Progression and Series | JEE Maths Videos | Ghanshyam Tewani | Cengage

[@jeeaspirant2024__]

44 minutes of pure teaching . A passionate teacher ♥️♥️ What an amazing teacher you are I can't explain in words

[@sirajgupta7031]

SIR U ARE GREAT IS CAN U PLS GIVE LAST VIDEO IN WHICH FEW QUESTIONS TOUCHING ENTIRE MATHS ARE THERE

[@sridharbajpai420]

when LEGEND comes to earth to teach u i was in need of all these concept but never find it anywhere on earth

[@amrutmadje9991]

LEGEND of Mathematics!!! 👍🏻

[@dstsirnitw]

Excellent job sir you are great

[@uddipan_1842]

You are the best teacher of mathematics

[@aakash4924]

Sir pls make 3 videos A.M G.M inequality Trigo+Inverse trigo & last is on theory of equation

[@ballibhatia4481]

I dont no why these kind of videos get only few likes and views as they are of advance level which we are able to see free only because of this great person

[@mohitsawane6241]

he is blessing for all of us

[@atharvsaxena7218]

Always in the heart G.Tewani !!!

[@kartikeya7860]

Sir you make mathematics so easy!!! Thanks a lot!!!

[@vaibhavkumar5096]

Mza aa gaya video dekh ke . Questions krne ki shi approach pta lg gai . Thanks a lot sir

[@prakashchandra4427]

Saandaar , bejhor ,laajawab

[@varadthube4851]

Easy trick to solve first question is to know that the sum of first 'n' odd integers is n^2. So the given que directly represents (sum of first 57 odd integers)-(sum of first 13 odd integers) and que is finished....

[@padmakant1]

Sir, sigma wala concept bahut achha tha...thank you..

[@prjadhav7783]

theme questions , very helpful :) thanks a lot .

[@dineshratnani5358]

Wow awesome application of inclusion exclusion

[@ShikharGoswami]

And also composite functions and their differentiation.. Find it very hard..h(g(gx)) type

[@dubeyd5384]

Sir aapki jee mains aur advanced books me kya difference hai, kya mains wali books aur advanced wali books ki theory aur questions me difference hai, kuchch samajh nhi aa rha, reply dena jarur sir

[@tanushbidkar8724]

Hello sir one of the great video ever I have watched I am ur follower of maths sir i watch ur all lectures on youtube, your videos site and cengage videos also. I am understand whole jee maths from u easily . Only one doubt in this chapter that is v(r) -v(r-1) method is sufficient Or ur t1, t2 method which u substituted as tr is needed

[@manojrajguru8852]

Sir would you please suggest me about your online setup... I am impressed too much

[@8796205190]

Sir, You are great, when come to teaching. Please upload more videos on CONIC SECTIONS.

[@madanmotre]

sir your videos are totally amazing

[@rameshpandey5637]

Sir aaj kis topic par video aeyega.calculus ke mixed concepts par bana sakte hai kya.

[@ankurupadhyay280]

Thank you sir

[@tushargoyaliit]

At 18:30 I usually solve like Agar ham sab brackets ki maximum power se multiply kare to 1275 So hame ek degree kam karni hai . It could be done by selecting constant from (x+1) =1; or by selecting linear from (x-2)^2 which is 4 ; or quadratic term from (x+3)^3 which is equal to 9(3C1×x^2×3^1) .... Similarly 4C1×4 .... ... Aapke method me je problem aa rahi hai ke ham 3 vaar(x-3) ko kyu bahar rakh rahe hai ?

[@gtimeducation]

To understand my method you can follow this logic also. Degree of polynomial is 1275. We are looking for coefficient of x^1274. So, sum of the zeros will be equal to (-co-efficient of x^1274/ coefficient x^1275). So, coefficient of x^1274 = -(sum of zeroes) = - (-1 + 2 + 2 - 3 - 3+ 4 + 4 + 4 + 4 .....) etc.

[@tushargoyaliit]

Really outstanding sir awesome Very very nice way

[@tushargoyaliit]

This is best method that could be for this que

[@sheebapratap2555]

God in disguise..... #respect🙏🙏

[@rajdeepsarkar5721]

Trigonometry pls 😊

[@ritehkumarsingh1499]

I not = j not= k wale question me jab tino equal ho jaye to wo wala substract nahi kiye hai

[@pathipakabanesh4659]

fantastic class sir , sir pls post more videos on every topic which touch overall concept

[@rajatparab8116]

Thankyou sir You are legend

[@DilkhushKumar-ok2pp]

Thanks so much sir.

[@snipergranola6359]

Thanx sir

[@VIKASVERMA-nk8uw]

Great

[@ShikharGoswami]

Sir please cramers rule and system of equations

[@radheygupta220]

hats off to you sir for your dedication towards us

[@xenngaming1973]

Sir can you explain domain of composite functions ?

[@RajeshKumar-go6st]

Sir vo i and j ko jab equal kiya to uske subtract kaise kiya Matlab subtract krne vaala expression kaise

[@gtimeducation]

I think you are asking in question where double sigma is there. It is simple, when i = j, we have i x j = i^2, and there is no need of sigma for j variable only i variable will do. If it is a doubt of triple sigma question then ask it again.

