GCSE Chemistry Revision "Titration Calculations 2" (Triple)

[@szymonkuzniar6638]

Thanks u made it so easy to understand. My chemistry teacher literally over-complicated it so much. THANKS.

[@listen-music548]

Mines too, he makes me stress and panic over easy stuffs

[@izzygeorgia1274]

This guy deserves an MBE what a legend

[@yashaswar1973]

How come you haven't got like at least a million subscribers for explaining this topic under ten minutes? You deserve to be the Education Secretary

[@sadiqrebelo2866]

Real!!

[@omorrahman7491]

I like the new suit look somewhat dashing... great videos

[@name.surname.9707]

Corona virus student here you're actually acting as a teacher for me so I want to thank you for these videos as my exams are next year!!!

[@parthkapadia4948]

Same

[@archiefostr]

@@parthkapadia4948 are they tho

[@Qwazor]

@@archiefostr I don't know how it is with other schools but my school is still doing assessments in order to gather evidence. For example, I've got my chemistry tomorrow.

[@bigby4315]

ay bro how were your exams 2 years ago

[@Qwazor]

I always felt like I was behind everyone else in chemistry; I couldn't get my head around titrations. Now you've explained it in a different way it has really helped!

[@emily-sz4jf]

ahhh thank you so much! saved me again! I got all 9s in my chemistry biology and physics mocks and I'm pretty sure it's all down to your videos so thank you!! :)

[@Freesciencelessons]

Well done but I think it's mainly down to your hard work, with a bit of help from my videos. Good luck in your summer exams.

[@emily-sz4jf]

Gotham Rues thanks!! So I've been making groups of flashcards for each topic (i.e. B1, B2 etc) in quite a lot of detail. I put a question on the front and then the answer on the back so I really have to remember it. Then I just go through them thoroughly! Good luck with your exams :)

[@princess_naadirah9900]

@@emily-sz4jf what did you get?

[@ketchurself7979]

@@princess_naadirah9900 they probably got 9s

[@rab.j]

@@ketchurself7979 ye probably

[@RSS1350]

Hey man preparing for my mocks and I would love to say thank you for all the content you make. You probably will not read this comment but carry on what you are doing!!! You are creating so many opportunities for students

[@Freesciencelessons]

Hi. I read all the comments. Thanks for your message. I'm glad that you found the videos useful. Good luck in your mocks. I hope you get the grades that you want.

[@jedharendstrash]

what once seemed like one of the most intimidating things in chemistry has now gone down to something i could fully understand and remember in around 5 minutes of studying, all thanks to this video! you genuinely are a life saver lol i've already gone from bad at science to achieving 8s and 9s in my mock exams thanks to you!

[@mimahamed7337]

I'm in Year 10 rn and these videos are helping me with my end of topic tests too. This guy literally carries me and before, i was one of the worst students but now, i can get full marks on my tests.

[@chironplayz]

Give me a fat kiss because you saved my life with these types of videos!

[@owltea2252]

Just 2 minutes of this video made me understand this! Thank you so much for the help and might I say that red tie is fantastic with that suit of yours good sir!! :)

[@Freesciencelessons]

Thanks for the comment. I'm glad that the videos are helping you to understand. That tie is one of my favourites.

[@phase0400]

I have recently just had a biology mocks and your videos have helped me so much, now you are saving my chemistry mocks. Thanks your videos are so good.

[@uyusukadam4225]

I would like to thank you so much for the effort you put into these videos.

[@nerdstalk5748]

I just wanted to say thank you so much. You have made my revision so much more easier. Before this video i did not understand these calculations but now i understand them easily. I have got my mocks next week so i am hoping my revision and your help has helped me. THANK YOU!

[@harry4901]

Thank you Shaun for all of the work you do, you have really helped me understand chemistry and actually made me enjoy it. I have a test coming up next week and i genuinely feel confident that i have the ability to do well after watching these videos. Keep up the great work :-)

[@lilia_casburn]

very helpful :) and such an effective way of remembering - good luck with chemistry mocks all

[@The_Laplace]

709K young adults are going to attend this man's funeral.

