Interference and Coincidence|CSIR NET JRF|GATE|Life Science|Genetics|

[@ChrististhereasonLecheKoza]

0.35 × 0.22 = 0.077 0.077 × 1000= 77 ☝️For those students who are confused in values

[@ummulbanin9845]

But when we calculate single cross over frequency we use the formula single + double/total ×100 but this time she didn't used that ???

[@ishakumari3617]

0.77×1000=770

[@perpetualearner1]

@@ummulbanin9845 It can be done with that formula as well but 100 will get canceled as we will multiply it both in denominator and numerator

[@anushkagupta4563]

@@perpetualearner1 yes bt thn the denominator will be 10 not thousand , and the answer will be different

[@golukumarthakur1349]

You gave the topic the out of world explanation you're the best teacher ever on you tube miss

[@NK18872]

COC = Observed number of double crossovers / Expected number of double crossovers ​Given: Expected double crossover frequency = 0.077* (0.77% chance that double crossover would occur) Total number of progeny = 1000 Observed number of double crossovers = 50 First, we calculate the expected number of double crossovers: Expected number of double crossovers=0.077×1000=77 Next, we use the observed number of double crossovers to calculate the coefficient of coincidence: COC = 50/ 77 COC= 0.649

[@LifeSciencesWithKumarP.]

15:55 par jab hum 0.35 multiply 0.22 karenge to answer value 0.077 aayegaa.

[@thokchomnaochaa9039]

You can make every steps in simple ways.....thank you...

[@shubhankarsahoo3376]

Well explained and I understand the whole topic with your good fluency 😄

[@drx.naveengujjar]

i thing At 8:57 total progeny (expected) should be 770 not 77 and coc should be 0.065 not 0.65,plz clear if i am wrong

[@kshitijshivne237]

Accurately speaking 0.36 is correct interference

[@priyalahorani1706]

Brilliantly explained... Thankyou mam

[@Riya-po3sk]

Love u sis u r too good sis😊😊😊😊hope ap meri school teacher hoti sis😊😊

[@Technologystarx]

Well Explained Mam....🌸

[@surbhivashishtha1830]

Mam formula for frequency you put it wrong No.of recombinant ÷total no of offspring × 100 Please explain

[@ajitsinghkrw7364]

Thnxs ma'am, of your simple explanation

[@dineshsitesh6633]

MAAM YOU ARE SO CUTE, YOUR LECTURE IS SO CUTE AND EASY TO UNDERSTAND..I LOVE YOU🥰

[@bikashkumarpanda8136]

Thank you so much mam ..now it is crystal clear to me..❤

[@ruchidubey8487]

Thank you so much Ma'am for this wonderful lecture.❤

[@zinsinag7497]

Well explained .It helped me a lot

[@ajithajayakumar1738]

Well explained, thank you so much ❤️

[@bilalyatoo3416]

Thanks mam ... more videos plz on the genetics ... unique way of laying an emphasis on the important stuff 👍👍

[@uzaidshaikh2195]

Thank you mam Exquisite lecture 💥

[@sonalisony350]

Thank u so much mam you solve my all problem

[@ripubisi4124]

Simple explain u thanks

[@dineshkumar-lp6yx]

U made it sooooooo easy 😊🤗

[@subhosmita98]

Mam frequency ka formula me × 100 bhi to ata hai . Wo kaise manage hua idhar

[@monikumari5303]

I must say you are gruu of genetics 🙏🏼🌺

[@medhashreegoswami13]

Best lecture on this topic ❤️

[@anushkagupta4563]

recombinantion frequency formula has 100 multipying in it bt ma'am uh haven't add it here why? in ur previous lecture the formula u used was no. of offspring/total no of offspring*100

[@sudeshna2164]

Bcz in that case we hv to calculate the gene distance..if we don't multiply with 100 then no % in ans & in such decimal number(0.012 / 0.03) gene distance can't be written..but in this vdo gene distance isn't required to calculate!so..

[@vishalrana7837]

So beautiful, intelligent, concept understanding looking like a wow ❤

[@padmalochanseth7932]

Well make out mam....👍👍👍

[@asinjitdas3113]

Thank you।।। please also explain qtl analysis

[@BansalBiologyAvantika]

Sure

[@ChrististhereasonLecheKoza]

Best explanation! ❤ New subscriber here

[@siddhantjain1699]

mam apart from how pretty u r i totally love the way u teach

[@najiabanu8791]

Thank you ❤️ ye mere semester exam me kaam aaenge 😅

[@kvrsvlogadventurenature4020]

Mere bhi aayega kal hai exam 😅

[@jaisharma8998]

Ma'am, but when we were solving frequency previously the formula was = no. Of recombinant /total no. Of progeny ×100 but here you are not using 100 in multiple why?