[@ritehkumarsingh1499]

Thanks a lot sir

[@utsavdesai5885]

there is an error at 17:45 the sum should be (1^1)-(2^2)+(3^3)-(4^4).....

[@abueleas22]

I think you are wrong

[@mahimaarora3292]

Sir how to think in such a way that we can split the nth terms in T (r+1) -T (r)

[@gtimeducation]

I sequence and series there is one section of series of this type in which we split the general term in T(r + 1) - T(r). It stars with elementary partial fraction. It requires practice of such questions then by some logical thinking you can split. If you are reading cengage books, you will find this topic at the end the theory just before subjective questions. One thing is clear in such questions we have to split the term otherwise there is no way to get this sum. Now keep thinking that splitting must benefit you like when u r splitting and write the terms by putting the values of r terms must be cancelled in some pattern. If it is not cancelling u rework.

[@tany1291]

@@gtimeducation Thank you sir.👍🏻👍🏻

[@abdevilliers7744]

Question solved between 29:00 and 34:00 the last term must have a 1 in multiplication why there is a 2

[@ashishjain48578]

waha pe sir ne subtract karne ke bad wali jo term likhi wo shayad galat likhi he

[@studyalways593]

Sir in the first question , of 57²-13², there can be another series also possible,how can we find that series , please give some guidances.

[@tushargoyaliit]

Sir wo to pta lag gya ke konse case minus krne hai but kaise karne hai Like i ;j;k equal krne pe aapne 3 sigma ki jagah ek hi sigma likha Vo kaise at 32:0 k and j ko equal krne par jab subtract kr rahe hai to k ke saath vaala sigma gayab hi jo gya? Thoda please bta do i have confusion

[@gtimeducation]

We want sum when i, j and k are distinct. So we first find sigma when i, j and k are independent which is equal to (sigma of 1 for i)(sigma of 1 for j) (sigma of 1 for k). In this sum there will be terms when i = j (k may be equal to this or not), j = k( i may be equal to this or not) and i = k (j may be equal to this or not). Now all these sums will be equal. when u make i = j or j = k or i = k, we get the same sum. So, i am subtracting sum when i = j three times (one for each i = j, j = k, i = k). Now doing this we have subtracted the case when i = j = k more than required times. So we are adding the sum when i = j = k two times to balance. If still doubt dont hesitate ask again.

[@gtimeducation]

This is for triple sigma question. We want sum when i, j and k are distinct. So we first find sigma when i, j and k are independent which is equal to (sigma of 1 for i)(sigma of 1 for j) (sigma of 1 for k). In this sum there will be terms when i = j (k may be equal to this or not), j = k( i may be equal to this or not) and i = k (j may be equal to this or not). Now all these sums will be equal. when u make i = j or j = k or i = k, we get the same sum. So, i am subtracting sum when i = j three times (one for each i = j, j = k, i = k). Now doing this we have subtracted the case when i = j = k more than required times. So we are adding the sum when i = j = k two times to balance. If still doubt dont hesitate ask again.

[@tushargoyaliit]

Sir i had clearity about this what u replied . But i wanted to know Jo expression subtract karte time likha vo kaise bana ; usme sirf 2 sigma hai I m clear about which cases to subtract or add . But i just wanted to know jab hamne k=j maan ke subtract kiya tab vaha pe only 2 sigma hai kya k=j karne c ham either k or either j only ek sigma hi rakhe. . ( Kaise) Je doubt hau

[@chhayanchoidhury1747]

Bhaiya ap iit pouch Gaye

[@parmitkumar8065]

Sir please components and divinendo bataiye

[@ananyav3395]

Thank you sir!!

[@yt.abhijeetsingh]

sir is some part of this video from your previous progression and series lesson???

[@gtimeducation]

No, this is freshly recorded.

[@roshansphotography4140]

check out binomial, it is linked

[@yt.abhijeetsingh]

Roshan's Photography i also remebered 😅

[@hrishikeshaddagatla4789]

Sir can you give me the solution of arithmetic mean of 2sin2,4sin4,6sin6,.....180sin180degree

[@hrishikeshaddagatla4789]

@@gtimeducation Thank you sir

[@carryminnnnati]

3:42

[@roshansphotography4140]

sir why previous year questions, i did it already

[@Aalekhsingh1057]

Aap kya glass k upar likhte ho 🤔🤔

[@carryminnnnati]

25:00 to 36:00 hardest minutes of my life

[@ranasvoice554]

👍👍👍👍👍👍👍

[@ranbirpalsingh2245]

Sorry sir but there is some error in qno. 4 u have solved as u have solved the x+1/x by using am gm inequality and on applying the equality conditions we are getting absurd result then how can be accept am gm we need to find its min. Valurle by some other method

[@abueleas22]

You're wrong....the method is absolutely correct

[@narayanastudent9392]

omg

[@arunasharma6614]

Sir hum gareeb log ke liye aap sare upload Kar do pl. I'm

[@rubalsinghdhaliwal1360]

Thank you sir