Gauss law logical proof (any closed surface) | Electric charges & fields | Physics | Khan Academy

[@andrei-un3yr]

I'm so glad I found you, it has always bugged me how the flux had to be the same for any closed surface, and I was never able to find a convincing proof online

[@rajnishranjan3271]

i have been hovering on internet for hours to find a correct explanation. I am so greatful to find your video , it completely solve my problem. thanks for helping us.😊😊😊😊

[@aryanraj441]

great explanation, as always!

[@kingsuk_panda]

It was actually amazing, sir.

[@zitscx886]

thank you for this amazing proof.

[@LostWings5]

I have never been this happy while learning physics😅, but this one blowed my mind❤

[@brianandrews6124]

My head hurts. My mind is blown. My heart beating. Thank you!

[@Pixel_25]

Thanks for explaining this so easily 🤝

[@shephalikashyap2243]

U r a life saver bro ❤

[@abbasfadhil1715]

gauss is truly a genius he went from proving the flux for only a sphere to proving its the same as long as it's a closed surface using only high school geometry truly magnificent

[@meatychunkz8875]

Fantastic, thank you!

[@amirhosseinhosseinmardi4848]

your work is truly amazing

[@vijayanand2783]

Thanks sir !!Great Explanantion!!❤❤❤

[@growwithgaurav3225]

Got amazed by this explanation. Love it .

[@Parapresdokian]

This guy seriously need a raise.

[@Shoeb._.248G]

Your best at explaing a boring topic in an exiting way and easy way

[@Z-eng0]

Wow, I have to admit when you said logical proof and stuff I was really skeptical, felt like it barely even involve math totally caught me off guard with how detailed this was, great work. But just to make sure I got this part right, at the start you basically divided the whole sphere into many tiny circles and same with the blob all to sum it up later much like how we can divide anything into tiny squares in calculus but transferred into spherical coordinates, or something like that right?

[@hmmtheyesguy]

yeah

[@pizzarickk333]

You're literally the best. I seriously love you from the bottom of my heart

[@rainbow7164]

So much helpful 💕

[@DeepakKumar-pm4ur]

Nice explanation!

[@mansishivgunde1159]

Thank you very much!😊 I am so happy today. I was searching for it from so long time.

[@sherrymillhawkin011]

I'm in love with this writing dude

[@andreaprado112]

Thank you soooo much ❤

[@blenderfuzz3895]

My new favorite channel

[@animalpalace3750]

This is so clear. Thank you!

[@nsmultiman1679]

Just ,.....WOW. Thank you so much

[@arielyazdi5646]

Thank you!!!

[@sir_ionhard7067]

Nicely explained sir ❤

[@Brucewastaken5201]

Thanks!

[@_slvya1647]

For a charge outside the gausian surface, every electric field line (originated from charge) IF goes inside the surface must also come outside the surface. Field line inwards the surface denotes negative charge and outwards denotes positive. So net enclosed charge (assume two equal and opposite charges cause the entering & exiting field line) cancel out. By gauss law Flux * e = net charge enclosed (Net charge =0) Implies flux =0 Hence field lines by charges outside the surface don't change the results

[@tmarvel4347]

amazing...love from heart

[@krishnashisdas1606]

maan this is really great. it kinda surprised me

[@gangadhararao7733]

Great explanation ....👍👊

[@מעייןאריאלי]

theres a really weird implication of this though. Because now if we have a flat board and some charge outside of it(that lets say creates a uniform field), the flux is simply the field strength times the area (assuming the board is facing the field ). However,if the board is even slightly not flat, making it a closed surface, then the flux is suddenly 0. To me this seems intuitively paradoxical, because the flat board has field lines entering and exiting it as well, but for some reason the idea that the flux is negative when entering and positive when exiting only applies to closed (3d surfaces). What do you think about this?

[@kenzzz3998]

Beautiful and elegant proof!

[@arshpreetkaur532]

Make such videos on on other maxwell's equations also

[@faizaanwar8403]

Thank you a hundred times.

[@estebanl2354]

very intuitive thankss

[@subhajittalukdar3727]

FloatHead Physics ? Mahesh is that your voice ?❤

[@firozahmed8430]

Love from Bangladesh

[@MmAaZzzz]

great explanation!

[@sumankandel8576]

Beautiful trickery !

