Free Fall - IB Physics

[@pavlovacat]

I love your videos so much!!!! we all appreciate you!! thank you endlessly

[@lucianagrimson4790]

Your channel is a boon to us IB physics students

[@lucianagrimson4790]

Thanks to you I pushed my 6 to a 7 this term! Super grateful!

[@kofiampo4085]

@@lucianagrimson4790 i hope to push it from 4 to 6 then 7

[@skiijamaa1611]

this was very helpful thank you!

[@MpitiLetsie-q2j]

pls remember to take the issue of significant figures in your calculations. thank you

[@yuenfong4959]

Great video! I was wondering though, how do we round our answers in physics ?

[@roshakchinapalli2969]

3sf for ib

[@yuenfong4959]

@@roshakchinapalli2969 Thank you!!

[@antonissak6297]

classic, thanks mate

[@numnumnum-b4e]

erm a dumb question but since the acceleration is constant, will one equation (if variables are known) be correct?

[@harshakatta3815]

why is it -9.8 for the second part of the last question its fallling down from max hight

[@harshakatta3815]

i mean the acceleration

[@numnumnum-b4e]

erm well it really depend on your frame of reference, but if you decide that falling down mean negative velocity(going opposite direction to the positive velocity), then acceleration of the faling down motion should be negative as well, -9.8 mean your velocity is increased by -9.8/sec per sec(the object accelerate faster negatively-or downward ) this could be all explained by doing a v-t & a-t graph

[@ESports-ps1ix]

from the 2.04 sec time to reach max height .do we not count the time as twice meaning going up and the down before i consider that one of the 50m height??

[@numnumnum-b4e]

erm i think you are right acording to motion graph

[@lovefad8504]

i'm in love with u