integral of x*sqrt(1-x^4), trig substitution, calculus 2 tutorial

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blackpenredpen

blackpenredpen

Күн бұрын

Пікірлер: 58
@maksnowakmaks1819
@maksnowakmaks1819 2 жыл бұрын
Wow!!! That was AMAZING! You just blew my mind! Thank you for the explanation, it was just what I've been looking for!
@sheylaroblesrodriguez7437
@sheylaroblesrodriguez7437 3 жыл бұрын
I was trying to solve this, but I couldn´t... Now, you helped me, thank you so much!!!!
@vincentochieng9698
@vincentochieng9698 3 жыл бұрын
You are an excellent teacher. I got helped a lot. Thank you
@aastha3428
@aastha3428 Жыл бұрын
After substituting u , I used the identity integral of sqrt(a-x^2) = x/2 sqrt(a-x^2) + a^2/2 sin^-1 (x/a) +c and got the answer within 2 minutes . Memorizing identities ,though nerve racking, sure has its perks.
@ernestosaboia
@ernestosaboia 5 жыл бұрын
Great help, buddy!!! Thanks for all your videos
@andrewmaksimovich2432
@andrewmaksimovich2432 3 жыл бұрын
This is so helpful, I don't know how I would survive my class without this
@gabrielsalazarbustillos8592
@gabrielsalazarbustillos8592 3 жыл бұрын
thanks man, 2021 at 1:11 am, saving my life
@saxbend
@saxbend 7 жыл бұрын
I love the way you pronounce Hypotenuse. :)
@cheks_765
@cheks_765 3 ай бұрын
This exact question was on my quiz earlier today. If only the algorithm would have recommended it sooner :(
@atmsc4nd4l
@atmsc4nd4l 3 жыл бұрын
when i saw the thumbnail, trigo sub is the method that comes to my mind.
@eness26-h1g
@eness26-h1g 9 ай бұрын
thanks sir that was helpful
@gokharol
@gokharol 6 жыл бұрын
I came across this problem in a James Stewart and have spent a great deal of time trying to solve it but couldn't do it :-( I wanna thank you for sharing the solution. I guess I had to have an advanced vision to be able to think of this....unfortunately not this time
@kaustavchakraborty811
@kaustavchakraborty811 5 жыл бұрын
integrate 1/sqrt(1-x^4) between limits 0 to 1.
@jimyjofred3540
@jimyjofred3540 4 жыл бұрын
explicas tan bien que no hablo muy bien el ingles y te comprendo muchas gracias
@chorobatestopografia7689
@chorobatestopografia7689 6 ай бұрын
IMPRESIONATE
@joansgf7515
@joansgf7515 2 жыл бұрын
I got the same answer using x=sqrt(sin(theta)), nice!
@braedenrubin4234
@braedenrubin4234 2 жыл бұрын
This uses so many levels of mathematics it's incredible, I mean it's integration, u sub, trig sub, power reduction, trig identities AND fundamental trigonometry😂
@guardiadiego1137
@guardiadiego1137 2 жыл бұрын
yeah6 you learn them all in elementary sch6ool
@AniketBaniket
@AniketBaniket 2 жыл бұрын
@@guardiadiego1137 i doubt you were doing calc 1 in 8th grade
@investingpioneer
@investingpioneer 11 ай бұрын
Elementary School? You must be a late bloomer, though I feel a sense that you're bragging. Indeed, preschool is the time to get a head start on such matters.@@guardiadiego1137
@mariogabrielsalvatierrafra4500
@mariogabrielsalvatierrafra4500 8 жыл бұрын
good one, thanx for sharing it
@yesmanic
@yesmanic 2 жыл бұрын
How can I do this using riemann sum?
@sebastianfernandezmora5796
@sebastianfernandezmora5796 7 жыл бұрын
why you hold a mini death star?
@blackpenredpen
@blackpenredpen 7 жыл бұрын
Sebastián Fernández so u could leave a comment like this :)
@MC-mx1mt
@MC-mx1mt 5 жыл бұрын
@@blackpenredpen he purposely asked that question so that you could reply him that answer
@mhammedtomy545
@mhammedtomy545 4 жыл бұрын
You are wonderful thank you keep doing these amazing videos . Again thanks
@sarojkhanal7257