[@abinayamathanarajah5267]

Thank you so much for this video on titration calculations. Before watching this I was always make a mistake somewhere but now I understand it properly. :):)

[@505am6]

This really helps with the basics in a level as well thanks

[@MH_2456]

It's also useful to put the ratios at the top of the chemical equation before you begin the question :)

[@ellabentley9697]

THANK YOUUU legit never understood this

[@sailor.mars7]

More difficult titrations always seem to stump me but you made this so clear and understandable for me. Thank you so so much sir! And, can I just say, that tie is amazing sir :)

[@elh9720]

this video is the reason i got an 8 in my chemistry gcse. i literally watched this video n learnt this finally seconds before the exam my exam has a 6 mark question about this in it

[@TajTaj-pj2bs]

Hello I would like to know how you got to the mol of the other acid. Did you divide/ multiply by anything?? But great videos you’re saving my chemistry grade

[@Aaminah-bu5gv]

i hated the practical of titrations and the titration calculations but you've made me into liking this topic because you made it so easy to understand:) thnkx

[@theohallworth2632]

this really helped me

[@stanellison2229]

Watching this an hour before the exam

[@sophieswann9283]

Thank you so much! I actually understand!

[@casinovathedon8924]

How much marks would these questions be? Titration calculations and percentage yield questions? And if it asks you to balance the equation will it be an extra mark? Thanks for the video, really helpful

[@Freesciencelessons]

The titration method would most likely be a six marker and the calculation maybe a four marker I suspect. Percentage yield perhaps a four marker. If they did incorporate a balancing question then that would normally be worth a mark.

[@casinovathedon8924]

@@Freesciencelessons Thank you so much sir i really appreciate it

[@JJ-ny7tq]

THANK YOU SHAUN ❤

[@naatlyricstv7990]

Thanks alot. You made this chapter easier than ever

[@yowassup4205]

Sir in the exam will we ever be asked to calculate the concentration of any of the products

[@hawazenmussa2639]

U made it so easy and fun to understand it thank u so much ur a legend

[@chemotokaula-ew1zn]

Following from Kenya 🇰🇪🇰🇪🇰🇪🙏🙏🙏🏆🏆🏆🎉🎉🎉

[@hs_0550]

Do we need to know how to write the symbol equations from the word equation given in the exam or will they give the symbol equation as well?

[@beauhamilton-smith2873]

Very helpful, I finally understand it, thanks.

[@ziczicon4267]

U know he knows what he talks about when he records the whole video with no cuts

[@hannahn5175]

Hey there, I would just like to ask whether the equation for the titration will already be written with the question in the exam?

[@daws5958]

Hannah N it will be mate

[@seraphblackburn1597]

If you get a large decimal number, to what decimal place should you round it to? 2 or 3? I asked this because you changed it throughout the video! Thanks!

[@Freesciencelessons]

Hi. It changed in the video because some calculations produce a number which does not need rounding but others do. To be honest, it depends on the calculation. If it's important, the exam question will tell you how many decimal places you need to round to.

[@sebastianel-homsi4017]

Hello Sir, at 2:45, we multiple 0.25 mol/dm^3 by the RFM (36.5) to get g/dm^3, but shouldn't we multiply that answer by 2 because the formula is 2HCl?

[@Freesciencelessons]

Hi. No we took the large 2 infront of the HCl into account earlier on when we worked out that we have 0.0025 moles of calcium hydroxide so we must have 0.005 moles of hydrochloric acid. After that, we don't need to consider the large 2.

[@Harjotsingh-hk3zb]

Will the question give you the balanced equation or the equation at all to work out the ratio?

[@Freesciencelessons]

If it's a titration, they may just give you the balanced equation since they're testing your ability to do a titration not balance an equation. However, if they also want you to balance the equation, then you will still be able to get the marks on the titration even if you balance the equation incorrectly (the mark scheme will account for that).

[@dunleavy0994]

Studying an access course to get into University, if it wasn't for your videos I would be lost.

[@r-white457]

4:31 This throws me off because in maths we were told never to round up before the question is over so I always use the non-rounded version to convert into g/dm^3 before rounding them both up. Would I lose marks for this?

[@Beesechurgersports]

Round it in your working, but keep the actual answer in your calculator so you have the exact amount. have a good day

[@tendaijakutindi4175]

Thank you so much for this, very helpful

[@peterpeterson125]

Great Video! what if it is 1M because my question asks 25m*3 of ammonia solution were neutralized by 20cm*3 of 1M sulphuric acid. calculate the concentration of the ammonia solution How would I calculate this?

[@Freesciencelessons]

The number of moles of sulfuric acid will be 1 x 0.02 = 0.02 moles. The equation for the reaction you are discussing is 2NH4OH + H2SO4 ---> (NH4)2SO4 + 2H2O. This means that we have 0.04 moles of ammonium hydroxide (ie ammonia solution). Concentration = number of moles / volume = 0.04 / 0.025 = 1.6 M

[@saffronls8101]

Could you please do one of these on limiting reactants 😊

[@Freesciencelessons]

There is one already. Just search my channel for limiting reactants.

