You shouldn't complain. If it weren't for videos like this I wouldn't have learned about the Lambert function. Also, please note that at the end he showed why the answer was complex. The grafs didn't intersect
@florisv5592 күн бұрын
I was offering constructive criticism. What's wrong with that? I'd say that people who still need such an expanded reduction of the original equation to the Lambert W function because they aren't comfortable with logarithms etc. yet, shouldn't start with the Lambert W function but should first get comfortable with logs.
@florisv5592 күн бұрын
You first spoon feed the viewer with simple steps to solve the equation, then you start about the Lambert W function, which is indeed higher maths, then you loosely comment that the equation doesn't have any real solutions, without showing how you come to that conclusion. Try to be more consistent and your videos will improve greatly.
@TimBoulette2 күн бұрын
Ask for your money back.
@janami-dharmam2 күн бұрын
how do you know that W(-ln5) does not exist?
@florisv5592 күн бұрын
@@janami-dharmam Like this: f(w) = we^w for real w has an absolute minimum -1/e for w = -1. -ln(5) < -1 < -1/e, so we^w can't get that value. Another way to see it is to view the graphs of the functions x-> x and x -> 5^x - they don't intersect.
@Snow411742 күн бұрын
@@florisv559 He referred to a previous video where he discussed the relationship of complex valued solutions and non-intersecting graphs. BUT WHICH VIDEO?
@RAMPRASADLANDAGE2 күн бұрын
Make videos on SAT maths questions (vote button)
@Snow411742 күн бұрын
You referred to a previous video where you discussed the relationship of complex valued solutions and non-intersecting graphs. BUT WHICH VIDEO?
@tzirvee3 күн бұрын
5^log x = x ⁵
@randyparker57212 күн бұрын
5^0=0 X=0
@fubaralakbar68002 күн бұрын
Any number to the 0 power = 1
@hamzahaidar2084Күн бұрын
No. X⁰ = 1 ( X€ R) And 5^x≠x (X€R) So the solution is complex/ imaginary
@Mack-ed1ig3 күн бұрын
You are solving questions for other people to see not for yourself. For God's sake, writing should be bigger so we can see easily .
@БоянБожанов-м1н2 күн бұрын
Its written pretty well. Have you checked your eyes recently
@edwardhuff47272 күн бұрын
x = -0.01075 - 0.98279 i
@edwardhuff47272 күн бұрын
5^x = x (e^ln 5)^x = x e^(x ln 5) = x x ln 5 = ln x (ln x)/x = ln 5 (ln x)/(e^ln x) = ln 5 (ln x)e^(-ln x) = ln 5 (-ln x)e^(-ln x) = -ln 5 W((-ln x)e^(-ln x)) = W(-ln 5) -ln x = W(-ln 5) ln x = -W(-ln 5) x = e^(-W(-ln 5))
@janami-dharmam2 күн бұрын
how??
@edwardhuff4727Күн бұрын
@@janami-dharmamWolfram Alpha or Mathematica, or one of many other computer algebra systems. Look at Wikipedia article on CAS.
@edwardhuff4727Күн бұрын
Here's more solutions. There are countably many. Sheet refers to the Riemann surface, which is cut into sheets. Each sheet fills the complex plane. All of the complex x values satisfy 5^x=x. sheet=-5 x=1.7462696339565527+16.5264299576489i x-5^x=10^-14 + 0.i sheet=-4 x=1.5796262962043934+12.610451070467139i x-5^x=10^-14 - 10^-15i sheet=-3 x=1.3507162537895936+8.688085376179854i x-5^x=10^-15 - 10^-15i sheet=-2 x=0.9815502377624126+4.753430109599094i x-5^x=10^-16+10^-16i sheet=-1 x=-0.010750838472555747+0.9827872262285992i x-5^x=-10^-17+0.i sheet=0 x=-0.010750838472555783-0.9827872262285992i x-5^x=10^-17+0.i sheet=1 x=0.9815502377624126-4.753430109599094i x-5^x=10^-16-10^-16i sheet=2 x=1.3507162537895936-8.688085376179854i x-5^x=10^-15+10^-15i sheet=3 x=1.5796262962043934-12.610451070467139i x-5^x=10^-14+10^-15i sheet=4 x=1.7462696339565527-16.5264299576489i x-5^x=10^-14+0.i sheet=5 x=1.8774508360596127-20.43888917162955i x-5^x=10^-14+10^-15i