Graph plotting techniques in calculus

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Ghanshyam Tewani JEE Maths Video Lectures

Ghanshyam Tewani JEE Maths Video Lectures

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Buy JEE Maths video lectures : Call 07814166606, 0172-4280095, Visit our website www.tewanimaths... Prof. Ghanshyam Tewani is author of many books on IITJEE mathematics published by worlds one of the most renowned publisher CENGAGE LEARNING. These books are appreciated all over INDIA and abroad. These books are now one of the top selling books in INDIA. Some books authored by Prof. Ghanshyam Tewani are 1. Algebra 2. Coordinate Geometry 3. Trigonometry 4. Calculus 5. Vectors and 3-D Geometry Prof. Ghanshyam Tewani has experience of 15 years for training students in Mathematics for IITJEE and other competitive examinations. He has worked for four years for FIITJEE Ltd., Delhi , the renowned name in IITJEE coaching. He is a rare genius, acknowledged as one of the best national level teachers in mathematics. His intense and concise lectures are aimed at clearing the student's fundamental concepts in mathematics and at the same time, laying a strong foundation for better understanding of complex problems. A man of uncommon devotion, he leaves no stone unturned to help out needy and deserving students. Every single word he speaks is weighed, for he believes in precision. In his own words, "For me each student counts, each one must learn to the best of his / her capability." Being a perfectionist, he doesn't tolerate even a minor error. It is not surprising that the best & most brilliant of student community hold him as their ideal and an adored mentor. Our Mission To develop a strong base with deeper understanding, and strengthen theoretical and applied dimensions of mathematics. To equip the students with a set of conceptual skills, intuitive tricks and fast methods to make them more confident and consequently expel the baseless fear of mathematics. (Buy iitjee videos : Call 07814166606, 0172-4280095, Visit our website www.tewanimaths.com)

