Formation of hemiacetals and hemiketals | Aldehydes and ketones | Organic chemistry | Khan Academy

[@colejones6966]

I agree Khan is so hard to understand now. The tutors don't explain things very well. They just say "this is happening now" not, why or how - it just is.

[@VictorSirnesHegelstad]

Thank you. You showed it in a way that makes sense if I look at the hemiacetal group in a- or b-glucose.

[@cync1149]

thank you so much! I have been procrastinating on studying this topic until i see this video!

[@Swagnermite]

Great vid, explained much better than my uni professor

[@zhxilas7567]

dont you need to protonate the aldehydes first with acid or base? lots of literature say so because ROH is poor nu

[@estellaque8615]

used to love Kahn academy.. now the tutors talk all smarty fast... just like the lecturers we barely understand... sigh

[@estellaque8615]

it's neither fun anymore

[@MonkeyDLuffy-xr4fl]

There's an option to slow it down if that's what you mean xD

[@albrightaz]

Same here I don't understand

[@AlfaHanen1]

Thanks for u time, Perfekt.

[@titoflash1212]

Excellent for review

[@HS-jg8ti]

The first step of acetal formation is protonation of the carbonyl by a base.

[@LB-gw8gt]

I’m sorry this is not helpful at all

[@TheAmidons]

Can you reply and name the 2 molecules at 6 minutes so I can learn that a little better. Thanks!

[@Physmodus]

I believe the left molecule is 5-hydroxypentanal. The right molecule is oxane (tetrahydropyran) with an attached hydroxyl group, therefore 2-hydroxytetrahyropyran. I would recommend sites like pubchem or chemspider for looking up molecules. Happy learning.

[@Rkamal]

good explanation

[@corey5454]

He talked so fast lol

[@albrightaz]

Not understanding

[@AlfaHanen1]

learn the base first...

[@דניאלגליק-ו4ס]

you first protenat the aldehyde....guys khan akadamy are not perfect and they make mistakes,be carfull