertfaney41488 жыл бұрын
again your use of the word conductor is the real confusion , it is not a disc conductor ! It is hollow area where the flux builds within a wire loop, am I wrong ?