Fourier cosine series of f(x) = x

[@donwald3436]

omggg I can't stop seeing you as Dr. Foreman from House!

[@markusmcgee]

Subscribing. Prime Newton is showing us the goods! Refreshing my Math degree by watching him lol.

[@mariag2916]

Love the chalkboard! ☺️

[@vestieee5098]

This was awesome, I'd love to see more videos about Fourier series from you, loved the previous one on sine series of x^2 as well! Also, would it be possible to make a video on how these formulae are obtained or is that beyond the scope of a KZbin video?

[@Ayoub-lv3yl]

Thank you sir Please continue

[@glorrin]

Hey this is so cool that means no odd function have cosine term in Fourrier series And by the same demonstration no even function have sine term in Fourrier series Which means (but that is obvious) sin(x) do not have cosine terms and cos(x) do not have sine tems

[@marvinochieng6295]

Mr Newtons, there is an equation that hasnt been solved. 1=16^{x^2+y}\:+16^{y^2+x} I would be happy to have it featured in your video

[@midhunmartin6627]

Hi sir, could make a video showing how to find the domain of f(x) = ((x+1)^2) /(x+2) ?

[@AurynBeorn]

If I am correct the domain of that function is all real numbers EXCEPT -2. x+1 is on the numerator and we're not calculating roots but, rather, an exponent, so (x+1)^2 is something that you can always calculate. x+1=0 when x=-1, but this is only a problem if it also makes the denominator to evaluate to zero. The denominator is x+2, which is equal to 0 when x+2=0, this is, when x=-2. This value of x makes for the denominator to be zero and so we must exclude it from the domain. Any other values for x give us something that we can calculate.

[@nournote]

You basically say that x=0 for every x in (- l, l)

[@PrimeNewtons]

If you want cosine terms..

[@yba7586]

Second

[@viktor-kolyadenko]

cosine series is 0.

[@comdo777]

asnwer=j isit hmm gmm