Пікірлер: 59
@franky0226
@franky0226 6 жыл бұрын
Baaki teachers padha dete Hain...But you sir...U invoke ideas within us...Thanks a lottt
@shardapathak9809
@shardapathak9809 6 жыл бұрын
Sir aapka last video bhi shandaar tha
@jaysoni9568
@jaysoni9568 4 жыл бұрын
Graphs just solve everything
@yusufazad967
@yusufazad967 6 жыл бұрын
Sir, how to find the range of f(x)=(sinx)^2 + 4 (cosecx)^2,.........Why fail here, AM-GM inequality Concept. Please, elaborate where it is applicable.
@nikhil12310
@nikhil12310 6 жыл бұрын
No.of point of discontinuity and non differentiability of (arcsinx)+(arccosx) where (.) =g I f
@sankalpgupta3601
@sankalpgupta3601 3 жыл бұрын
10:35 Sir there is one root for k= -1/e also
@EasyMaths_official
@EasyMaths_official 2 жыл бұрын
Also 1 root for k=0
@snehlata3
@snehlata3 3 жыл бұрын
For 1 root why it's not [0,infinity)union{-1/e}
@idontknowyouitseems_4370
@idontknowyouitseems_4370 5 жыл бұрын
I love Mathematics!
@maazshaikh8238
@maazshaikh8238 4 жыл бұрын
Wait what?
@neevhingrajia3822
@neevhingrajia3822 4 ай бұрын
@@maazshaikh8238yes, is it really that unbelievable to you?
@maazshaikh8238
@maazshaikh8238 4 ай бұрын
​@@neevhingrajia3822now I too🙂
@yusufazad967
@yusufazad967 6 жыл бұрын
Thanks Sir for detailed Explanation, But Sir, how to recognize for more than two terms AM>=GM Concept is applicable or not eg, [1]f(x)= 4 (sinx)^2 + (cosecx)^2 +2 [2] g(x)= 3^x +3^(-x) +8 [3] h(x)=2x+4x^3 + x^(-4) where, x>0 [4] f(x)=6^x + 3^x +6^(-x)+3^(-x) +2
@strangersings
@strangersings 2 жыл бұрын
All are positive terms so obv applicable though I guess it won't help now 🙃
@shardapathak9809
@shardapathak9809 6 жыл бұрын
Sir next on parabola
@codingwithanonymous890
@codingwithanonymous890 5 жыл бұрын
Was searching for thia topic only thank u sir
@nikhil12310
@nikhil12310 6 жыл бұрын
in any trangle ABC 2sinB=cosA ,the length of internal bisector is 2√2÷3. and the equation 25.cos^2(A-B)+ x^2+40cos(A-B)-2x+17=0 has at least one solution then what is the circumradius pls give me answer
@nikhil12310
@nikhil12310 6 жыл бұрын
Of angle C
@nikhil12310
@nikhil12310 6 жыл бұрын
Pls sir give me answer
@karangurbani353
@karangurbani353 5 жыл бұрын
Sir, in the graph of x^x, I think there will be no point of inflection after x=1/e or I'm unable to find it. As f''(x) >0 ¥ x>0. Pls tell.
@subratadebnath5436
@subratadebnath5436 9 ай бұрын
In the frist question Hume kaise pata chalega ki graph negative X se atee atee niche turn karega phir origin se pass hoke Infinity pe chala jayega
@rajivkulkarni5463
@rajivkulkarni5463 6 жыл бұрын
For x e^x=k to have a single solution, I think k=(0,infinity)U{-1/e}
@studyphobe9005
@studyphobe9005 Ай бұрын
Just curious to know where are you broo.... Jee aspirant... I think now you hv already done you bachelor's... If this comment finds you ...make sure to reply
@shardapathak9809
@shardapathak9809 6 жыл бұрын
Sir vo graph niche kyo gaya
@junedahmed5246
@junedahmed5246 4 жыл бұрын
Sir you are God of mathematics
@yusufazad967
@yusufazad967 6 жыл бұрын
Sir, What will be the Range of f(x)=(sinx)/x ?
@nekibuzzaman2471
@nekibuzzaman2471 Жыл бұрын
(0, 1)
@studyphobe9005
@studyphobe9005 Ай бұрын
Just curious to know where are you broo.....I think now you hv already done your bachelor's... If this comment finds you... Please make sure to reply.
@yusufazad967
@yusufazad967 6 жыл бұрын
A lot of Thanks Sir...., Sir, how to get exact value of c ,involved in your explanation for the Range of f(x)=(sinx)/x
@yusufazad967
@yusufazad967 6 жыл бұрын
Thank you very much, Sir...
@yusufazad967
@yusufazad967 6 жыл бұрын
Thanks Sir for detailed Explanation, But Sir, how to recognize for more than two terms AM>=GM Concept is applicable or not eg, [1]f(x)= 4 (sinx)^2 + (cosecx)^2 +2 [2] g(x)= 3^x +3^(-x) +8 [3] h(x)=2x+4x^3 + x^(-4) where, x>0 [4] f(x)=6^x + 3^x +6^(-x)+3^(-x) +2
@christy_003
@christy_003 3 жыл бұрын
Sir are you author of Cengage Mathematics???
@agarwalyashhh
@agarwalyashhh 2 жыл бұрын
Yes
@shardapathak9809
@shardapathak9809 6 жыл бұрын
Sir range how
@8796205190
@8796205190 6 жыл бұрын
Range would be -1 to infinity including-1
@idontknowyouitseems_4370
@idontknowyouitseems_4370 5 жыл бұрын
@@8796205190 range means the corresponding y coordinates of the least value and max value of x co-ordinate respectively. For -1 you get f(x)= y=-1/e and f(infinity) =y=infinity
@madhumunjial5797
@madhumunjial5797 6 жыл бұрын
sir plz upload lec other than available on cengage app .....
@shardapathak9809
@shardapathak9809 6 жыл бұрын
truth teller is this available on cengage app
@madhumunjial5797
@madhumunjial5797 6 жыл бұрын
yes login with code given on book
@Satyam_3345
@Satyam_3345 Ай бұрын
Gr8 sir
@shang_chi4651
@shang_chi4651 6 жыл бұрын
sir isliye hi aapki books best hain for IIT jee preparation
@AshishGupta-gj4zy
@AshishGupta-gj4zy 5 жыл бұрын
Thankx for such advance videos
@ayushff2197
@ayushff2197 4 жыл бұрын
Sir plz make videos on jee advanced 2020
@studyphobe9005
@studyphobe9005 Ай бұрын
What was your result?
@mathacademy-jeeimocuet6566
@mathacademy-jeeimocuet6566 5 жыл бұрын
What software you used sir
@AshishGupta-gj4zy
@AshishGupta-gj4zy 5 жыл бұрын
Sir point of inflection ka answer not defined hai if this true plz tell sir
@codingwithanonymous890
@codingwithanonymous890 5 жыл бұрын
does anybody know which technology sir is using curus to know
@shardapathak9809
@shardapathak9809 6 жыл бұрын
First like
@Mathematics_by_mpatwal
@Mathematics_by_mpatwal 5 жыл бұрын
Any reference book for maths where solution are given.
@Sumanmandal-l7n
@Sumanmandal-l7n 3 жыл бұрын
G Tewani Sir book
@Sumanmandal-l7n
@Sumanmandal-l7n 3 жыл бұрын
Cengage Mathematics
@Ranbeer7770
@Ranbeer7770 2 жыл бұрын
Sir board ka bahar aaja koi kuch nahi kahega
@yusufazad967
@yusufazad967 6 жыл бұрын
Thanks Sir for detailed Explanation, But Sir, how to recognize for more than two terms AM>=GM Concept is applicable or not eg, [1]f(x)= 4 (sinx)^2 + (cosecx)^2 +2 [2] g(x)= 3^x +3^(-x) +8 [3] h(x)=2x+4x^3 + x^(-4) where, x>0 [4] f(x)=6^x + 3^x +6^(-x)+3^(-x) +2
@studyphobe9005
@studyphobe9005 Ай бұрын
Just curious to know where are you broo.... Jee aspirant... I think now you hv already done you bachelor's... If this comment finds you ...make sure to reply
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