[@sakib_al_shishir]

Awesome 😎

[@denisvalentin4258]

Great proof and explanation! Most people argue using the electric field lines when introducing Gauss's Law and its independence of the closed surface, but I always found that argument a bit unsatisfying. I find electric field lines are merely a simplification of the electric field for visualization purposes (they are artificial in a sense the other concepts aren't), and using them to "prove" E&M laws always seemed unrigorous to me, at least not as rigorous as a limiting process as this one. But then again, I'm still a student, so maybe I'll change my opinion. Nevertheless, great video =))

[@nomann5244]

this is a proof for spherical charge but is there any proof gauss law also holds for a plane charge

[@satishgp1918]

Here, the tiny portion of the irregular closed surface was approximated as a circle, how is that?

[@khanphysics8209]

Very informative... appreciated

[@misaki2104]

This is so cool!

[@user-fo3ug3cr4m]

Endlich eine zufriedenstellende Erklärung, wo die 1. Maxwell-Gleichung herkommt.

[@Pradeepkumar-tg1kx]

Great 👌👌👌

[@4m0d]

thanks for this excellent video sir

[@mynameis7964]

make more videos i enjoyed it sir

[@supratimpaul-cw1rg]

What is the book of Richard Feynman he is talking about?

[@nishaprakash2592]

I LOVE THIS CHANNEL

[@sabarishks6089]

Thank you sir

[@ITS_jaunpuriya_BLOGS]

The area of the outer area on the random surface is finite because n*r is finite . But then also , why do we use gauss law for extended infinite distributions ?

[@krishjoshi2739]

beautiful!

[@_societyspeaks]

amazing explanation. oof finally, my sch is nth compared to this...

[@daylight1nsomniac536]

thanks

[@jeeaspirant1192]

9:16 If diameter of smaller circle is rθ then shouldn't the diameter of bigger circle be nrθ?

[@ahornypotato5397]

yeah, So?

[@GoodgyanE]

Sir, please make awesome video more fastly

[@mysteriousenvironment5734]

❤❤❤❤❤❤

[@jarifahmed977]

💓

[@anilsurjewala3606]

You always rock

[@bekalutadesse8615]

Tku mesh keep on

[@mangounjuicemangoe9983]

beautiful

[@jacqkrol4494]

Why do you take the area perpendicular to E at the outer surface. You need to take the area A of the outer surface and normal vector n to that area.

[@hmmtheyesguy]

it's the same thing

[@factsss7]

Fantastic

[@moderncybergamer3076]

It seemed cool bro

[@yong8467]

i love you sir

[@VG__]

2:30 9:50

[@easy-peasy9906]

Love from Pakistan

[@KhanhNguyen-dn8bm]

hell awsome

[@eternalwolverine4027]

SO fcking amazing explanation, I now love richard feyman.

[@itsmehere8285]

I've got a doubt bugging my head.... If the flux due to the charges outside do cancel out then why consider the field due them in the E.S surface integral ? Why don't we just ignore them altogether?

[@KhanAcademyIndiaEnglish]

That's a great question. You are absolutely right. So, then why do that? It's accurate to say flux through a closed surface also equals E (only due to charges inside). S. But that's not a very useful thing for me? Because, my goal is most often is to calculate the electric field at some point in space. And that field is due to all the charges in the universe. So, the idea is to first find the flux - which is E (due to all charges).S - using Gauss's law and then use it to find the E(due to all charges). Does that make sense?

[@itsmehere8285]

@@KhanAcademyIndiaEnglish Ohh yeahh.. I get it now !! Thank you so much for replying sir... These lectures are on a whole different level and it feels so great when the logic is known :)

[@YT_Admin_]

It kinda looks electric flux follows equation of continuity!

[@_slvya1647]

Rivhard Feynman!!!

[@dearantho]

Is it true that the radius is nr, is it not n+r...

[@Snakethug-k6u]

God saved my life

[@ymcatch]

Let me explain... E = kq / r^2 kq = E * r^2 (flip variables) E' = kq / (nr)^2 E' = E * r^2 / (nr)^2 (substitution) E' = E / n^2 A = pi * r^2 = pi * (d/2)^2 A' = pi * (nd/2)^2 A' = A * n^2 E' * A' = E * A You're welcome ❤

[@danielmaxwell7536]

dude what a beautiful explanation !!mind blowing

[@shreedattasahu9746]

Thank you sir