Matrices for JEE Advanced | JEE Maths Videos | Ghanshyam Tewani | Cengage

[@swapnasaritmohapatra8126]

These Videos are really Priceless!!

[@rithwhickpraharsha6047]

It's values unpayyable price ..bro

[@abhisekchanda2485]

Best ever lecture on matrices and determinants

[@arpanmukherjee6031]

Sir 1 specific video on *PROBABILITY (BINOMIAL)* ... And one general video , based on *multiple concepts* Most imp for advanced .

[@coderinthewoods]

In the Question from IIT-JEE where we are given P , A , Q and we need to find X , there is an error. P•P` is not an identity matrix as you evaluate it. Please have a look.

[@gtimeducation]

Junaid Rehman It may be by mistakes In original P second element of second row u consider + then it is done

[@coderinthewoods]

Yes, it comes out then. Anyways, Sir share a part 2 video of Matrices based on Adjoint, Inverse etc. Thanks.

[@chouhan15]

wonderful manipulation skills in wilderness of maths .

[@mathsmirror2184]

Sir मैं भी एक मैथ टीचर हु लेकिन मैंने एक चीज गौर किया है कि आपके बहु काम व्यूअर है क्योंकि आप धोखेबाज नही है।मेरे पास के सभी लिखे गए किताब है और मैं आपको अपना मैथमेटिकल गुरु मानता हूं।आपके चरणों मे मेरा प्रणाम,,,,,,

[@gtimeducation]

cricket kida 🙏🙏🙏

[@avyakthaachar2.718]

Sir at 37:16, how did you conclude that det(M-N²)≠0? M-N²≠O does not necessarily imply it's determinant is not zero, isn't it?

[@tusharkushwaha5042]

thanks sir for helping us for jee advanced

[@msaivignesh5304]

Best 👍💯maths tutorial for jee

[@tushargoyaliit]

Sir at 18:11 we can use clearly it is orthogonal matrix as both rows r unit vectors and dot product if both rows is zero . Fast observation

[@RajeshKumar-go6st]

challenge Success yes by orthogonal directly AAtranspose =I

[@gtimeducation]

👍👍👍

[@tushargoyaliit]

Ghanshyam Tewani JEE Maths Video Lectures Thanks sir U r very helpful Plz take some multiple concept problems also

[@utkarshade7966]

G. Tewani sir is legend !!!

[@rohith.peddi7]

in 18:17, he wrote p22 element as +ve root3 by 2

[@swapnasaritmohapatra8126]

Really helping a lot specifically this point of time before Jee Advance...I solve along with you as soon as you upload the videos for advanced and once more at end of the day.... Finding really helpful!!

[@arpanmukherjee6031]

Swapnasarit Mohapatra Abe tui durgapur er ?

[@547_rahul8]

Your adv rank bro?

[@zakianwar5118]

Thankx

[@kamidhunkumar3021]

Beautiful....

[@Rohankumar-ju8ul]

Sir how can u teach so fabulous.i love ur videos it helps me in my jee prep.

[@kishanpatelmathematics11th40]

All of your videos are very helpful .... awesome....

[@fn9979]

Sir came to your video for the first time...Really liked the thorough explanation of the method and the level of problems...Thank you for the amazing explanation

[@ishitaagarwal5607]

In second question can't we take A and B matrices as identity because equation can become B=A.A^-1=I

[@namansharma1330]

Best teacher for jee advanced

[@hrishikeshaddagatla4789]

Sir can you provide me a solution of Q)If A is a square matrix and e^a=I+A^1+A^2/2!+...(infinity)= 0.5 [f(x) g(x)] [f(x) g(x)] Where A=[x x] for all [x x] for all x€(0,1) and I is the identity matrix order of 2 .Then integral of (f(x)-1)× (g(x)-1)dx with limits 1/4 to 1/2 is equal to

[@DilkhushKumar-ok2pp]

Thanks so much sir.

[@dhruvshah3728]

salute to you thankyou

[@theungabunga38]

Amazing

[@deveshkumarsingh5271]

Sir, please restart uploading videos for Jee advanced 2020

[@PavanKumar-qd3uk]

by taking both A and B as I we get in two steps that lamda is 2^2010

[@gauravkumawat7993]

18:22 Question is wrong sir...

[@jeeranker1167]

👏 awesome

[@sapanasaini4821]

Sir please esi video aur banau JEE advance 2021

[@shang_chi4651]

sir aap aise hi tough questions discuss karte rahiye .this is very helpful for students like me who are good at concepts but are unable to solve tough questions.thankyou....so much

[@harsh17_17]

Shu bham Dixit if u are good at concepts ..after that u not need tough question ... It mean clearing concept frm tough question Kyuki concept bolna aasan h dost ...pr vo hi smaj na kafi mushkil h ...