[@willowmugglestone9924]

will we be given the relative formula mass of the solution we need to find the concentration for?

[@choco1026]

finally understand this now thx

[@Harjotsingh-hk3zb]

What if the ratio of the moles from the balanced equation is acid 3: alkali 2

[@Freesciencelessons]

Divide the number of moles of acid by 3 and multiply by 2 to get the number of moles of alkali.

[@lucy-qk4id]

Thank you so much! This was so helpful

[@Freepalestinefromisnotreal111]

Will they ask to convert into grams or do u have to do it by choice

[@Freesciencelessons]

No they'll tell you to do it if that's what they're looking for.

[@szymonkuzniar6638]

ans also will the equation be balanced or do you have to balance it in an exam?

[@swaglife-mi5fh]

Great video!

[@swaglife-mi5fh]

Great video!

[@Hannnnnahh]

This is a great video thank you so much!! ☺

[@user-cn9pj3iw3s]

Do we times the big number in front of the compound (like the 2 in 2HCL) when calculating its relative formula mass?

[@Freesciencelessons]

No you never use large numbers when calculating relative formula mass.

[@mimicove1848]

YOU ARE AMAZING THANK YOU

[@edicross14]

When someone asks which chemistry teacher i have i say this guy

[@naatlyricstv7990]

Great video. But why you call zero "nol"

[@simranhans8806]

Hi sir, what does sub strip and coefficient mean? And what does it mean with this 2Fe(small 2 at the bottom)? Doesn't the small two mean its diatomic and there are two sets of them because of the two in front? I get confused with what coefficient and sub strip is completely new to me. please,

[@Freesciencelessons]

Hi. I'm not sure what you mean either. Can you tell me the time-point in the video where you hear those words and I'll tell you what they are. I was probably mumbling.

[@simranhans8806]

Hi sir its just generally so what does this element tell me 2fe(small two at the bottom) And what coefficient mean? Its not really in the video except in the equation at the end 2H(small 2)O. If that makes sense

[@g123-i5o]

The small two means it is diatomic like oxygen (O and small 2). This means that the oxygen molecule only exists in two pairs. The big 2 shows the number of moles or how many there are.

[@tegan9862]

in an exam does it tell you wether to put the answer in mol/dm^3 or g /dm^3

[@Freesciencelessons]

It will tell you in the question.

[@lilpinkbeananooshaullah786]

I don’t understand why in the first example the acids mole would be 0.005 ? How did you do that ?

[@SANDER-cg]

bloody legend

[@MH_2852]

Hello there! The question at this time stamp 2:44 shows the Mr of HCI to be 36.5 but in the equation it shows a large number 2 so you have to multiply the 2 to the Mr of 36.5 to get 73. I might be mistaken but could you check for me? Thanks

[@Freesciencelessons]

Hi. The Mr of a compound does not depend on any big number before the formula, so the Mr of HCl is still 36.5. We take the large 2 into account later in the calculation.

[@najmallayl]

@@Freesciencelessons I don't know why, but my teacher says to times by the big number? Is she wrong should i say something?

[@Freesciencelessons]

To determine the Mr, you do not multiply by any big number. You take big numbers into account later to calculate the number of moles reacting.

[@Chappati]

do we get the balanced equation in the exam or not

[@theohallworth2632]

yeah you do

[@zaynabzaman285]

thank you very much!

[@mohameddalghous5203]

how do you know when to answer in g/dm cubed or mol/dm cubed

[@zionateba7032]

Mohamed Dalghous it will say in the question x

[@arissa3586]

Do we always write the answer to 3 d.p?

[@Freesciencelessons]

No the exam question will tell you the number of decimal places.

[@c.o2307]

Sir when will Biology Paper 2 be ready?

[@harrisonprocter8947]

What a LEGEND

[@naatlyricstv7990]

Also tell me how to find out volume through these calculations. I'll be grateful.

[@Letik3x]

Thank you !

[@chirathin814]

Hi I was just wondering for the second titration calculation should I use my rounded answer from finding the mol/dm^3 to find the g/dm^3 or should I just use the answer from my calculator without rounding it. Thanks

[@Freesciencelessons]

I would recommend using the unrounded answer as it's more accurate.