[@anshikapatel3347]

+++++

[@KomalSuryakamble]

Same question

[@mrutyunjaysahoo970]

😂😂😂😂lol

[@mrutyunjaysahoo970]

Thats a formula 😂😂😂😂

[@educationalfriends1506]

Happy teacher's day didi🥰🥰

[@BansalBiologyAvantika]

Thank you😊

[@manashmahanta4765]

Happy Teachers day my all time favorite mam ❤️❤️

[@BansalBiologyAvantika]

Thank you😊

[@manashmahanta4765]

@@BansalBiologyAvantika Most welcome mam❤️❤️❤️

[@aryanchugh682]

Di i guess 9:06 par answer 0.77 × 1000 = 770 ana chahiye

[@sangitalala9133]

right,i too found it.

[@ChrististhereasonLecheKoza]

0.35 × 0.22 = 0.077 0.077 × 1000= 77

[@down2root]

Ma'am be like mother's of genetics 👍🏻👍🏻

[@kalyanlohar476]

Thank you maam.... Thank you 🙂🙂👍💞

[@barshabibar4847]

App ki dress bahut achi lagi mujhe mam ji 😂❤😅

[@atanubera9851]

Well explained 👍

[@muhammadsalman3536]

Well Explained mam

[@tajokamra1411]

Happy Teacher's Day ma'am

[@BansalBiologyAvantika]

Thaank you😊

[@subha4682]

🔴🔴Expected DCO frequency=0.35×0.22=0.077

[@Barkha_Rain]

Please pin the previous video link you taught about the example. Please

[@barshabibar4847]

Mam last part me clear nahi dekhai diya mam

[@abhishekverma7205]

Plz tell me the scope of bsc horticulture

[@pankajshayari8369]

Mam please make video how to read ncert ❤️❤️❤️❤️❤️

[@BansalBiologyAvantika]

Sure

[@sujatapradhan7149]

Well explained.

[@sujatapradhan7149]

Mam why didn't you multiply 100 when you calculate single cross over???

[@sujatapradhan7149]

If I will divide the map distance by 100 of both the single cross over and multiply with total progeny to calculate expected double crossover is it correct process or not???

[@vv.ashrita7286]

Doublecross excepted frequency is wrong. It should 0.077

[@T-Rexxxxx]

Really helpful

[@amse__music8423]

ma'am I'm sorry but 0.077 hona chahiye not 0.77. sorry ma'am, just one small calculation mistake

[@mohsinrashid8979]

Mam thank you so much Mam i m facing problems in botany genetics , can you you help me in solving those problems.... Thanks mam

[@rounakmukherjee7915]

Mam i have a doubt...where should I post?

[@raviprattipati7990]

Mam also explain English language Other wise use both languages same time

[@Ajaykumar47205]

0.77*1000 = 77 kaise aaya 🧐🧐 ..770 hona chahie n

[@animeshhb]

Maam I've a confusion. Why we didn't multipied the single crossover frequency with 100 here. Pls reply

[@rushikeshmane208]

She didn't put ×100 in formula. Let me simplify, formula of Recombination frequency use as it is but formula get divisible by 100 when u find frequency of crossover. Reason: We use the unit centimorgan (cM) to measure distance between genes based on offspring phenotype frequency. A centimorgan = 100 times the frequency of crossovers in the offspring. In this example, the frequency of crossovers is 10/100 and the distance between the genes is 100 * 1/10 = 10 centimorgans.

[@rachanasingh6626]

Can you simplify this explanation

[@UmarClub]

Mam, zindabad 🥰🤩

[@shashankmanitiwari8532]

Thank you mam

[@dsrtutorial1924]

nice

[@joyshreenath2585]

Thankyou maam💕

[@jabirrajin4246]

Interference kya (-) a sakti hey..

[@takeaartbreak]

Yes...in bacteriophages (lower organisms )

[@bipssong3371]

❤️❤️❤️❤️

[@edu_bio]

Got it

[@Umeshsharma-rn3id]

Tnq mam

[@SARITAYADAV-l3q]

Thnx mam ❤

[@rupamahale4889]

I think you did wrong calculation...and comes as 0.99 interference

[@tanu6464]

🥰🥰🥰🥰🥰🥰🥰🥰🥰🥰

[@ishakumari3617]

0.77×1000=770