[@shang_chi4651]

@@harsh17_17 you are absolutely right .agar kisi me concepts solid ho to tough questions bhi use easy lagenge. But I am one of those few jinhe multiple question practice she hi concepts samajh mein aate hain

[@sabyasachi36]

Real jewels. This man deserves some really great honour

[@nicholasnye7318]

Thank you sir

[@lakshmitirumaladasu101]

Cool

[@arnavnegi6099]

excellent video

[@tushargoyaliit]

Sir very doubtful at 37:48 U said if M not equal to N^2 Then M-N^2 ka determinant zero ni aa sakta Isn't it wrong . It implies a non null matrix can't be a singular matrix Plz verify Plz tell I m always confused here

[@Rohankumar-ju8ul]

Aabe Bhai when M is not = N^2 Than M-N^2 is not equal to 0 na.

[@kishanpatelmathematics11th40]

@@Rohankumar-ju8ul it's not necessary that matrix is non zero then it's determinant also non zero ......

[@bhaskarasastryvedam184]

@@Rohankumar-ju8ul but it may be singular na

[@dwight.kschrute2936]

@@bhaskarasastryvedam184 for singular Det should be 0 . Meaning M = N^2 which is restricted in the question

[@pratikchoudhury3683]

OMG 🙄🙄 what I am seeing , 🙏🙏🙏sir you are one of my fav book writer

[@devadattacharan2920]

masterpiece in maths

[@bhaskarasastryvedam184]

M is not equal to N^2 that means M-N^2 is not null matrix when why its determinant is not zero

[@Lone_warrior_18]

Maths me maja toh abhi aane laga hai....

[@SurjeetKumar-ev8qx]

Wait for more

[@tushargoyaliit]

Surjeet Kumar Yes please do maximum videos

[@SurjeetKumar-ev8qx]

sure

[@nishasaha3069]

31:51 worth this.

[@arnavnegi6099]

at 12:52 who got the value of k =5;

[@kishanpatelmathematics11th40]

M not equal to N^2 then how can we say det(M-N^2)# 0......explain plz

[@varshadeotare4644]

Wow!!!

[@VivekKumar-qj8iz]

Best lecture sir

[@AnkitKumar-oy6ij]

Part 2 waiting....

[@nannumittal8806]

sir i m very much fan of you, but one thing l never understand why in product of two matrices Number of column of I matrix is equal to Number of rows of II matrix. Please tell the concept

[@gtimeducation]

Click the following link for your query. It is taken from my Algebra book. It may help you clear your doubt. drive.google.com/file/d/1cbV9uIbuHQcIQWB0BeFjjpgznqGJ2MEu/view?usp=sharing

[@ankitkfly]

Sir in 3rd question ..... .... You driectly conclude that trend of equation is B^2 then B^4 then B^8 ....which is right ... .. bt it can be B^2 then B^4 then B^6 ... Which results wrong answer... ... How do I choose the trend ..... Confused !! ... Please explain this ..sir..

[@akramfaiza3017]

Sir please upload next part

[@nabeelkhan4910]

At 6:48 what about premultiplying with a inverse in one eqn and with b inverse in the other we get a=b=i

[@gtimeducation]

We can premultiply by A inverse only if we r sure that Det.(A) is non zero, i.e. A is non singular. But given that AB = A. So det.(AB) = det.(A). From this either det.(A) = 0 or det.(B) = 1. Thus we r not sure about A wether it is singular or not. So we not sure about existence of inverse of A.

[@sabyasachi36]

37.30 seconds there is a mistake.

[@sabyasachi36]

Because m-n2 is nonzero does not guarantee that its determinant is nonzero

[@arnavnegi6099]

sir plzz.. telll how u guess In Question no. 3 that power of B must be 8 rather than 6, I m confuse in little bit in 6 or 8

[@sanjibkhaddar1878]

I too hv the same ques

[@tushargoyaliit]

Plz reply sir

[@gtimeducation]

challenge Success Replying in sometime

[@tushargoyaliit]

I spended more than 1hour on this que and got that det(M^2+MN^2)=o not because det(M-N^2) is not equal to zero infact vo to zero ho sakta . det(M^2+MN^2)=o because it can't be non zero due to ... I solved but vo type krne me mushkil hai .

[@raahilbadiani7289]

Same doubt. Sir please help me out

[@mathsbys.shankar6824]

@@tushargoyaliit before one step it should be that M-N^2 is not zero cause M & N^2 are not equal so M^2+MN^2=0 finally we have det.( M^2+MN^2) = 0

[@Mathematics_by_mpatwal]

Price lesss...

[@jeeranker1167]

In short all determinant have value = 0 XD

[@udayjordan4262]

MOHIT TYAGI SIR SA PARLO ACHA PARAYAGA YE MAINS LEVEL KA BHI NAHI HA

[@yashbaheti96]

Thank you sir

[@VivekKumar-qj8iz]

Thank you sir