@sarojkhanal7257 4 жыл бұрын
Answer this pleasee. Isnt square root of (1-sin^2theta) modulus of costheta? Why did you write just costheta
@odobenusrosmarus6035
@odobenusrosmarus6035 4 жыл бұрын
i think its because cos^2theta is always positive, so we dont need the modulus
@bonbonpony
@bonbonpony 8 жыл бұрын
Why is the next video in this playlist private?
@blackpenredpen
@blackpenredpen 8 жыл бұрын
Bc it's private.
@bonbonpony
@bonbonpony 8 жыл бұрын
blackpenredpen So why is it listed on a public playlist? :P (Also tautology is not really an answer ¬.¬ )
@julioalexandre9
@julioalexandre9 7 жыл бұрын
Integral of ((x^4 + 1)^(3/2))/(x^2) ?
@jonathanmalagonnabor1762
@jonathanmalagonnabor1762 3 жыл бұрын
thanks a lot, you are the guy :^)
@przemysawkwiatkowski2674
@przemysawkwiatkowski2674 5 жыл бұрын
Why sqrt(cos^2)=cos ? Why not |cos| ?
@halden3014
@halden3014 5 жыл бұрын
it is. but with integrals we dont evaluate the absolute values because we only care about the answer.
@alexting827
@alexting827 5 жыл бұрын
It is, but in indefinite integrals we assume it to be |cos| to be positive. When doing definite integrals, you have to look at the bounds to determine how to drop the absolute value bars
@HieuLe-my2qm
@HieuLe-my2qm 2 жыл бұрын
Thanks a lot
@vincenciussufijanhadi1287
@vincenciussufijanhadi1287 Жыл бұрын
How if, integral (4 + x^-1)° 1/2 dx. x = 0 to x = 1. This is length of curve
@ayoubsbai6339
@ayoubsbai6339 5 жыл бұрын
2:29 is that a JoJo reference ?
@rosaangelicamarinez5689
@rosaangelicamarinez5689 5 жыл бұрын
thanks
@CeceMelchor
@CeceMelchor 6 жыл бұрын
Thanks!
@peacegaming3691
@peacegaming3691 4 жыл бұрын
Please solve 1/x sqrt (x)^4-1 answers
@kahnsinho
@kahnsinho 8 жыл бұрын
thx bro
@rhivanaashari3903
@rhivanaashari3903 5 жыл бұрын
Ily 3000
@peacegaming3691
@peacegaming3691 4 жыл бұрын
1/x sqrt (x)^4-1 answers
@tarotymagia22
@tarotymagia22 6 жыл бұрын
thaankkkkssss
@bhabatoshbarman4440
@bhabatoshbarman4440 4 жыл бұрын
anyone help integration of (1+X^4)dx
@void2509
@void2509 4 жыл бұрын
definitely not x + x^5/5
@yusupovjasur
@yusupovjasur 5 жыл бұрын
Genius!
@NoNameAtAll2
@NoNameAtAll2 8 жыл бұрын
why did you write sin^(-1)(u) rather than arcsin(u)?sin^(-1)(u) can be interpret as 1/sin(u)=cosec(u), which is wrong in this integral...
@227morgan3
@227morgan3 8 жыл бұрын
(sin(x))^-1=1/sin(x)=csc(x), but sin^-1(x) in that notation always refers to arcsin and NOT cosecant
@gr1nder07
@gr1nder07 8 жыл бұрын
nah man, in maths by the time you get to calculus it should be understood that "sin^-1" does not equal (!=) "1/sin" but is instead inverse sin. Arcsin isnt standard notation, just an adapted one that some people find easier
@227morgan3
@227morgan3 8 жыл бұрын
gr1nder07 You're saying the same thing I was. It is just a question of whether the ^-1 superscript is written between the sin and x (meaning arcsin/ sin inverse, plug in a ratio and get out an angle), versus putting the ^-1 after sin(x) (i.e. (sin(x))^-1) is saying take the whole thing sin(x) and raise it to the negative first power, which is equivalent to csc(x)
@blackpenredpen
@blackpenredpen 8 жыл бұрын
Yes, you two are both right. I think gr1nder07 were just trying to support and strengthen your very first statement. Especially I agree with " .. by the time you get to calculus it should be understood.." Thanks for watching btw! = )
@AlgyCuber
@AlgyCuber 6 жыл бұрын
what about arcsin^2(x)? it will be arcsin^-2(x)
@mmebled31sansnom26
@mmebled31sansnom26 5 жыл бұрын
xiéxié xiexie very lesson
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