[@chirathin814]

Thank you very much for your help.

[@oliviaoneillx]

would they tell you If you need to put it in g/dm^3 or mol/dm^3

[@Freesciencelessons]

Yes it will be very clear in the question.

[@oliviaoneillx]

Freesciencelessons thank you!

[@WiggleOcto]

Thanks!

[@InformationCrazy]

thanks alot man.

[@esbee2663]

1:56 how does the ratio work

[@Rayaann]

Bigger numbers at the front.

[@Iwasbornpretty]

so if a question like this comes in the exam then how will we know if we are supposed to find the concentration in grams or moles. will it tell us? cuz i am worried if it doesnt cuz how will we know if to find it in moles or grams so plz reply soon or if anyone else knows plz reply

[@harisamaan786]

Thanks

[@mohammudghafoor8305]

thanks so much

[@Freesciencelessons]

No problem and thanks for the comment.

[@darktrooper8766]

I sorry but I really don’t understand why you got 0.00125 I know it’s right but I just don’t understand how to get that

[@donelumuhoza2733]

thank you !!!

[@sofiam4715]

THANK YOU

[@tomshuter5248]

I don't have to watch this my school isn't allowing anyone to do triple as we have missed 6 months so I'm in higher foundation now kind of wanted to do triple but stress relived I guess

[@Crypt2349]

Is triple chemistry basically extended chemistry or different

[@kieranmarshall4527]

learn more in a shorter amount of time and there are three tests instead of two

[@rubysmith9135]

will the symbol formula telling us whether is 1 or 2 moles (2hcl +ca(oh)2 ... ) be in the question or do we need to work that out too, thanks

[@Freesciencelessons]

You may have to balance the equation but often they just give you the numbers.

[@rubysmith9135]

great thank you so much , your videos are so great and easy to understand!

[@shekinahlim8798]

in the first example, how did it become 0.005 moles?

[@twiggy2104]

Times by 2 cus its 2 moles and the other one is 1 mole

[@twiggy2104]

Btw can u tell me if my profile is the brown default one cus i changed it but it shows that it hasn't changed

[@vithu1810]

i dont understand how you got 0.00125 moles for sulphuric acid, can you help?

[@jd8404]

there are two moles of sodium hydroxide and only one mole of sulphuric acid. therefore you have to divide by two when going from a 2 to a 1.

[@unironicirony9741]

Thanks mate

[@ayoosiyale1893]

can u pls explain how batteries work.

[@Freesciencelessons]

Hi. This video explains everything you need: GCSE Chemistry (9-1) Cells and Batteries

[@ayoosiyale1893]

Thanks it really helped

[@lily-102]

What does the n stand for???

[@Freesciencelessons]

"number" of moles

[@lewisheath364]

i dont get how 0.0025 moles went into 0.005 moles can you help me?

[@Freesciencelessons]

It was doubled because there are 2HCl in the equation.

[@sebf6356]

In the first one, how is 25cm = 0.025dm?

[@SuperGeekalicious]

Seb F because there are 1000cm3 in 1dm3 so you have to divide the 25 by 1000. Hope that helped for your gcse ^^

[@studytube8967]

divide 25 by 1000

[@sxvageop528]

Every time you convert cm^3 to dm^3 you divide by 1000

[@firstname6591]

Update cakaculation and quantive playlis5

[@Freesciencelessons]

It should be accurate. Is there a problem with it?

[@firstname6591]

It’s perfect and amazing I mean honestly I got exams tomorrow and his helped but I had t learn about Tritiation as this is not on the playlist thankyou for being the best and ur an amazing person who help people thankyou

[@Freesciencelessons]

Thanks for the comment. Titration calculations are in the Chemical Reactions playlist.

[@ahsaanahmad4712]

My guy your a g

[@FlameOG-yc1bj]

Chem exam this morning

[@ebrahimkarimi1504]

So easy

[@KermitTh3Fr0g]

wag1

[@casinovathedon8924]

wys

[@khalim6420]

GG wp mr science guy

[@dema6389]

help me out 😫😫

[@simranhans8806]

Hi sir, I don't get how, 1 mole of substance in grams is the same as its relative atomic mass in grams? Also how to work out the answer in g/dm^3? Si vous plait

[@g123-i5o]

Hi I would like to help I'm not sure about the first question but for the second one multiply the concentration (mol/dm^3) with the Mr which is normally given in the question to give you the concentration in (g/dm^3)

[@AdreenFernando]

times the final result by the relative formula mass