great work again ,u r perfectionist sir like aamir khan........
@sriguruskandha99204 жыл бұрын
Sir,I didn't understand differ between planar structure and plane of bending.🙏🙏🙏 Please help in understanding that concept sir...
@manaspatnaik913 жыл бұрын
Great Work sir.....Really i am bubbling with knowledge......
@pranav93392 жыл бұрын
Orr beta kesa hai tu ab youtube pe pada raha hai na
@patialapopdesign4 жыл бұрын
Sir problem 1 ma moment at point A 300 *2/3 *300 lea ha300 *1/3*300 Kyo nhi .......plz reply sir
@saleemq710 жыл бұрын
Great work but I think that he made a mistake when calculating at 46:27. It should be -300-600= -900 because there are negative signs next to the halves.
@kristofeh11 жыл бұрын
at about 47:00 mins, why is it that when calculating the moments due to the linearly varying load, you multiply the load by 1/3 ? I would have thought that because the load is linearly varying, this would be equivalent to multiplying the load by 1/2 (average load per unit length)
@vedanadhmeka348211 жыл бұрын
for centroid of triangle it is h/3 from the base
@kristofeh11 жыл бұрын
vedanadh meka thank you
@shivgangakumarpatel30237 жыл бұрын
Sir bending stress in beams ka koi lecture nahi h kya???
@geraldocarvalhobritojunior47939 жыл бұрын
Very nice lecture...
@kedharediga87929 жыл бұрын
where is 5th lecture in bending of beams
@srijanagarwal9646 жыл бұрын
When P is acting downward, Why is the stress resultant also acting downward at 36:10.
@jshkumar25 жыл бұрын
any direction you can take while evaluating but once direction has been taken be consistent with the direction in the entire problem :)
@rathourhimanshu67724 жыл бұрын
great sir
@adithyasharma98886 жыл бұрын
thank u very much sir..
@reza164114 жыл бұрын
Thanks!!!
@vellankisaichandra57419 жыл бұрын
i need flexural stresses
@rameshkumarsingh96067 жыл бұрын
thanks
@TheSat000711 жыл бұрын
Thank U sir...!!!
@jrkravikumar13 жыл бұрын
thanks a lot sir
@umugore111 жыл бұрын
Thanks Sir
@lhohohihjcujfjc68936 жыл бұрын
شو هيدا بالضبط
@92hyadav13 жыл бұрын
i feel like iit bombay is not the only iit that is suffering wid professors :(
@Apjooz13 жыл бұрын
I have a beam in my pants. Sorry, I didn't have anything intelligent to say.
@mranubhavsingh61865 ай бұрын
bro 🤣🤣🤣🤣 I'm crying with laughter
@VishalNamani10 жыл бұрын
simply supported beam has 3 reactions??... please check your books.. it has only 2 reaction forces ... there will no hinged support in simply supported beam. both has roller support
@coolsarfar10 жыл бұрын
SSb has 3 reactions... two from hinged end, one from roller...if a beam has two roller it will not be stable...its an unstable beam...check its indeterminacy...it will come negative...!!!
@123223mohit9 жыл бұрын
do u know why we provide a roller support at the other end, why not hinged , is it just to make it determinate?
@MounikaMeduri8 жыл бұрын
No.. To allow thermal expansions and contractions in the span, we provide roller support at one end.
@mohitdahiya91155 жыл бұрын
TO remove thermal stress. when body wants to increase its length they free to increase no resistant no thermal stress.
@mvtrumpetgeek1314 жыл бұрын
@punjabpolice911 learn how to spell dude.
@monty97582 жыл бұрын
Informatice but boring
@yogeshgajre70573 жыл бұрын
Not good at all
@pankajkumarpandey66582 жыл бұрын
study fundamental properly. Then only you can understand.